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Suppose that \(Y_{1}\) and \(Y_{2}\) are independent \(\chi^{2}\) random variables with \(\nu_{1}\) and \(\nu_{2}\) degrees of freedom, respectively. Find $$\text { a. } E\left(Y_{1}+Y_{2}\right)$$ $$\text { b. } V\left(Y_{1}+Y_{2}\right)$$

Short Answer

Expert verified
a. \(E(Y_1 + Y_2) = \nu_1 + \nu_2\); b. \(V(Y_1 + Y_2) = 2\nu_1 + 2\nu_2\)

Step by step solution

01

Understanding the Expectation of a Sum

To find the expectation \( E(Y_1 + Y_2) \), use the linearity property of expectation, which states that \( E(aX + bY) = aE(X) + bE(Y) \). Since \( Y_1 \) and \( Y_2 \) are independent, we have \( E(Y_1 + Y_2) = E(Y_1) + E(Y_2) \).
02

Compute Expectation of Each Chi-Square Variable

The expectation of a \( \chi^2 \) distribution with \( u \) degrees of freedom is \( u \). Thus, \( E(Y_1) = u_1 \) and \( E(Y_2) = u_2 \).
03

Calculate Total Expectation

Using the results from Step 2, the total expectation is \( E(Y_1 + Y_2) = u_1 + u_2 \).
04

Understanding the Variance of a Sum

For variance, because \( Y_1 \) and \( Y_2 \) are independent, the variance of their sum is the sum of their variances: \( V(Y_1 + Y_2) = V(Y_1) + V(Y_2) \).
05

Compute Variance of Each Chi-Square Variable

The variance of a \( \chi^2 \) distribution with \( u \) degrees of freedom is \( 2u \). Therefore, \( V(Y_1) = 2u_1 \) and \( V(Y_2) = 2u_2 \).
06

Calculate Total Variance

Using the results from Step 5, the total variance is \( V(Y_1 + Y_2) = 2u_1 + 2u_2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expectation
Expectation is a fundamental concept in probability and statistics. It represents the average or mean value of a random variable over a large number of trials. In the context of the Chi-squared distribution, the expectation has a straightforward calculation. Suppose we have two independent Chi-squared random variables, say \(Y_1\) and \(Y_2\), with degrees of freedom \(u_1\) and \(u_2\), respectively. The expectation of a Chi-squared variable with \(u\) degrees of freedom is simply \(u\). Therefore, \(E(Y_1) = u_1\) and \(E(Y_2) = u_2\). By utilizing the property of expectation linearity, the expectation of the sum \(Y_1 + Y_2\) is the sum of their expectations:
  • \(E(Y_1 + Y_2) = E(Y_1) + E(Y_2) = u_1 + u_2\)
Understanding expectation helps us comprehend the typical outcome we can anticipate from a set of random variables.
Variance
Variance measures the spread or variability around the expectation of a random variable. It's a fundamental concept to understand how data is dispersed. For a Chi-squared random variable with \(u\) degrees of freedom, the variance is given by \(2u\). If \(Y_1\) and \(Y_2\) are independent Chi-squared variables, the variance of their sum is simply the sum of their variances, owing to their independence. Hence the calculation is:
  • \(V(Y_1 + Y_2) = V(Y_1) + V(Y_2) = 2u_1 + 2u_2\)
This formula indicates how widespread the outcomes of a sum of random variables could be and is crucial in predicting the variability within statistical models.
Independence
Independence in probability and statistics refers to the scenario where the occurrence of one random event does not affect the occurrence of another. When two random variables are independent, like \(Y_1\) and \(Y_2\) in our Chi-squared example, various properties of expectation and variance can be made simple. Specifically:
  • The expectation of the sum of independent random variables equals the sum of their expectations.
  • The variance follows the same rule; the variance of the sum equals the sum of their variances.
Understanding independence simplifies complex calculations and helps in unraveling the random nature of combined events. Independence is a powerful tool utilized frequently in statistical inference and probability analysis, revealing intrinsic relationships between variables.
Degrees of freedom
Degrees of freedom are a critical concept in statistics, often denoted by \(u\). They describe the number of values in the final calculation of a statistic that are free to vary. For a Chi-squared distribution, they’re particularly important as they directly determine its shape and expectations. Each independent Chi-squared variable in our example, \(Y_1\) and \(Y_2\), has its own degrees of freedom, \(u_1\) and \(u_2\). Together, they impact:
  • The expectation directly, as seen by \(E(Y_1 + Y_2) = u_1 + u_2\)
  • The variance too, since \(V(Y_1 + Y_2) = 2u_1 + 2u_2\)
Degrees of freedom are essential in hypothesis testing, modeling, and understanding how different constraints or parameters influence the variability and mean behavior of statistical distributions.

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Most popular questions from this chapter

The total sustained load on the concrete footing of a planned building is the sum of the dead load plus the occupancy load. Suppose that the dead load \(X_{1}\) has a gamma distribution with \(\alpha_{1}=50\) and \(\beta_{1}=2,\) whereas the occupancy load \(X_{2}\) has a gamma distribution with \(\alpha_{2}=20\) and \(\beta_{2}=2\) (Units are in kips.) Assume that \(X_{1}\) and \(X_{2}\) are independent. a. Find the mean and variance of the total sustained load on the footing. b. Find a value for the sustained load that will be exceeded with probability less than \(1 / 16\)

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Let \(Z\) be a standard normal random variable and let \(Y_{1}=Z\) and \(Y_{2}=Z^{2}\). a. What are \(E\left(Y_{1}\right)\) and \(E\left(Y_{2}\right) ?\) b. What is \(E\left(Y_{1} Y_{2}\right) ?\left[\text { Hint: } E\left(Y_{1} Y_{2}\right)=E\left(Z^{3}\right), \text { recall Exercise 4.199. }\right]\) c. What is \(\operatorname{Cov}\left(Y_{1}, Y_{2}\right) ?\) d. Notice that \(P\left(Y_{2}>1 | Y_{1}>1\right)=1 .\) Are \(Y_{1}\) and \(Y_{2}\) independent?

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