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$$ \lim _{x \rightarrow \infty}(\operatorname{sgn} x)^{x} \quad\\{\text { Ans. } 1\\} $$

Short Answer

Expert verified
The limit of the given function as x approaches infinity is 1.

Step by step solution

01

Identify the signum function

The signum function, often denoted as sgn(x), extracts the sign of a real number. It gives -1 for negative numbers, 0 for zero, and 1 for positive numbers.
02

Identify the limit

In this particular exercise, the limit \( \lim_{x \rightarrow \infty}\) is described. This means that x, in the function, is tending towards infinity.
03

Evaluate the limit

As x approaches infinity, sgn(x) can be replaced with 1 because for all positive real numbers, the output of signum function is 1. The function then becomes \( \lim_{x \rightarrow \infty} 1^x \). Now, the limit of a constant raised to the power of x when x approaches infinity is the constant value itself, which in this case is 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Signum Function
The signum function, often represented as \( \text{sgn}(x) \), plays a key role in understanding how we interpret the sign of numbers. It tells us whether a number is positive, negative, or zero.
For any given real number \( x \):
  • If \( x > 0 \), \( \text{sgn}(x) = 1 \)
  • If \( x = 0 \), \( \text{sgn}(x) = 0 \)
  • If \( x < 0 \), \( \text{sgn}(x) = -1 \)
In our exercise, as \( x \) approaches infinity, which means \( x \) is getting larger indefinitely, the element of \( x \) being positive is central. When \( x \) becomes very large and positive, \( \text{sgn}(x) \) will consistently equal 1. Thus, the signum function simplifies complex scenarios by giving a straightforward indicator of the sign of a number.
Infinite Limits
An infinite limit is a concept in calculus where the variable within the limit approaches either positive infinity \( \infty \) or negative infinity \( -\infty \). This describes the behavior of function values as one moves further and further along the number line without bound.
In mathematical notation, \( \lim_{x \rightarrow \infty} f(x) \) describes the value that \( f(x) \) approaches as \( x \) becomes extremely large.
This is crucial because it helps us to determine the behavior of functions over extensive ranges:
  • If \( \lim_{x \rightarrow \infty} f(x) = L \), where \( L \) is a constant, it tells us that \( f(x) \) stabilizes or approaches a horizontal asymptote at \( y = L \).
  • If \( \lim_{x \rightarrow \infty} f(x) = \pm \infty \), it indicates the function grows without bound.
In our exercise, \( \lim_{x \rightarrow \infty} (\text{sgn}(x))^x \) involves \( \text{sgn}(x) \) becoming 1, and thus the expression behaves like \( 1^x \) which equals 1, showing stability.
Limit Evaluation Techniques
Evaluating limits involves understanding the behavior of expressions as variables approach a certain value, potentially resulting in simpler expressions. The most common techniques to evaluate limits include:
  • Substitution: Directly replace the variable with a given value, if no indeterminate form arises.
  • Factoring: Break down complex expressions to cancel terms and simplify the limit evaluation.
  • Hopital's Rule: Applied when encountering indeterminate forms like \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \).
In our example, the limit \( \lim_{x\rightarrow\infty}(\text{sgn}(x))^x \), is simplified by recognizing that for \( x \rightarrow \infty \):
  • The \( \text{sgn}(x) \) becomes 1.
  • Reducing the complexity of the expression to \( 1^x \).
  • Since any number to the power of \( x \) remains the same constant when \( x \) is infinity, the limit remains \( 1 \).
Hence, proper identification of terms and their behavior leads to an effective and concise solution of the problem.

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