/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 129 We noted in Section 8.3 that if ... [FREE SOLUTION] | 91Ó°ÊÓ

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We noted in Section 8.3 that if $$S^{\prime 2}=\frac{\sum_{i=1}^{n}\left(Y_{i}-\bar{Y}\right)^{2}}{n} \text { and } S^{2}=\frac{\sum_{i=1}^{n}\left(Y_{i}-\bar{Y}\right)^{2}}{n-1}$$ then \(S^{\prime 2}\) is a biased estimator of \(\sigma^{2}\), but \(S^{2}\) is an unbiased estimator of the same parameter. If we sample from a normal population, a. find \(V\left(S^{\prime 2}\right)\) b. show that \(V\left(S^{2}\right)>V\left(S^{\prime 2}\right)\)

Short Answer

Expert verified
a. \(V(S'^2) = \frac{2\sigma^4}{n}\); b. Yes, \(V(S^2) > V(S'^2)\).

Step by step solution

01

Recall the definitions and properties

We already know that \(S'^2\) is a biased estimator for the population variance \(\sigma^2\), and \(S^2\) is an unbiased estimator. We are given the formulas for \(S'^2\) and \(S^2\). The goal is to find the variance of \(S'^2\) and show \(V(S^2) > V(S'^2)\).
02

Calculate the variance of \(S'^2\)

The formula for the variance of \(S'^2\), when sampling from a normal distribution, is given by the equation:\[ V(S'^2) = \frac{2\sigma^4}{n} \]This is derived from the properties of the chi-squared distribution and the sampling distribution of variance estimators.
03

Calculate the variance of \(S^2\)

To calculate the variance of \(S^2\), we use the relation:\[ V(S^2) = \frac{2\sigma^4}{n-1} \]Notice that this considers the \((n-1)\) denominator in \(S^2\) as it is based on the sample variance with \(n-1\) degrees of freedom, which is unbiased.
04

Compare the variances \(V(S^2)\) and \(V(S'^2)\)

We need to compare \(V(S^2) = \frac{2\sigma^4}{n-1}\) with \(V(S'^2) = \frac{2\sigma^4}{n}\). Since \(n > n-1\), the denominator for \(V(S^2)\) is smaller than that for \(V(S'^2)\). This implies that \(V(S^2) > V(S'^2)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variance Estimators
Estimating variance is crucial in statistics, especially when analyzing data sets. Variance estimators help us understand the spread or variability within a data set. They give insight into how much individual data points deviate from the mean. In the context of a normal population, two primary variance estimators are used: \( S'^2 \) and \( S^2 \).
The formula for \( S'^2 \) is \( \frac{\sum_{i=1}^{n}(Y_{i}-\bar{Y})^{2}}{n} \), while \( S^2 \) is calculated as \( \frac{\sum_{i=1}^{n}(Y_{i}-\bar{Y})^{2}}{n-1} \).

This distinction in their formulas arises from how they consider population and sample sizes, with \( S^2 \) using \( n-1 \) to adjust for degrees of freedom in a sample, ensuring it is a more accurate reflection of the population variance.
Biased vs. Unbiased Estimators
When we talk about biased vs. unbiased estimators, we refer to the accuracy and reliability of these estimators to reflect a true population parameter. A biased estimator consistently overestimates or underestimates the parameter it is intended to estimate.
  • \( S'^2 \) is biased because it tends to underestimate the true population variance \( \sigma^2 \).
  • On the other hand, \( S^2 \) is an unbiased estimator, as its expected value equals the true variance \( \sigma^2 \).
This is crucial when performing statistical analyses because using an unbiased estimator (like \( S^2 \)) means that in repeated sampling, the average value of the estimator equals the parameter being estimated, providing more reliable interpretation.
Sample Variance
Sample variance is a statistic that provides insight into the spread of data points within a sample. It is a crucial step in estimating population parameters from sample data and is fundamental in inferential statistics.
To compute the sample variance \( S^2 \), you subtract the sample mean \( \bar{Y} \) from each data point \( Y_i \), square the result, and then sum all these squares. The sum is then divided by \( n-1 \), not \( n \) as it corrects the estimation bias by accounting for degrees of freedom. This makes \( S^2 \) slightly larger, but unbiased, in contrast to \( S'^2 \), which employs \( n \) and thus remains biased.
Chi-Squared Distribution
The chi-squared distribution plays a pivotal role in the realm of variance analysis. Specifically, when sampling from a normal distribution, the sum of the squares of \( n-1 \) independent standard normal random variables follows a chi-squared distribution with \( n-1 \) degrees of freedom.
This property is key in deriving the variances of variance estimators:\( V(S'^2) = \frac{2\sigma^4}{n} \) and \( V(S^2) = \frac{2\sigma^4}{n-1} \).
  • The degrees of freedom, accounted for in \( n-1 \), originate from this distribution and justify the why sample variance \( S^2 \) is unbiased.
  • It highlights how chi-squared distribution helps adjust and correct estimates to reflect the true population variance accurately.
Understanding this distribution is essential for grasping how statistical variances are computed and interpreted.

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