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If \(Y\) is a random variable that has an \(F\) distribution with \(\nu_{1}\) numerator and \(\nu_{2}\) denominator degrees of freedom, show that \(U=1 / Y\) has an \(F\) distribution with \(\nu_{2}\) numerator and \(\nu_{1}\) denominator degrees of freedom.

Short Answer

Expert verified
If \( Y \sim F(\nu_1, \nu_2) \), then \( U = \frac{1}{Y} \sim F(\nu_2, \nu_1) \).

Step by step solution

01

Definition of an F-distribution

An F-distribution is defined as the ratio of two independent chi-squared distributions divided by their respective degrees of freedom. If a random variable \( Y \) follows an F-distribution with \( u_1 \) numerator and \( u_2 \) denominator degrees of freedom, then \( Y \) can be expressed as \( Y = \frac{(X_1 / u_1)}{(X_2 / u_2)} \), where \( X_1 \) and \( X_2 \) are independent chi-squared variables with \( u_1 \) and \( u_2 \) degrees of freedom respectively.
02

Transformation of Variables

Consider the transformation \( U = \frac{1}{Y} \). Therefore, \( U \) can be rewritten as \( U = \frac{(X_2 / u_2)}{(X_1 / u_1)} \), which is the inverse of the structure of \( Y \).
03

Identifying the Distribution of U

Given the transformation \( U = \frac{1}{Y} = \frac{(X_2 / u_2)}{(X_1 / u_1)} \), and noting that if \( Y \) is F distributed as \( F(u_1, u_2) \), \( U \) will naturally follow an \( F \) distribution where the roles of \( u_1 \) and \( u_2 \) are swapped. This means \( U \) follows \( F(u_2, u_1) \).
04

Conclusion

The transformation \( U = \frac{1}{Y} \) results in \( U \) having an \( F \)-distribution with the numerator and denominator degrees of freedom swapped, confirming that \( U \sim F(u_2, u_1) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chi-Squared Distribution
The chi-squared distribution is a fundamental concept in statistics, especially useful in hypothesis testing and constructing confidence intervals. It is a special type of probability distribution that appears when a set of random variables, each following a normal distribution, are squared and summed.
  • It is denoted as \( \chi^2 \) and characterized by the parameter called degrees of freedom \( u \).
  • This distribution is commonly used in scenarios where we need to compare a sample variance against a known population variance.
The chi-squared distribution arises naturally when dealing with data that has been squared. For instance, when you want to assess variability or spread using variance, which is a squared value. In the context of the F-distribution, each of the two independent chi-squared distributions contributes to constructing the F-distribution by forming a ratio between the two. This is why chi-squared is key to understanding F-distributions.
Degrees of Freedom
Degrees of freedom (DoF) represent the number of independent values that can vary in an analysis without breaking any given constraints. Imagine it as the number of choices you have when filling in values in a dataset. More formally:
  • Degrees of freedom are used as parameters in various statistical distributions such as \( \chi^2 \) and F-distributions.
  • In mathematical formulas, it determines the shape of the distribution. For instance, in \( \chi^2 \) with \( u \) as degrees of freedom, this number influences skewness, kurtosis, and tail heaviness of the distribution.
In an F-distribution, you have two parameters of degrees of freedom: one for the numerator and one for the denominator.This dual aspect describes the structure and relationship of the underlying chi-squared distributions. When you transform variables, like in the exercise, you also swap these degrees of freedom, which illustrates the flexibility and reversibility of this probabilistic structure.
Random Variable Transformation
A random variable transformation is a process where one random variable is expressed in terms of another, modifying its distribution properties. In the provided exercise, the transformation involves \( Y \rightarrow U = \frac{1}{Y} \).
  • This changes the original distribution of \( Y\) into a new distribution for \( U \), preserving the probability characteristics.
  • In this case, the transformation results in flipping the roles of the degrees of freedom in the F-distribution.
This concept is crucial because it allows you to manipulate distributions to gain insights or simplify analysis.For example, by inverting \( Y \), we demonstrate that \( U \)'s structure still fits within the family of F-distributions, albeit with swapped parameters. It showcases the versatility and robustness of transformations in statistical theory and application.

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Most popular questions from this chapter

Resistors to be used in a circuit have average resistance 200 ohms and standard deviation 10 ohms. Suppose 25 of these resistors are randomly selected to be used in a circuit. a. What is the probability that the average resistance for the 25 resistors is between 199 and 202 ohms? b. Find the probability that the total resistance does not exceed 5100 ohms. [Hint: see Example 7.9.]

In 2004 Florida was hit by four major hurricanes. In 2005 a survey indicated that, in \(2004,48 \%\) of the households in Florida had no plans for escaping an approaching hurricane. Suppose that a recent random sample of 50 households was selected in Gainesville and that those in 29 of the households indicated that their household had a hurricane escape plan. a. If the 2004 state percentages still apply to recent Gainesville households, use the Normal Approximation to Binomial Distribution applet to find the exact and approximate values of the probability that 29 or more of the households sampled have a hurricane escape plan. b. Refer to part (a). Is the normal approximation close to the exact binomial probability? Explain why.

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The Environmental Protection Agency is concerned with the problem of setting criteria for the amounts of certain toxic chemicals to be allowed in freshwater lakes and rivers. A common measure of toxicity for any pollutant is the concentration of the pollutant that will kill half of the test species in a given amount of time (usually 96 hours for fish species). This measure is called LC50 (lethal concentration killing 50\% of the test species). In many studies, the values contained in the natural logarithm of LC50 measurements are normally distributed, and, hence, the analysis is based on \(\ln (\mathrm{LC} 50)\) data. Studies of the effects of copper on a certain species of fish (say, species A) show the variance of In(LC50) measurements to be around. 4 with concentration measurements in milligrams per liter. If \(n=10\) studies on \(L C 50\) for copper are to be completed, find the probability that the sample mean of \(\ln (\text { LC50 })\) will differ from the true population mean by no more than .5.

The times that a cashier spends processing individual customer's order are independent random variables with mean 2.5 minutes and standard deviation 2 minutes. What is the approximate probability that it will take more than 4 hours to process the orders of 100 people?

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