Chapter 4: Problem 28
The line \(3 y=7 x-2\) has an intercept of \(-2\) on the \(y\)-axis.
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Chapter 4: Problem 28
The line \(3 y=7 x-2\) has an intercept of \(-2\) on the \(y\)-axis.
These are the key concepts you need to understand to accurately answer the question.
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The curves \(y=x^{2}, \quad y=x(2-x)\) intersect at: (a) \((0,0),(1,1)\) (b) \((2,4)\) (c) \((0,0),(2,4)\) (d) \((0,0),(-1,1)\) (e) \((1,1)\).
Find the equation of the line through \(\mathrm{A}(5,2)\) which is perpendicular to the the line \(y=3 x-5\). Hence find the coordinates of the foot of the perpendicular from A to the line.
Write down the equation of the line which goes through the point \((7,3)\) and which is inclined at \(45^{\circ}\) to the positive direction of the \(x\)-axis. Find the area enclosed by this line and the coordinate axes.
\(\mathrm{A}, \mathrm{B}\) and \(\mathrm{C}\) are three points where: (a) \(\mathrm{C}\) is equidistant from \(\mathrm{A}\) and \(\mathrm{B}\). (b) The coordinates of \(\mathrm{A}, \mathrm{B}\) and \(\mathrm{C}\) are \((1,2),(3,6)\) and \((2,4)\).
Show that the triangle whose vertices are \((1,1),(3,2),(2,-1)\) is isosceles.
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