Chapter 13: Problem 229
Prove that \(\sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} \leq \frac{1}{8}\).
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Chapter 13: Problem 229
Prove that \(\sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} \leq \frac{1}{8}\).
These are the key concepts you need to understand to accurately answer the question.
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Solve the triangle, given i. \(\quad a=\sqrt{3}, b=\sqrt{2}\) and \(c=\frac{\sqrt{6}+\sqrt{2}}{2}\).\ ii. \(\quad b=\sqrt{3}, c=1\) and \(A=30^{\circ} .\)\ iii. \(a=5, b=7\) and \(A=60^{\circ}\). iv. \(a=1, c=2\) and \(A=30^{\circ}\). v. \(\quad a=2, c=\sqrt{3}+1\) and \(A=45^{\circ}\).= vi. \(a=\sqrt{3}, b=\sqrt{2}\) and \(A=60^{\circ} .\) vii. \(a=4, b=5\) and \(A=120^{\circ}\). ix. \(\quad a=2, B=60^{\circ}\) and \(C=45^{\circ} .\) x. \(A=45^{\circ}, B=60^{\circ}\) and \(C=75^{\circ} .\)
\(\frac{a \sin (B-C)}{b^{2}-c^{2}}=\frac{b \sin (C-A)}{c^{2}-a^{2}}=\frac{c \sin (A-B)}{a^{2}-b^{2}} .\)
\(a \sin (B-C)+b \sin (C-A)+c \sin (A-B)=0 .\)
\(a \sin \frac{A}{2} \sin \frac{B-C}{2}+b \sin \frac{B}{2} \sin \frac{C-A}{2}+c \sin \frac{C}{2} \sin \frac{A-B}{2}=0 .\)
The sides of a triangle are three consecutive natural numbers and it's largest angle is twice the smallest one. Determine the sides of the triangle.
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