Chapter 13: Problem 12
\(a^{2}+b^{2}+c^{2}=2(b c \cos A+c a \cos B+a b \cos C)\)
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Chapter 13: Problem 12
\(a^{2}+b^{2}+c^{2}=2(b c \cos A+c a \cos B+a b \cos C)\)
These are the key concepts you need to understand to accurately answer the question.
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In any triangle, if \(\tan \frac{A}{2}=\frac{5}{6}\) and \(\tan \frac{B}{2}=\frac{20}{37}\), find \(\tan \frac{C}{2}\) and prove that in this triangle \(a+c=2 b\).
\(a(b \cos C-c \cos B)=b^{2}-c^{2}\)
\(\frac{1+\cos (A-B) \cos C}{1+\cos (A-C) \cos B}=\frac{a^{2}+b^{2}}{a^{2}+c^{2}}\).
If \((a+b+c)(b+c-a)=k b c\), then prove that \(k \in(0,4)\).
If \(p_{1}, p_{2}, p_{3}\) are altitudes of a triangle \(A B C\) from the vertices \(A, B, C\) and \(\Delta\) the area of the triangle, then prove that \(p_{1}^{-1}+p_{2}^{-1}-p_{3}^{-1}=\frac{s-c}{\Delta}\).
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