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The number of persons coming through a blood bank until the first person with type \(A\) blood is found is a random variable \(Y\) with a geometric distribution. If \(p\) denotes the probability that any one randomly selected person will possess type \(A\) blood, then \(E(Y)=1 / p\) and \(V(Y)=(1-p) / p^{2}\) a. Find a function of \(Y\) that is an unbiased estimator of \(V(Y)\). b. Suggest how to form a 2 -standard-error bound on the error of estimation when \(Y\) is used to estimate \(1 / p\).

Short Answer

Expert verified
An unbiased estimator of \( V(Y) \) is \( Y(Y-1) \). Use \( 2 \times \sqrt{\frac{Y-1}{Y^2}} \) for 2-standard-error bounds.

Step by step solution

01

Define the Geometric Distribution Expectation and Variance

We are given a random variable \( Y \) with a geometric distribution representing the number of trials until the first success (person with type \( A \) blood). The expectation \( E(Y) = \frac{1}{p} \) and variance \( V(Y) = \frac{1-p}{p^2} \), where \( p \) is the success probability, are parameters to guide the solution.
02

Identify an Unbiased Estimator for Variance

We need an unbiased estimator for \( V(Y) = \frac{1-p}{p^2} \). We already know \( E(Y) = \frac{1}{p} \). Using properties of the geometric distribution, the sample variance \( S^2 \) for very large \( n \) of the geometric random variable \( Y \) is an unbiased estimator of its population variance. Thus, \( Y(Y-1) \) becomes an unbiased estimator for \( V(Y) \), correcting for degrees of freedom.
03

Form the Estimator for Variance

Using the property that for a geometric random variable, the sample variance \( S^2 = \frac{(Y-1)^2}{Y^2} \), we need the expected value of this variance estimator to equal \( V(Y) \). Thus, the unbiased estimator of the variance \( V(Y) \) is \( Y(Y-1) \) functionally, as the expected value of \( Y(Y-1) \) will correctly adjust to variance with the sample size.
04

Create 2-Standard-Error Bound for Estimation Error

To estimate \( \frac{1}{p} \) using \( Y \), we have \( \hat{p} = \frac{1}{Y} \). The standard error (SE) of the estimator for \( 1/p \) is \( SE = \sqrt{V(Y)} \). Using our unbiased estimator, we form \( \hat{SE} = \sqrt{\frac{Y-1}{Y^2}} \). The 2-standard-error bound, therefore, is \( 2 \times \hat{SE} \), providing an interval \( \hat{Y} \pm 2 \times \hat{SE} \) for \( \frac{1}{p} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unbiased Estimator
An unbiased estimator is a statistical term referring to a method that, on average, accurately estimates the parameter of a population. In this context, considering a geometric distribution where the random variable \( Y \) represents the number of trials until the first success, we aim to find an estimator for its variance \( V(Y) = \frac{1-p}{p^2} \).

From the article, the variance estimator for \( V(Y) \) can be derived from a known property of geometric distributions. The sample variance \( S^2 \) for a large number of trials (\( n \)) can be utilized as an estimator for the population variance. The function \( Y(Y-1) \) is chosen as it properly estimates \( V(Y) \) when averaging across repeated sampling due to its correction for degrees of freedom.

The goal is to have the expected value of our estimator match the true parameter. Thus, using \( Y(Y-1) \) achieves this by functionally adjusting according to the number of observations. This provides an unbiased estimation of the variance of \( Y \).
Variance Estimation
In the context of probability and statistics, variance estimation is crucial for understanding how much each value in a data set varies from the mean. When dealing with geometric distribution, this entails calculating the variance of the number of tries needed until the first success.

For a geometric distribution, the variance \( V(Y) \) is represented as \( \frac{1-p}{p^2} \), where \( p \) is the probability of success in a single trial. For practical applications, especially when dealing with sample data, estimating this variance accurately is essential.

As mentioned, the use of \( Y(Y-1) \) provides an efficient estimator for the variance as it adjusts for the additional variability introduced by finite sample sizes. Understanding this estimation process enables statisticians to model real-world situations more precisely by accounting for variations in outcomes.

This variance estimation helps in predicting the spread of possible scenarios and plays a significant role in risk assessment in experiments involving repeated random trials.
Standard Error
Standard error (SE) is a statistical measure that indicates the accuracy with which a sample distribution represents a population mean. In a geometric distribution context, when estimating \( \frac{1}{p} \) using \( Y \), understanding SE is crucial to gauge precision.

The standard error is computed by taking the square root of the variance of the estimator. In this exercise example, \( SE = \sqrt{V(Y)} \). By incorporating our unbiased estimator, \( \hat{SE} = \sqrt{\frac{Y-1}{Y^2}} \), provides a corrected standard error relevant to our sample size. This adjustment ensures that the calculated intervals around the estimate are reliable.

By creating a 2-standard-error bound, we form a range that serves as a confidence interval around our parameter estimate. This results in an interval \( \hat{Y} \pm 2 \times \hat{SE} \), which quantifies the precision of our estimation of \( \frac{1}{p} \), allowing better decision-making based on the underlying data.
Probability Estimation
Probability estimation involves determining the likelihood of an event occurring within a given context. In a geometric distribution, estimating the probability \( p \) of success on a single trial is fundamental to analyzing the distribution of events.

Given the conditions that \( Y \) is the number of trials until the first success, the estimator \( \hat{p} = \frac{1}{Y} \) is employed. This estimator is grounded in the expected value of a geometric distribution, which is \( \frac{1}{p} \).

Using \( \hat{p} = \frac{1}{Y} \) provides a practical means to estimate the probability of success in individual trials as it inversely scales with repeated observations. Such probability estimation is critical because it affects predictions and decisions based on the likelihood of particular outcomes occurring.

Effective probability estimation is essential in fields like risk management, quality control, and experiment design, where predicting likely outcomes accurately guides strategic planning and operational adjustments.

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