Chapter 9: Problem 36
If the sum of \(n\) terms of an AP is \(2 n^{2}+5 n\), then show that its \(n t h\) term is \(4 n+3\).
Short Answer
Expert verified
The nth term of the given AP is \(a_n = 4n + 3\).
Step by step solution
01
Recall AP Definitions and Formulas
Recall the basic definition of an AP along with the sum formula:
1. The general term of an AP is given by \(a_n = a_1 + (n-1)d\),
where \(a_n\) is the nth term, \(a_1\) is the first term, \(n\) is the number of terms and \(d\) is the common difference between terms.
2. The sum of n terms of an AP is given by: \(S_n=\frac{n}{2}(2a_1+(n-1)d)\).
02
Substitute Given Sum in the AP Sum Formula
In this exercise, we are given the sum of n terms of the AP as \(S_n = 2n^2 + 5n\). We will substitute this value into the AP sum formula.
So, \(2n^2 + 5n = \frac{n}{2}(2a_1 + (n-1)d)\).
03
Simplify Equation and Solve
Multiply both sides by 2 to eliminate fractions:
\(4n^2 + 10n = n(2a_1 + (n-1)d)\).
Now we can simplify and distribute n on the right side:
\(4n^2 + 10n = 2na_1 + n^2d - nd\).
04
Compare Coefficients
In order to find the formula for the nth term, we need to compare the coefficients of the powers of n in the equation:
For \(n^2\) term: \(4 = d\)
For \(n\) term: \(10 = 2a_1 - d\)
Substitute the \(d\) value obtained from the \(n^2\) term equation:
\(10 = 2a_1 - 4\)
Now, solve for \(a_1\):
\(2a_1 = 14\)
\(a_1 = 7\)
Thus, we have the values of \(a_1\) and \(d\) as \(7\) and \(4\) respectively.
05
Find the nth term Formula
Now, substitute the values of \(a_1\) and \(d\) in the general term formula,
\(a_n = a_1 + (n-1)d\)
\(a_n = 7 + (n-1)4\)
Simplify to find the nth term formula:
\(a_n = 7 + 4n - 4\)
\(a_n = 4n + 3\)
Therefore, the nth term of this AP is indeed given by the formula \(4n + 3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
AP nth term formula
In an Arithmetic Progression (AP), each term increases by a constant amount, called the common difference. The formula to find the nth term of an AP (denoted as \( a_n \)) is essential for determining specific terms in a sequence. It is given by:\[ a_n = a_1 + (n-1) \cdot d \]where:
- \( a_n \) is the nth term we want to find.
- \( a_1 \) is the first term of the sequence.
- \( n \) is the term number.
- \( d \) is the common difference between consecutive terms.
Sum of n terms in AP
The sum of the first \( n \) terms in an AP is one of the key formulas in arithmetic sequences. This sum provides us with the total of adding up the first \( n \) numbers in the series. The formula is represented as:\[ S_n = \frac{n}{2} (2a_1 + (n-1) \cdot d) \]Here, \( S_n \) is the sum of the first \( n \) terms, and the other variables \( a_1 \), \( n \), and \( d \) are as previously defined:
- \( a_1 \) is the first term of the sequence.
- \( n \) is the total number of terms to be added.
- \( d \) is the common difference.
Common difference in AP
The common difference in an Arithmetic Progression (AP) is a crucial component that dictates how the sequence's terms increase. It is defined as the difference between any two consecutive terms in the sequence. Mathematically, if you have a sequence with terms \( a_1, a_2, a_3, \ldots \), the common difference \( d \) can be calculated by:\[ d = a_2 - a_1 \]This difference remains constant throughout the sequence. In the context of the problem solved, after equating and comparing the sum of \( n \) terms to the sum formula, the common difference \( d \) was determined to be 4:
- By matching the coefficient of \( n^2 \) in both expressions, it was established that \( d = 4 \).