/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 184 A city commissioner claims that ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A city commissioner claims that \(80 \%\) of the people living in the city favor garbage collection by contract to a private company over collection by city employees. To test the commissioner's claim, 25 city residents are randomly selected, yielding 22 who prefer contracting to a private company. a. If the commissioner's claim is correct, what is the probability that the sample would contain at least 22 who prefer contracting to a private company? b. If the commissioner's claim is correct, what is the probability that exactly 22 would prefer contracting to a private company? c. Based on observing 22 in a sample of size 25 who prefer contracting to a private company, what do you conclude about the commissioner's claim that \(80 \%\) of city residents prefer contracting to a private company?

Short Answer

Expert verified
Parts a and b involve binomial probability calculations, while Part c involves evaluation based on statistical significance.

Step by step solution

01

Identify the Parameters for a Binomial Distribution

The problem describes a binomial experiment. Let \( n = 25 \) be the number of trials (residents sampled), \( p = 0.8 \) be the probability of success (a resident prefers contracting), and \( X \) be the random variable representing the number of successes in 25 trials.
02

Calculate Probability for Part a (P(X ≥ 22))

We are interested in finding \( P(X \geq 22) \). This can be calculated using the complement rule and binomial probability formula: \( P(X \geq 22) = 1 - P(X \leq 21) \). Use the cumulative binomial probability formula: \[ P(X \leq k) = \sum_{x=0}^{k} {\binom{n}{x}} p^x (1-p)^{n-x} \] Compute \( P(X \leq 21) \) and subtract from 1 for the result.
03

Compute P(X = 22) for Part b

We need to find \( P(X = 22) \). Use the binomial probability formula: \[ P(X = 22) = {\binom{25}{22}} (0.8)^{22} (0.2)^{3} \] Calculate using the formula to find the exact probability of 22 successes.
04

Conclusion for Part c

Evaluate whether the probability found in part a is significant. If \( P(X \geq 22) \) is very low, it suggests that the commissioner's claim might not be correct as getting 22 or more is unlikely under the binomial assumption. However, if it is reasonably high, this supports the claim.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculation when dealing with a binomial distribution involves finding the likelihood of a given number of "successes" in a series of independent trials. In this exercise, we are analyzing a situation where residents of a city preferred a private garbage collection company. We want to calculate specific probabilities based on the commissioner's claim that 80% of people prefer this option.

### Understanding the ParametersRecognize this as a binomial experiment. Here:
  • Number of trials () is 25, representing the sampled residents.
  • Probability of success (p) is 0.8, as per the commissioner's claim.
Next, use these to calculate probabilities for specific scenarios, such as having exactly or at least a certain number of residents indicating a preference for private contracting.

### Calculating Specific ProbabilitiesTwo primary formulas are at play:
  • Exact Probability Formula: \[ P(X = k) = {\binom{n}{k}} p^k (1-p)^{n-k} \] calculates the probability of exactly k successes.
  • Cumulative Probability Formula: \[ P(X \geq k) = 1 - P(X \leq k-1) \] helps find the probability of getting at least k successes.
Apply these tools to see how "at least 22" or "exactly 22" preferences manifest in terms of probabilities.
Statistical Claims Testing
Statistical claims testing helps us verify or challenge claims made about a population. In this case, the commissioner's assertion that 80% of residents favor a private garbage company is under scrutiny. The aim is to test this claim using sample data and statistical tools.

### Hypothesis Testing Basics To understand if the commissioner's statement holds:
  • Null Hypothesis (H0): This assumes the claim is true, i.e., 80% prefer privatization.
  • Alternative Hypothesis (H1): This suggests the claim is false, indicating a different preference rate.
Using the binomial distribution and accumulated sample data, calculate the relevant probabilities to find if the observed data (22 out of 25) aligns well with the commissioner's claim.

### Evaluating Outcomes If the calculated probability, that at least 22 rather than 80% prefer privatization, turns out significantly low, it might indicate the claim is not true. The conclusion depends on the significance level (often 5% ) and whether the observed data lies within typical expectations of the binomial distribution.
Cumulative Probability
Cumulative probability is a powerful concept in probability theory, especially useful when dealing with the binomial distribution. It represents the probability that a random variable takes on a value less than or equal to a specific number, integrating over all possible outcomes at once.

### Computing Cumulative ProbabilityTo find cumulative probabilities using a binomial distribution, consider calculating \( P(X \leq k) \), the sum of the probabilities of all possible success counts up to \( k \) successes:\[ P(X \leq k) = \sum_{x=0}^{k} {\binom{n}{x}} p^x (1-p)^{n-x} \]This calculation often forms the basis for obtaining probabilities such as \( P(X \geq 22) \) by subtracting the cumulative probability through a complement approach:

\[ P(X \geq k) = 1 - P(X \leq k-1) \]

### Application in Testing ClaimsBy evaluating cumulative probabilities, assess how rare the observed outcome (22 or more successes in our scenario) is. It's crucial in verifying if deviations from expected outcomes (under the claim) could be attributed to random chance or if they suggest discrepancies in the claim itself.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Goranson and Hall (1980) explain that the probability of detecting a crack in an airplane wing is the product of \(p_{1},\) the probability of inspecting a plane with a wing crack; \(p_{2},\) the probability of inspecting the detail in which the crack is located; and \(p_{3}\), the probability of detecting the damage. a. What assumptions justify the multiplication of these probabilities? b. Suppose \(p_{1}=.9, p_{2}=.8,\) and \(p_{3}=.5\) for a certain fleet of planes. If three planes are inspected from this fleet, find the probability that a wing crack will be detected on at least one of them.

For a certain section of a pine forest, the number of diseased trees per acre, \(Y\), has a Poisson distribution with mean \(\lambda=10 .\) The diseased trees are sprayed with an insecticide at a cost of \(\$ 3\) per tree, plus a fixed overhead cost for equipment rental of \(\$ 50\). Letting \(C\) denote the total spraying cost for a randomly selected acre, find the expected value and standard deviation for \(C\). Within what interval would you expect \(C\) to lie with probability at least. \(75 ?\)

One model for plant competition assumes that there is a zone of resource depletion around each plant seedling. Depending on the size of the zones and the density of the plants, the zones of resource depletion may overlap with those of other seedlings in the vicinity. When the seeds are randomly dispersed over a wide area, the number of neighbors that any seedling has within an area of size \(A\) usually follows a Poisson distribution with mean equal to \(A \times d,\) where \(d\) is the density of seedlings per unit area. Suppose that the density of seedlings is four per square meter. What is the probability that a specified seeding has a. no neighbors within 1 meter? b. at most three neighbors within 2 meters?

If \(Y\) has a geometric distribution with probability of success \(p\), show that the moment-generating function for \(Y\) is $$m(t)=\frac{p e^{t}}{1-q e^{t}}, \quad \text { where } q=1-p$$.

A new surgical procedure is successful with a probability of \(p\). Assume that the operation is performed five times and the results are independent of one another. What is the probability that a. all five operations are successful if \(p=.8 ?\) b. exactly four are successful if \(p=.6 ?\) c. less than two are successful if \(p=.3 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.