Chapter 12: Problem 196
$$ \tan ^{-1}(x+1)+\tan ^{-1}(x-1)=\tan ^{-1} \frac{8}{31} $$
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Chapter 12: Problem 196
$$ \tan ^{-1}(x+1)+\tan ^{-1}(x-1)=\tan ^{-1} \frac{8}{31} $$
These are the key concepts you need to understand to accurately answer the question.
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\(\tan ^{3} x+\tan ^{2} x-3 \tan x=3\)
\(\sin x+\sin 2 x+\sin 3 x=0\)
\(2 \cos ^{2} x+\sin x=2\)
\(\sin 2 x+\cos 2 x=\sin x+\cos x\)
\(2 \sin ^{3} x-\cos 2 x-\sin x=0\)
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