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The number of breakdowns per week for a type of minicomputer is a random variable \(Y\) with a Poisson distribution and mean \(\lambda\). A random sample \(Y_{1}, Y_{2}, \ldots, Y_{n}\) of observations on the weekly number of breakdowns is available. a. Suggest an unbiased estimator for \(\lambda\). b. The weekly cost of repairing these breakdowns is \(C=3 Y+Y^{2} .\) Show that \(E(C)=4 \lambda+\lambda^{2}\) c. Find a function of \(Y_{1}, Y_{2}, \ldots, Y_{n}\) that is an unbiased estimator of \(E(C)\). [Hint: Use what you know about \(\left.\bar{Y} \text { and }(\bar{Y})^{2} .\right]\)

Short Answer

Expert verified
a. \(\bar{Y}\); b. \(E(C) = 4\lambda + \lambda^2\); c. \(4\bar{Y} + (\bar{Y})^2\).

Step by step solution

01

Understanding Poisson Distribution

The Poisson distribution is used for modeling the number of events (like breakdowns) that occur within a fixed interval. The number of breakdowns per week, denoted by the random variable \( Y \), follows a Poisson distribution with mean \( \lambda \).
02

Estimator for \( \lambda \)

For a Poisson distribution with mean \( \lambda \), the sample mean \( \bar{Y} = \frac{1}{n} \sum_{i=1}^{n} Y_i \) is an unbiased estimator of \( \lambda \). This is because the expected value \( E(\bar{Y}) \) is equal to \( \lambda \).
03

Calculate Expected Cost \( E(C) \)

The cost function is given as \( C = 3Y + Y^2 \). To find \( E(C) \), compute:\[ E(C) = E(3Y + Y^2) = 3E(Y) + E(Y^2) \].For a Poisson random variable, \( E(Y) = \lambda \) and \( E(Y^2) = \lambda + \lambda^2 \). Thus, \[ E(C) = 3\lambda + (\lambda + \lambda^2) = 4\lambda + \lambda^2 \].
04

Estimator for \( E(C) \)

Using the hint that \( \bar{Y} \) is an unbiased estimator for \( \lambda \), the estimator for \( E(C) = 4\lambda + \lambda^2 \) can be constructed as \( 4\bar{Y} + (\bar{Y})^2 \). Here, \( \bar{Y} \) estimates \( \lambda \), and \( (\bar{Y})^2 \) estimates \( \lambda^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unbiased Estimator
An unbiased estimator is a statistical term used to describe an estimate of a parameter, such as the mean, that is precisely equal to the expected value of the parameter being estimated. In simpler terms, it means that over numerous samples, the average of the estimates will converge to the true value of the parameter.

In the context of the Poisson distribution, where we are analyzing the number of minicomputer breakdowns per week, the unbiased estimator for the parameter \( \lambda \) is the mean of the sample, denoted as \( \bar{Y} = \frac{1}{n} \sum_{i=1}^{n} Y_i \). This is because the expected value of \( \bar{Y} \) is \( \lambda \), satisfying the condition of being an unbiased estimator.

Using \( \bar{Y} \) achieves an accurate representation of \( \lambda \) without systematic error, which is the key characteristic of unbiased estimators and essential for making reliable inferences in statistical analysis.
Expected Value
The expected value is a fundamental concept in probability that represents the average outcome of a random variable if an experiment is repeated numerous times. For the Poisson distribution, this involves determining the expected number of breakdowns, as well as any associated costs.

In this exercise, the cost function is given by \( C = 3Y + Y^2 \). To calculate the expected cost \( E(C) \), we break it down into two components: the expected value of \( Y \), which is \( \lambda \) for a Poisson distribution, and the expected value of \( Y^2 \), which is \( \lambda + \lambda^2 \).

Thus, the formula for the expected cost becomes:
  • \( E(C) = 3E(Y) + E(Y^2) = 3\lambda + (\lambda + \lambda^2) \)
  • Simplifying gives \( E(C) = 4\lambda + \lambda^2 \)
Understanding expected value is crucial as it provides insights into the average long-term cost of breakdowns, enabling effective budgeting and policy-making.
Cost Function
A cost function relates a certain cost to a variable, in this case, the number of breakdowns \( Y \). Given the Poisson distribution's nature and the mean \( \lambda \), the cost function is expressed as \( C = 3Y + Y^2 \), which accounts for both fixed and quadratic components of cost.

To find an unbiased estimator for the expected cost, similar reasoning for \( \lambda \) is utilized. Knowing that \( \bar{Y} \) is an unbiased estimator for \( \lambda \), we substitute to estimate \( 4\lambda + \lambda^2 \) using our sample's average criteria.

The resulting function, \( 4\bar{Y} + (\bar{Y})^2 \), serves as an unbiased estimator of \( E(C) \):
  • \( 4\bar{Y} \) estimates \( 4\lambda \)
  • \( (\bar{Y})^2 \) estimates \( \lambda^2 \)
This approach helps in assessing anticipated repair costs using available sample data, guiding future forecasts and decisions related to maintenance expenses.

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Most popular questions from this chapter

A factory operates with two machines of type \(A\) and one machine of type \(B\). The weekly repair costs \(X\) for type \(A\) machines are normally distributed with mean \(\mu_{1}\) and variance \(\sigma^{2}\). The weekly repair costs \(Y\) for machines of type \(B\) are also normally distributed but with mean \(\mu_{2}\) and variance \(3 \sigma^{2} .\) The expected repair cost per week for the factory is thus \(2 \mu_{1}+\mu_{2} .\) If you are given a random sample \(X_{1}, X_{2}, \ldots, X_{n}\) on costs of type \(A\) machines and an independent random sample \(Y_{1}, Y_{2}, \ldots, Y_{m}\) on costs for type \(\mathrm{B}\) machines, show how you would construct a \(95 \%\) confidence interval for \(2 \mu_{1}+\mu_{2}\) a. if \(\sigma^{2}\) is known. b. if \(\sigma^{2}\) is not known.

Organic chemists often purify organic compounds by a method known as fractional crystallization. An experimenter wanted to prepare and purify \(4.85 \mathrm{g}\) of aniline. Ten 4.85 -gram specimens of aniline were prepared and purified to produce acetanilide. The following dry yields were obtained: $$\begin{array}{llllllll} 3.85, & 3.88, & 3.90, & 3.62, & 3.72, & 3.80, & 3.85, & 3.36, & 4.01, & 3.82 \end{array}$$ Construct a \(95 \%\) confidence interval for the mean number of grams of acetanilide that can be recovered from 4.85 grams of aniline.

Refer to Exercise 8.34. In polycrystalline aluminum, the number of grain nucleation sites per unit volume is modeled as having a Poisson distribution with mean \(\lambda\). Fifty unit-volume test specimens subjected to annealing under regime A produced an average of 20 sites per unit volume. Fifty independently selected unit-volume test specimens subjected to annealing regime \(\mathrm{B}\) produced an average of 23 sites per unit volume. a. Estimate the mean number \(\lambda_{\mathrm{A}}\) of nucleation sites for regime \(\mathrm{A}\) and place a 2 -standard-error bound on the error of estimation. b. Estimate the difference in the mean numbers of nucleation sites \(\lambda_{A}-\lambda_{B}\) for regimes \(A\) and B. Place a 2-standard-error bound on the error of estimation.Would you say that regime B tends to produce a larger mean number of nucleation sites? Why?

The Mars twin rovers, Spirit and Opportunity, which roamed the surface of Mars in the winter of 2004, found evidence that there was once water on Mars, raising the possibility that there was once life on the plant. Do you think that the United States should pursue a program to send humans to Mars? An opinion poll \(^{\star}\) indicated that \(49 \%\) of the 1093 adults surveyed think that we should pursue such a program. a. Estimate the proportion of all Americans who think that the United States should pursue a program to send humans to Mars. Find a bound on the error of estimation. b. The poll actually asked several questions. If we wanted to report an error of estimation that would be valid for all of the questions on the poll, what value should we use? [Hint: What is the maximum possible value for \(p \times q ?]\)

A state wildlife service wants to estimate the mean number of days that each licensed hunter actually hunts during a given season, with a bound on the error of estimation equal to 2 hunting days. If data collected in earlier surveys have shown \(\sigma\) to be approximately equal to 10 , how many hunters must be included in the survey?

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