Chapter 13: Problem 10
If \(a=3-\mathrm{i}\) and \(b=1+2 \mathrm{i}\), find the moduli of: (a) \(2 a+3 b\) (b) \(\frac{a}{2 b}\)
Short Answer
Expert verified
The moduli are \(\sqrt{97}\) and \(\frac{\sqrt{2}}{2}\).
Step by step solution
01
Calculate the expression for 2a + 3b
First, we need to compute the value of the expression \(2a + 3b\). Given that \(a = 3 - i\) and \(b = 1 + 2i\), let's calculate: \(2a = 2(3 - i) = 6 - 2i\)\(3b = 3(1 + 2i) = 3 + 6i\)Now, add these two results together: \(2a + 3b = (6 - 2i) + (3 + 6i) = 9 + 4i\)
02
Find the modulus of 2a + 3b
To find the modulus of the complex number \(9 + 4i\), use the formula \(\sqrt{a^2 + b^2}\):\[\lVert 9 + 4i \rVert = \sqrt{9^2 + 4^2} = \sqrt{81 + 16} = \sqrt{97}\]
03
Calculate the expression for \(\frac{a}{2b}\)
Next, find \(\frac{a}{2b}\). First compute \(2b\):\(2b = 2(1 + 2i) = 2 + 4i\)Now, divide \(a\) by \(2b\):\(\frac{a}{2b} = \frac{3 - i}{2 + 4i}\)To simplify, multiply the numerator and the denominator by the conjugate of the denominator: \(\frac{3 - i}{2 + 4i} \times \frac{2 - 4i}{2 - 4i} = \frac{(3 - i)(2 - 4i)}{(2 + 4i)(2 - 4i)} = \frac{6 - 12i - 2i + 4i^2}{4 - 16i^2} = \frac{6 - 14i - 4}{4 + 16} = \frac{2 - 14i}{20} = \frac{1 - 7i}{10}\)
04
Find the modulus of \(\frac{a}{2b}\)
To find the modulus of the complex number \(\frac{1 - 7i}{10}\), use the same modulus formula: \[\lVert \frac{1 - 7i}{10} \rVert = \frac{\sqrt{1^2 + (-7)^2}}{10} = \frac{\sqrt{1 + 49}}{10} = \frac{\sqrt{50}}{10} = \frac{5\sqrt{2}}{10} = \frac{\sqrt{2}}{2}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Modulus of Complex Numbers
The modulus of a complex number gives its distance from the origin on the complex plane. It's like finding the length of the hypotenuse in a right-angled triangle. If your complex number is in the form of \(a + bi\), the modulus is calculated using the formula: \(\lVert a + bi \rVert = \sqrt{a^2 + b^2}\). This formula comes from the Pythagorean theorem.
In the given problem, we first find the modulus of \(9 + 4i\). Plugging in the values, we get:
In the given problem, we first find the modulus of \(9 + 4i\). Plugging in the values, we get:
- \(a = 9\)
- \(b = 4\)
- \(a = 1/10\)
- \(b = -7/10\)
Complex Number Operations
Complex numbers involve operations similar to real numbers with some additional rules for the imaginary part. Here are the key operations:
- Addition: Combine like terms. For example, \((3 - i) + (1 + 2i) = 4 + i\).
- Subtraction: Distribute the negative sign and combine like terms. For example, \( (3 - i) - (1 + 2i) = 2 - 3i\).
- Multiplication: Use the distributive property and remember that \(i^2 = -1\). For example, \((3 - i)(1 + 2i) = 3 + 6i - i - 2i^2\) which simplifies to \(5 + 5i\).
- Division: Multiply the numerator and the denominator by the conjugate of the denominator. For example, to simplify \(\frac{3 - i}{2 + 4i}\), multiply by the conjugate of the denominator: \(\frac{(3 - i)(2 - 4i)}{(2 + 4i)(2 - 4i)}\). The denominator then becomes a real number.
Mathematical Problem-Solving
Mathematical problem-solving often involves breaking down a problem into smaller, more manageable parts. Here’s a step-by-step approach:
1. Calculate expressions (like \(2a + 3b\) and \( \frac{a}{2b} \)).
2. Simplify the expressions using appropriate operations.
3. Find the modulus of the resulting complex numbers. Breaking problems into these steps simplifies complex calculations and enhances problem-solving efficiency.
- Understand the problem: Carefully read the problem statement. Identify the given information and what needs to be found.
- Devise a plan: Consider different strategies to solve the problem. This could involve algebraic manipulations, geometric interpretations, or other mathematical techniques.
- Execute the plan: Carry out the steps you have planned methodically. Make sure to work step by step to avoid errors.
- Review your work: Once you have an answer, review your calculations and reasoning. Verify if your solution makes sense in the context of the problem.
1. Calculate expressions (like \(2a + 3b\) and \( \frac{a}{2b} \)).
2. Simplify the expressions using appropriate operations.
3. Find the modulus of the resulting complex numbers. Breaking problems into these steps simplifies complex calculations and enhances problem-solving efficiency.