Chapter 7: Problem 17
Show that the polynomial \(P(x)=x^{5}+x^{3}+2 x+1\) cannot have a positive real root.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 7: Problem 17
Show that the polynomial \(P(x)=x^{5}+x^{3}+2 x+1\) cannot have a positive real root.
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
$$ \sqrt{3^{x}} \cdot \sqrt{5^{x}}=225 $$
$$ |x|^{2}-3|x|+2=0 $$
$$ \left(9^{3-5 x}\right)\left(7^{5 x-3}\right)=1 $$
$$ \sqrt{x+1}=8-\sqrt{3 x+1} $$
$$ 5^{|4 x-6|}=25^{3 x-4} $$
What do you think about this solution?
We value your feedback to improve our textbook solutions.