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The length of time required to complete a college achievement test is found to be normally distributed with mean 70 minutes and standard deviation 12 minutes. When should the test be terminated if we wish to allow sufficient time for \(90 \%\) of the students to complete the test?

Short Answer

Expert verified
Terminate the test at 86 minutes.

Step by step solution

01

Understand the Problem and Data

We need to find the time that covers 90% of the students. We know that the test completion times are normally distributed with a mean (\( \mu \)) of 70 minutes and a standard deviation (\( \sigma \)) of 12 minutes.
02

Find the Z-Score for 90%

To find the time corresponding to 90% of the students, we need to determine the Z-score that corresponds to the 90th percentile of a standard normal distribution. From standard normal distribution tables or using a calculator, the Z-score for 90% is approximately 1.28.
03

Apply Z-Score Formula

The formula to find a particular value (\( X \)) from a normal distribution is given by the Z-score formula: \[ Z = \frac{X - \mu}{\sigma} \]Rearranging, we have: \[ X = Z \cdot \sigma + \mu \]Substitute \( Z = 1.28 \), \( \sigma = 12 \), and \( \mu = 70 \) into the equation.
04

Calculate the Time

Substitute the known values into the formula:\[ X = 1.28 \cdot 12 + 70 \]\[ X = 15.36 + 70 \]\[ X = 85.36 \]
05

Interpret the Result

The time we found, 85.36 minutes, represents the point by which 90% of students will complete the exam. Since we typically round to the nearest whole minute in practical situations, we should set the termination time at 86 minutes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Score
The Z-score, also known as a standard score, is a measure that describes a value's relation to the mean of a group of values. It is expressed as a number that indicates how many standard deviations an element is from the mean. The formula to calculate the Z-score of an individual data point is:
\[ Z = \frac{X - \mu}{\sigma} \]Where:
  • \( X \) is the value under consideration.
  • \( \mu \) is the mean of the distribution.
  • \( \sigma \) is the standard deviation.
Z-scores are a useful way of standardizing data, allowing us to compare data points from different distributions. When dealing with a normal distribution, the Z-score helps in determining the position of a data point within the distribution, such as perceiving how extreme a data point is compared to the average.
Mean and Standard Deviation
In statistics, the mean is the average value of a data set. It is calculated by adding all the numbers in a dataset and dividing by the count of those numbers:
\[ \mu = \frac{\sum X}{N} \]
  • \( \mu \) represents the mean.
  • \( \sum X \) is the sum of all data points.
  • \( N \) is the number of data points.
Standard deviation, on the other hand, is a measure of the amount of variation or dispersion in a set of values. A low standard deviation indicates that values tend to be close to the mean, whereas a high standard deviation indicates that values are spread out over a wider range:
\[ \sigma = \sqrt{\frac{\sum (X_i - \mu)^2}{N}} \]Both mean and standard deviation are essential in describing the nature of a normal distribution, helping to understand the central tendency and spread of data.
Percentile Calculation
Percentile calculation is a statistical measurement that provides the relative position of a value within a dataset. In terms of a normal distribution, the percentile determines the percentage of scores that fall below a particular value. This helps in understanding how a specific score compares to all other scores:
To calculate the time for a particular percentile, like the 90th percentile in a normal distribution, we can use the Z-score. A Z-score table or calculator helps find the Z-score that corresponds to a desired percentile, such as a Z-score of approximately 1.28 for the 90th percentile. Once the Z-score is determined, it can be converted to a raw score (actual value) using the mean and standard deviation.
This calculation is done by rearranging the Z-score formula to solve for the value of interest:\[ X = Z \cdot \sigma + \mu \]This formula allows us to find the specific score within a normal distribution that corresponds to any given percentile, making it a powerful tool for interpreting and understanding data.

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