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If \(\theta_{1}<\theta_{2}\), derive the moment-generating function of a random variable that has a uniform distribution on the interval \(\left(\theta_{1}, \theta_{2}\right)\)

Short Answer

Expert verified
The MGF is \(M_X(t) = \frac{e^{t\theta_2} - e^{t\theta_1}}{t(\theta_2 - \theta_1)}\).

Step by step solution

01

Define the Uniform Distribution

The random variable we are dealing with has a uniform distribution over the interval \((\theta_1, \theta_2)\). This means that for any \(x\) in this interval, the probability density function (pdf) is constant and can be expressed as \(f(x) = \frac{1}{\theta_2 - \theta_1}\). For values of \(x\) outside this interval, \(f(x) = 0\).
02

Write the Definition of MGF

The moment-generating function (MGF) of a random variable \(X\), denoted by \(M_X(t)\), is defined as \( M_X(t) = E[e^{tX}] \), which means it is the expected value of \(e^{tX}\).
03

Express the MGF for the Uniform Distribution

To find the MGF of the uniform distribution on \((\theta_1, \theta_2)\), compute:\[M_X(t) = \int_{\theta_1}^{\theta_2} e^{tx} f(x) \, dx = \int_{\theta_1}^{\theta_2} e^{tx} \frac{1}{\theta_2 - \theta_1} \, dx.\]
04

Integrate the Expression

Integrate the function \(e^{tx}\) within the limits \(\theta_1\) and \(\theta_2\):\[M_X(t) = \frac{1}{\theta_2 - \theta_1} \int_{\theta_1}^{\theta_2} e^{tx} \, dx = \frac{1}{\theta_2 - \theta_1} \left[ \frac{e^{tx}}{t} \right]_{\theta_1}^{\theta_2}.\]
05

Evaluate the Definite Integral

Substitute the limits of integration:\[M_X(t) = \frac{1}{\theta_2 - \theta_1} \left( \frac{e^{t\theta_2}}{t} - \frac{e^{t\theta_1}}{t} \right) = \frac{e^{t\theta_2} - e^{t\theta_1}}{t(\theta_2 - \theta_1)}.\]This is the MGF for the uniform distribution on \((\theta_1, \theta_2)\).
06

Simplify for Special Cases (if needed)

For \(t = 0\), notice that the MGF should equal 1, which aligns with the definition, as \(M_X(0) = \frac{e^{0} - e^{0}}{0} = 1 - 0 = 1\). Thus, the derived MGF is generally valid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniform Distribution
The uniform distribution is one of the simplest types of probability distributions in statistics. When we say that a random variable has a uniform distribution on an interval \(a, b\), it means that every value within that interval is equally likely to occur.
This is characterized by a constant probability density function (pdf). For our case, where a random variable is uniformly distributed over \(\theta_1, \theta_2\), the pdf is given as \(f(x) = \frac{1}{\theta_2 - \theta_1}\) for \(x\) within the interval.
If \(x\) is outside this range, the pdf is zero, indicating that those values have no chance of occurring. Some key features of uniform distribution:
  • Constant probability across the interval \(\theta_1 \) to \(\theta_2\).
  • Mean of the distribution is given by \(\frac{\theta_1 + \theta_2}{2}\).
  • Variance is \(\frac{(\theta_2 - \theta_1)^2}{12}\).
Uniform distributions are often used in simulations when all outcomes are equally likely.
Probability Density Function
The probability density function (pdf) is a fundamental concept in understanding continuous random variables. It's a function that describes the relative likelihood for this random variable to take on a given value. A pdf is non-negative and integrates to one over its entire space, ensuring the total probability of all outcomes sums to 1. For a continuous uniform distribution as in our exercise, the pdf is constant across the interval \(\theta_1, \theta_2\).
Meaning the function \(f(x)\) is flat across this range, simplifying the calculation for many statistical operations.
In other words, there is no preferential leaning towards certain values within the given interval.A few important points:
  • The area under the pdf curve over a certain interval provides the probability that the variable falls within that interval.
  • The pdf itself can be used to derive other properties, such as the moment-generating function.
This concept is crucial for designs like the pdf of a normal distribution, which varies, unlike the constant version of a uniform distribution.
Expected Value
The expected value, often referred to as the mean or average, is a measure of the central tendency of a random variable. In other words, it provides a 'long-run' average if an experiment is repeated multiple times. For continuous distributions, the expected value \(E[X]\) is calculated using an integral of the product of the variable and its probability density function over the possible values. For the uniform distribution on the interval \(\theta_1, \theta_2\), the expected value can be calculated with:\[E[X] = \int_{\theta_1}^{\theta_2} x \cdot f(x) \, dx = \int_{\theta_1}^{\theta_2} x \cdot \frac{1}{\theta_2 - \theta_1} \, dx = \frac{\theta_1 + \theta_2}{2}\]This result shows that the expected value of a uniformly distributed variable is simply the midpoint of the interval.
It reflects symmetry, as any shift would point to a weighted region within the interval.
Thus, expected value becomes a key in understanding and predicting outcomes of random variables.
Integration in Calculus
Integration is a fundamental operation in calculus that is used to calculate areas under curves. It's particularly useful when working with probability density functions of continuous random variables. In the context of deriving the moment-generating function for a uniform distribution, integration is used to calculate the expected value of \(e^{tX}\). This involves integrating \(e^{tx}\) over the interval \(\theta_1, \theta_2\), which was expressed as:\[\int_{\theta_1}^{\theta_2} e^{tx} \cdot \frac{1}{\theta_2 - \theta_1} \, dx\]The power of integration allows us to handle even complex functions \(e^{tx}\) systematically over defined limits.
Integration helps compute values that are otherwise difficult to determine exactly.
This process highlights the relationship between calculus and probability.Additionally, integration enables other statistical calculations such as determining variances and higher moments. Integration plays a pivotal role in linking calculus with statistical concepts, making it indispensable for deep learning in statistics.

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Most popular questions from this chapter

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