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Suppose that the random variables \(Y_{1}\) and \(Y_{2}\) have means \(\mu_{1}\) and \(\mu_{2}\) and variances \(\sigma_{1}^{2}\) and \(\sigma_{2}^{2}\) respectively. Use the basic definition of the covariance of two random variables to establish that a. \(\operatorname{Cov}\left(Y_{1}, Y_{2}\right)=\operatorname{Cov}\left(Y_{2}, Y_{1}\right)\). b. \(\operatorname{Cov}\left(Y_{1}, Y_{1}\right)=V\left(Y_{1}\right)=\sigma_{1}^{2} .\) That is, the covariance of a random variable and itself is just the variance of the random variable.

Short Answer

Expert verified
A. Covariance is symmetric; B. Covariance of a variable with itself equals its variance.

Step by step solution

01

Understand Covariance Definition

Covariance is a measure of how much two random variables change together. The covariance of two variables, \( Y_1 \) and \( Y_2 \), is defined as \( \operatorname{Cov}(Y_1, Y_2) = E[(Y_1 - \mu_1)(Y_2 - \mu_2)] \), where \( E \) is the expectation or mean.
02

Prove Symmetry of Covariance

To show that \( \operatorname{Cov}(Y_1, Y_2) = \operatorname{Cov}(Y_2, Y_1) \), we use the covariance definition:\[ \operatorname{Cov}(Y_1, Y_2) = E[(Y_1 - \mu_1)(Y_2 - \mu_2)] \]If we switch \( Y_1 \) and \( Y_2 \), we get:\[ \operatorname{Cov}(Y_2, Y_1) = E[(Y_2 - \mu_2)(Y_1 - \mu_1)] \]Since multiplication is commutative, \((Y_1 - \mu_1)(Y_2 - \mu_2) = (Y_2 - \mu_2)(Y_1 - \mu_1)\), it follows that \( \operatorname{Cov}(Y_1, Y_2) = \operatorname{Cov}(Y_2, Y_1) \).
03

Prove Covariance of a Variable with Itself

The covariance of a random variable with itself, \( \operatorname{Cov}(Y_1, Y_1) \), is calculated using the definition:\[ \operatorname{Cov}(Y_1, Y_1) = E[(Y_1 - \mu_1)^2] \]This is simply the definition of the variance of \( Y_1 \), i.e., \( V(Y_1) = \sigma_1^2 \). Thus, you can see that \( \operatorname{Cov}(Y_1, Y_1) = \sigma_1^2 \).
04

Conclusion

By using the properties of the covariance and the definition of variance, we showed:A. \( \operatorname{Cov}(Y_1, Y_2) = \operatorname{Cov}(Y_2, Y_1) \) due to the commutative property of multiplication.B. \( \operatorname{Cov}(Y_1, Y_1) = \sigma_1^2 \), as covariance of a variable with itself equals its variance.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
To fully grasp covariance, it's important to first understand what a random variable is. In statistics, a random variable is a variable whose possible values are numerical outcomes of a random phenomenon. There are generally two types of random variables: discrete and continuous.
  • Discrete random variables take on a countable number of distinct values, such as the sum of dice rolls or the number of heads in coin tosses.
  • Continuous random variables, however, can take on any numerical value in a certain range, like the height of students in a class or the time it takes to complete a race.
essential aspect of a random variable is its probability distribution, which describes the probabilities of all possible outcomes. Now, in our problem context, we have two random variables, \( Y_1 \) and \( Y_2 \), each described by their means \( \mu_1 \) and \( \mu_2 \), and variances \( \sigma_1^2 \) and \( \sigma_2^2 \).These characteristics are the foundation on which we build the understanding of covariance.
Variance
Variance is a key concept when dealing with random variables and covariance. It measures how far a set of numbers, in this case, the values of a random variable, are spread out from their average value or mean.For any random variable \( Y \), the variance \( V(Y) \) is calculated as follows:\[ \sigma^2 = V(Y) = E[(Y - \mu)^2] \]where \( E \) represents the expectation or mean of a given set.Variance is crucial because it describes the dispersion of values around the mean, giving a quantitative form of variability.
  • Low variance indicates that data points are generally close to the mean.
  • High variance means they are spread out over a wider range of values.
Its relationship with covariance is also notable as it defines the covariance of a random variable with itself. Understanding this connection further clarifies why \( \operatorname{Cov}(Y_1, Y_1) = \sigma_1^2 \) in our problem context.
Properties of Covariance
Covariance is a statistical measure used to determine how much two random variables change together. It's a useful indicator of the direction of the linear relationship between variables.The basic properties of covariance include:
  • Symmetry: The covariance between two variables is symmetric, meaning \( \operatorname{Cov}(Y_1, Y_2) \) is the same as \( \operatorname{Cov}(Y_2, Y_1) \). This is due to the commutative property of multiplication, which states that the order in which numbers are multiplied does not affect the product.
  • Covariance with Itself: The covariance of a variable with itself is equal to its own variance, an essential concept in probability theory. Hence, \( \operatorname{Cov}(Y_1, Y_1) = \sigma_1^2 \).
  • Zero Covariance: If the covariance between two variables is zero, it suggests that the variables have no linear relationship. However, this doesn't necessarily imply they are independent.
In practical applications, understanding the properties of covariance allows one to interpret relationships between variables effectively, assessing how changes in one variable might predict changes in another. This foundational knowledge was applied to solve the initial covariance problem in the exercise.

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Most popular questions from this chapter

Let \(Y_{1}\) and \(Y_{2}\) denote the proportions of time (out of one workday) during which employees I and II, respectively, perform their assigned tasks. The joint relative frequency behavior of \(Y_{1}\) and \(Y_{2}\) is modeled by the density function $$f\left(y_{1}, y_{2}\right)=\left\\{\begin{array}{ll} y_{1}+y_{2}, & 0 \leq y_{1} \leq 1,0 \leq y_{2} \leq 1 \\ 0, & \text { elsewhere } \end{array}\right.$$ a. Find \(P\left(Y_{1}<1 / 2, Y_{2}>1 / 4\right)\). b. Find \(P\left(Y_{1}+Y_{2} \leq 1\right)\).

The management at a fast-food outlet is interested in the joint behavior of the random variables \(Y_{1},\) defined as the total time between a customer's arrival at the store and departure from the service window, and \(Y_{2}\), the time a customer waits in line before reaching the service window. Because \(Y_{1}\) includes the time a customer waits in line, we must have \(Y_{1} \geq Y_{2}\). The relative frequency distribution of observed values of \(Y_{1}\) and \(Y_{2}\) can be modeled by the probability density function $$f\left(y_{1}, y_{2}\right)=\left\\{\begin{array}{ll} e^{-y_{1}}, & 0 \leq y_{2} \leq y_{1}<\infty \\ 0, & \text { elsewhere } \end{array}\right.$$ with time measured in minutes. Find a. \(P\left(Y_{1}<2, Y_{2}>1\right)\). b. \(P\left(Y_{1} \geq 2 Y_{2}\right)\). c. \(P\left(Y_{1}-Y_{2} \geq 1\right)\). (Notice that \(Y_{1}-Y_{2}\) denotes the time spent at the service window.)

A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. Let \(Y_{1}\) and \(Y_{2}\) denote the numbers of customers who spend more than \(\$ 50\) on groceries at the respective counters. Suppose that \(Y_{1}\) and \(Y_{2}\) are independent binomial random variables, with the probability that a customer at counter I will spend more than \$50 equal to .2 and the probability that a customer at counter II will spend more than \(\$ 50\) equal to .3. Find the a. joint probability distribution for \(Y_{1}\) and \(Y_{2}\) b. probability that not more than one of the three customers will spend more than \(\$ 50 .\)

Let \(Y_{1}\) and \(Y_{2}\) have joint density function \(f\left(y_{1}, y_{2}\right)\) and marginal densities \(f_{1}\left(y_{1}\right)\) and \(f_{2}\left(y_{2}\right)\) respectively. Show that \(Y_{1}\) and \(Y_{2}\) are independent if and only if \(f\left(y_{1} | y_{2}\right)=f_{1}\left(y_{1}\right)\) for all values of \(y_{1}\) and for all \(y_{2}\) such that \(f_{2}\left(y_{2}\right)>0 .\) A completely analogous argument establishes that \(Y_{1}\) and \(Y_{2}\) are independent if and only if \(f\left(y_{2} | y_{1}\right)=f_{2}\left(y_{2}\right)\) for all values of \(y_{2}\) and for all \(y_{1}\) such that \(f_{1}\left(y_{1}\right)>0\).

A population of \(N\) alligators is to be sampled in order to obtain an approximate measure of the difference between the proportions of sexually mature males and sexually mature females. Obviously, this parameter has important implications for the future of the population. Assume that \(n\) animals are to be sampled without replacement. Let \(Y_{1}\) denote the number of mature females and \(Y_{2}\) the number of mature males in the sample. If the population contains proportions \(p_{1}\) and \(p_{2}\) of mature females and males, respectively (with \(p_{1}+p_{2}<1\) ), find expressions for $$E\left(\frac{Y_{1}}{n}-\frac{Y_{2}}{n}\right) \quad \text { and } \quad V\left(\frac{Y_{1}}{n}-\frac{Y_{2}}{n}\right)$$

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