Chapter 2: Problem 19
\(3 \log x+1=\log 10 x^{3}\) is an equation.
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Chapter 2: Problem 19
\(3 \log x+1=\log 10 x^{3}\) is an equation.
These are the key concepts you need to understand to accurately answer the question.
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\(\frac{1}{2} \log 16-1:\) (a) can be expressed as a single logarithm, (b) has an exact decimal value, (c) is equal to log 7 .
If \(\log _{x} y=2\) : (a) \(x=2 y\) (b) \(x=y^{2}\) (c) \(x^{2}=y\) (d) \(y=2 x\) (e) \(y=\sqrt{x}\).
Express \(\log _{9} x y\) in terms of \(\log _{3} x\) and \(\log _{3} y\). Without using tables, solve for \(x\) and \(y\) the simultaneous equations $$ \begin{gathered} \log _{9} x y=\frac{5}{2} \\ \log _{3} x \log _{3} y=-6 \end{gathered} $$ expressing your answers as simply as possible.
\(\frac{p^{-\frac{1}{2}} \times p^{\frac{3}{4}}}{p^{-\frac{1}{4}}}\) simplifies to: (a) 1 (b) \(p^{-\frac{1}{2}}\) (c) \(p^{\frac{3}{4}}\) (d) \(p\) (e) \(p^{\frac{1}{2}}\).
Show that \(\log _{16}(x y)=\frac{1}{2} \log _{4} x+\frac{1}{2} \log _{4} y .\) Hence, or otherwise, solve the simultaneous equations $$ \begin{aligned} &\log _{16}(x y)=3 \frac{1}{2} \\ &\frac{\left(\log _{4} x\right)}{\left(\log _{4} y\right)}=-8 \end{aligned} $$
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