Chapter 11: Problem 195
$$ \text { If } A+B=45^{\circ}, \text { prove that }(\cot A-1)(\cot B-1)=2 $$
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Chapter 11: Problem 195
$$ \text { If } A+B=45^{\circ}, \text { prove that }(\cot A-1)(\cot B-1)=2 $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \frac{1+\tan ^{2} A}{1+\cot ^{2} A}=\frac{\sin ^{2} A}{\cos ^{2} A} $$
$$ \tan \theta \sin \left(\frac{\pi}{2}+\theta\right) \cos \left(\frac{\pi}{2}-\theta\right)=\sin ^{2} \theta $$
$$ (\sin 3 A+\sin A) \sin A+(\cos 3 A-\cos A) \cos A=0 $$
$$ (1+\cot A-\operatorname{cosec} A)(1+\tan A+\sec A)=2 $$
$$ (\sin A+\operatorname{cosec} A)^{2}+(\cos A+\sec A)^{2}=\tan ^{2} A+\cot ^{2} A+7 $$
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