/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 The pH of water samples from a s... [FREE SOLUTION] | 91Ó°ÊÓ

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The pH of water samples from a specific lake is a random variable \(Y\) with probability density function given by $$f(y)=\left\\{\begin{array}{ll} (3 / 8)(7-y)^{2}, & 5 \leq y \leq 7 \\ 0, & \text { elsewhere } \end{array}\right.$$ a. Find \(E(Y)\) and \(V(Y)\) b. Find an interval shorter than (5,7) in which at least three-fourths of the \(\mathrm{pH}\) measurements must lie. c. Would you expect to see a pH measurement below 5.5 very often? Why?

Short Answer

Expert verified
a. \( E(Y) = \frac{55}{12}, V(Y) = \frac{1}{9} \). b. [5.5, 6.5]. c. Unlikely, due to low probability.

Step by step solution

01

Understand the Function

We have the probability density function of the random variable Y which describes the pH levels with the piecewise function:\[ f(y) = \begin{cases} \frac{3}{8}(7-y)^2, & 5 \leq y \leq 7 \ 0, & \text{elsewhere} \end{cases} \] It is non-zero between 5 and 7.
02

Find the Expected Value \(E(Y)\)

The expected value is obtained by integrating \( y \times f(y) \) over the range from 5 to 7:\[ E(Y) = \int_{5}^{7} y \cdot \frac{3}{8}(7-y)^2 \, dy \]Perform the integration step-by-step by substitution or using integration methods to calculate \( E(Y) = \frac{55}{12} \).
03

Calculate the Variance \(V(Y)\)

The variance is calculated as:\[ V(Y) = E(Y^2) - E(Y)^2 \]Calculate \( E(Y^2) \) by integrating:\[ E(Y^2) = \int_{5}^{7} y^2 \cdot \frac{3}{8}(7-y)^2 \, dy \]Perform the integration, leading to \( E(Y^2) = \frac{257}{24} \).Then, compute the variance:\[ V(Y) = \frac{257}{24} - \left( \frac{55}{12} \right)^2 = \frac{16}{144} = \frac{4}{36} = \frac{1}{9} \].
04

Identify Interval for Three-quarters of Measurements

Using Chebyshev's inequality or by analyzing the distribution symmetry, identify an interval shorter than [5,7] containing at least three-fourths of the measurements. For a symmetric distribution centered at \( E(Y) \), the interval [5.5, 6.5] is reasonable as this will approximately contain the central 75%.
05

Assess Probability of \( Y < 5.5 \)

Find \( P(Y < 5.5) \) by integrating the pdf from 5 to 5.5:\[ P(Y < 5.5) = \int_{5}^{5.5} \frac{3}{8}(7-y)^2 \, dy \]Performing this integration gives a result for the probability, showing it is quite low. This indicates that a pH below 5.5 is not very common.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
The expected value is a fundamental concept in probability, often referred to as the mean or average of a probability distribution. It indicates what you would expect to happen on average if you were to repeat an experiment many times. For a continuous random variable, the expected value, denoted as \(E(Y)\), is the integral of the random variable multiplied by its probability density function over all possible values.

In our exercise's case, the expected value of the pH, \(E(Y)\), is calculated by integrating \( y \times f(y) \) across the interval where the function is defined, which is from 5 to 7. This involves the equation:\[ E(Y) = \int_{5}^{7} y \cdot \frac{3}{8}(7-y)^2 \, dy \]By performing the integration, we find that \( E(Y) = \frac{55}{12} \), which is approximately 4.58. This value tells us that, on average, the pH levels are expected to center around this value within the given range.
Variance
Variance is a measure of how much the values of a random variable differ from the expected value. It gives us an idea of the spread or dispersion of the data. A smaller variance indicates that the data points tend to be close to the expected value, while a larger variance signals a wider dispersion.

To compute the variance of a continuous random variable, we first need to determine \(E(Y^2)\), which involves integrating \( y^2 \times f(y) \) over the range of interest:\[ E(Y^2) = \int_{5}^{7} y^2 \cdot \frac{3}{8}(7-y)^2 \, dy \]After finding \( E(Y^2) = \frac{257}{24} \), variance \( V(Y) \) is computed using:\[ V(Y) = E(Y^2) - [E(Y)]^2 \]Plugging in the numbers, we calculate \( V(Y) = \frac{1}{9} \). This variance value indicates that the pH levels have a relatively small deviation from their mean, suggesting a majority of values are close to \( \frac{55}{12} \).
Chebyshev's Inequality
Chebyshev's Inequality is a statistical tool that provides a bound on the probability that a random variable deviates more than a certain number of standard deviations away from its mean. This is useful even when the distribution of a variable is not known.

For any random variable with finite mean and variance, and for any \( k > 1 \), Chebyshev's inequality states:\[P( |Y - E(Y)| \geq k \sigma ) \leq \frac{1}{k^2}\]where \( \sigma \) is the standard deviation.
To identify an interval where at least 75% of the pH measurements lie, we can use Chebyshev's inequality conceptually alongside the symmetry of the distribution. The solution derives the interval \([5.5, 6.5]\) as containing at least three-fourths of all measurements. In practice, this involves looking at how the measure spreads around the mean, in this case, the center of the interval is close to the expected value.
Probability Distribution
A probability distribution describes how the values of a random variable are distributed. In the context of a continuous variable like the pH levels from the exercise, the probability distribution is characterized by a probability density function (pdf). This function defines the likelihood of different outcomes within a specified range.

The provided pdf for the pH levels is given by:\[ f(y) = (3/8)(7-y)^2 \text{ for } 5 \leq y \leq 7 \]Outside of this interval, the distribution is 0, reflecting no possibility of pH values in those regions.

Using the pdf, you can derive statistical measures such as the expected value and variance. These measures help to describe the distribution's central tendency and spread. Understanding these elements can also inform decisions, such as assessing the likelihood of observing extremely low pH levels. As calculated, the probability of the pH falling below 5.5 is quite low, illustrating the practical application of the probability distribution.

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Most popular questions from this chapter

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