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Chapter 4: Problem 3

Reduce the given fraction to an equivalent fraction in lowest terms. $$\frac{9}{15}$$

Short Answer

Expert verified
Question: Reduce the fraction 9/15 to its lowest terms. Answer: The fraction 9/15 reduced to its lowest terms is 3/5.

Step by step solution

01

Find the GCD of the numerator and denominator

In the given fraction, the numerator and denominator are 9 and 15 respectively. The factors of 9 are 1, 3, and 9, while the factors of 15 are 1, 3, 5, and 15. The common factors are 1 and 3, and the greatest of these is 3. Therefore, the GCD of 9 and 15 is 3.
02

Divide the numerator and denominator by the GCD

Divide the numerator 9 by the GCD (3): \(\frac{9}{3} = 3\). Divide the denominator 15 by the GCD (3): \(\frac{15}{3} = 5\).
03

Write the equivalent fraction in lowest terms

After dividing the numerator and denominator by their GCD, we get the equivalent fraction in lowest terms: $$\frac{3}{5}$$.

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Most popular questions from this chapter

A student spends \(\frac{1}{3}\) of a typical day sleeping, \(\frac{1}{6}\) of the day in classes, and \(\frac{1}{8}\) of the day watching TV. a. If \(x\) represents the fraction of the rest of the day available for study, write an equation describing the situation. b. Solve the equation for \(x .\)
Evaluate each expression. a. \(2 x-4(x-3),\) where \(x=\frac{1}{2}\) b. \(a(a-2)+a(3 a-2),\) where \(a=\frac{1}{3}\) c. \(2 x+6(x+2),\) where \(x=\frac{3}{4}\) d. \(6 x y-y^{2},\) where \(x=\frac{5}{16}\) and \(y=\frac{1}{8}\) e. \(4 x^{3}+x^{2},\) where \(x=\frac{1}{2}\)
An Ivy League college accepts 5 students for every 100 that apply. What fraction of applicants is accepted? Write your result in lowest terms.
Perform the indicated operation. Write all results in lowest terms. $$\frac{1}{6}+\frac{1}{2}$$
Perform the indicated operation. Write all results in lowest terms. $$\frac{4}{5}-\frac{1}{5}$$
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