Chapter 12: Problem 268
$$ \sin ^{-1} x \geq-2 $$
Short Answer
Expert verified
The solution to the inequality \( \sin^{-1} x \geq -2 \) is \( -1 \leq x \leq 1 \). This implies that the inequality holds for all real numbers x in the domain of the arcsine function.
Step by step solution
01
Understand the function
The sine inverse function, denoted as \( \sin^{-1} x \) or arcsin(x), is the inverse of the sine function. It outputs the angle whose sine is x, and it exists only for x between -1 and 1. The output of the arc sine function is always in the interval \( [-Ï€/2, +Ï€/2] \).
02
Analyze the inequality
The inequality given is \( \sin^{-1} x \geq -2 \). However, keep in mind that the range of the arcsine function is \( [-Ï€/2, +Ï€/2] \). Since -2 is in this range and any value of x in the domain would result in an arcsin(x) within this range, the inequality holds for all x in the domain of arcsin.
03
State the solution
This means the solution set for the inequality \( \sin^{-1} x \geq -2 \) is the entire domain of the \( \sin^{-1} x \) function, which is \( -1 \leq x \leq 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Arcsin Function
The arcsin function, often written as \( \sin^{-1} x \) or \( \text{arcsin}(x) \), is a fundamental concept in mathematics, especially when dealing with inverse trigonometric functions. The essence of the arcsin function is to find the angle whose sine value equals a given number \( x \). This is an inverse operation of the standard sine function. It specifically applies to situations where you know the sine value (an opposite/hypotenuse ratio in a right triangle) and you need the corresponding angle.
There are some important features of the arcsin function:
There are some important features of the arcsin function:
- It is defined only for \( x \) values between \(-1\) and \(1\). This is because the range of the sine function is between \(-1\) and \(1\), so these are the only possible outputs.
- The arcsin function has an output, or range of \( [-\pi/2, \pi/2] \). This means any angle it returns will lie within these boundaries. As a result, arcsin can be thought of as mapping real numbers from the interval \([-1, 1]\) to angles in radians from \([-\pi/2, \pi/2]\).
Sine Inverse Inequality
The sine inverse inequality, like \( \sin^{-1} x \geq -2 \), means we are examining how the output of the arcsin function compares to a specific number, in this case, \(-2\). Understanding this requires recalling the range of the arcsin function, which is \([-\pi/2, \pi/2]\) or approximately \([-1.57, 1.57]\) in decimal form.
Since \(-2\) is less than \(-\pi/2 \approx -1.57\), this inequality holds true for all \( x \) within the domain of the arcsin function, specifically \(-1 \leq x \leq 1\). This means if you choose any value of \( x \) in this domain, the resulting angle from \( \sin^{-1} x \) will always be greater than \(-2\).
Therefore, checking inequalities involving arcsin simply requires us to compare the range of the function to the value in question. Here, since \(-2\) is not within the arc sine's range boundary, the inequality comfortably holds for the full domain without further restriction.
Since \(-2\) is less than \(-\pi/2 \approx -1.57\), this inequality holds true for all \( x \) within the domain of the arcsin function, specifically \(-1 \leq x \leq 1\). This means if you choose any value of \( x \) in this domain, the resulting angle from \( \sin^{-1} x \) will always be greater than \(-2\).
Therefore, checking inequalities involving arcsin simply requires us to compare the range of the function to the value in question. Here, since \(-2\) is not within the arc sine's range boundary, the inequality comfortably holds for the full domain without further restriction.
Function Domain and Range
In mathematics, understanding a function's domain and range is crucial. For the arcsin function, this knowledge helps determine where the function exists and what value outputs it can provide. The domain of a function refers to all the possible inputs for which the function is defined.
For the arcsin function, the domain is \([-1, 1]\). This means the arcsin function only accepts input values within this interval, reflecting the allowable range of the sine function outputs. Any input outside this interval would not have a corresponding output angle.
The range, on the other hand, is the set of possible outputs, which for \( \sin^{-1} x \) is \([-\pi/2, \pi/2]\). It implies that results from \( \sin^{-1} x \) will always be angles between \(-\pi/2\) and \(\pi/2\) radians.
For the arcsin function, the domain is \([-1, 1]\). This means the arcsin function only accepts input values within this interval, reflecting the allowable range of the sine function outputs. Any input outside this interval would not have a corresponding output angle.
The range, on the other hand, is the set of possible outputs, which for \( \sin^{-1} x \) is \([-\pi/2, \pi/2]\). It implies that results from \( \sin^{-1} x \) will always be angles between \(-\pi/2\) and \(\pi/2\) radians.
- Domain of \( \sin^{-1} x \): \(-1 \leq x \leq 1\)
- Range of \( \sin^{-1} x \): \(-\pi/2 \leq \sin^{-1} x \leq \pi/2\)