Chapter 11: Problem 75
$$ \frac{\sin 5 A-\sin 3 A}{\cos 3 A+\cos 5 A}=\tan A $$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 11: Problem 75
$$ \frac{\sin 5 A-\sin 3 A}{\cos 3 A+\cos 5 A}=\tan A $$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
$$ \cos \left(45^{\circ}-A\right) \cos \left(45^{\circ}-B\right)-\sin \left(45^{\circ}-A\right) \sin \left(45^{\circ}-B\right)=\sin (A+B) $$
$$ \sin \frac{\pi}{10}+\sin \frac{13 \pi}{10}=-\frac{1}{2} $$
$$ \text { If } x=y \cos \frac{2 \pi}{3}=z \cos \frac{4 \pi}{3}, \text { then show that } x y+y z+z x=0 $$
$$ \frac{\cos 2 A \cos 3 A-\cos 2 A \cos 7 A+\cos A \cos 10 A}{\sin 4 A \sin 3 A-\sin 2 A \sin 5 A+\sin 4 A \sin 7 A}=\cot 6 A \cot 5 A $$
$$ (1+\cot A-\operatorname{cosec} A)(1+\tan A+\sec A)=2 $$
What do you think about this solution?
We value your feedback to improve our textbook solutions.