Chapter 11: Problem 130
$$ \operatorname{cosec} 2 A+\cot 2 A=\cot A $$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 11: Problem 130
$$ \operatorname{cosec} 2 A+\cot 2 A=\cot A $$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
$$ \sin \left(45^{\circ}+A\right) \sin \left(45^{\circ}-A\right)=\frac{1}{2} \cos 2 A $$
$$ \frac{\cos 2 B-\cos 2 A}{\sin 2 B+\sin 2 A}=\tan (A-B) $$
$$ \text { Find the value of } \sin 10^{\circ}+\sin 20^{\circ}+\sin 30^{\circ}+\cdots \cdots+\sin 360^{\circ} $$
$$ \text { If } \sec x=p+\frac{1}{4 p}, \text { show that } \sec x+\tan x=2 p \text { or } \frac{1}{2 p} \text { . } $$
$$ \frac{\sin A-\sin 5 A+\sin 9 A-\sin 13 A}{\cos A-\cos 5 A-\cos 9 A+\cos 13 A}=\cot 4 A $$
What do you think about this solution?
We value your feedback to improve our textbook solutions.