Chapter 2: Problem 35
$$ \lim _{x \rightarrow 0} \frac{e^{x}}{x^{2}}\\{\text { Ans. } \infty\\} $$
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Chapter 2: Problem 35
$$ \lim _{x \rightarrow 0} \frac{e^{x}}{x^{2}}\\{\text { Ans. } \infty\\} $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \lim _{x \rightarrow \infty} x^{\frac{3}{2}}\left(\sqrt{x^{3}+1}-\sqrt{x^{3}-1}\right) \text { \\{Ans. 1\\} } $$
$$ \lim _{x \rightarrow 0} e^{\operatorname{sgn} x}\left\\{\text { Ans. } e, \frac{1}{e}\right\\} $$
$$ \left.\lim _{x \rightarrow 3} \frac{\sqrt{x^{2}-2 x+6}-\sqrt{x^{2}+2 x-6}}{x^{2}-4 x+3} \text { \\{Ans. }-\frac{1}{3}\right\\} $$
\begin{aligned} &\text { Given }\\\ &\begin{aligned} f(x) &=x, \quad x<0 \\ &=1, \quad x=0 \\ &=x^{2}, \quad x>0 \\ \text { Does } & \lim _{x \rightarrow 0} f(x) \text { exist? \\{ns. Yes\\} } \end{aligned} \end{aligned}
$$ \lim _{x \rightarrow \frac{\pi}{2}} \frac{1}{\ln (\sin x)}\\{\text { Ans. }-\infty\\} $$
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