Chapter 6: Problem 7
Show that a sequence in a metric space has at most one limit.
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 6: Problem 7
Show that a sequence in a metric space has at most one limit.
These are the key concepts you need to understand to accurately answer the question.
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A linear map \(T: V \rightarrow W\) from a normed vector space \(V\) to a normed vector space \(W\) is called bounded below if there exists \(c \in(0, \infty)\) such that \(\|f\| \leq c\|T f\|\) for all \(f \in V\). Suppose \(T: V \rightarrow W\) is a bounded linear map from a Banach space \(V\) to a Banach space \(W\). Prove that \(T\) is bounded below if and only if \(T\) is injective and the range of \(T\) is a closed subspace of \(W\).
Prove that every finite subset of a metric space is closed.
Show that the map \(f \mapsto\|f\|\) from a normed vector space \(V\) to \(\mathbf{F}\) is continuous (where the norm on \(\mathbf{F}\) is the usual absolute value).
Suppose \((X, d)\) is a complete metric space and \(G_{1}, G_{2}, \ldots\) is a sequence of dense open subsets of \(X\). Prove that \(\bigcap_{k=1}^{\infty} G_{k}\) is a dense subset of \(X\).
Prove that there does not exist an infinite-dimensional Banach space with a countable basis. [This exercise implies, for example, that there is not a norm that makes the vector space of polynomials with coefficients in \(\mathbf{F}\) into a Banach space.]
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