/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 131 The number of knots in a particu... [FREE SOLUTION] | 91Ó°ÊÓ

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The number of knots in a particular type of wood has a Poisson distribution with an average of 1.5 knots in 10 cubic feet of the wood. Find the probability that a 10 -cubic-foot block of the wood has at most 1 knot.

Short Answer

Expert verified
The probability is approximately 0.5578.

Step by step solution

01

Understand the Problem

We know that the number of knots follows a Poisson distribution with an average (rate parameter) of \( \lambda = 1.5 \) knots per 10 cubic feet of wood. We need to find the probability that there are at most 1 knot in a 10 cubic-foot block of wood.
02

Poisson Probability Formula

The probability mass function for a Poisson distribution is given by: \( P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!} \) where \( X \) is the Poisson random variable, \( \lambda \) is the average rate, \( k \) is the number of occurrences, and \( e \) is the base of the natural logarithm.
03

Compute Probability for 0 Knots

For \( k = 0 \) (0 knots), we use the formula: \[ P(X = 0) = \frac{e^{-1.5} \times 1.5^0}{0!} = e^{-1.5} \] Calculate this value to find the probability of having 0 knots.
04

Compute Probability for 1 Knot

For \( k = 1 \) (1 knot), we use the formula: \[ P(X = 1) = \frac{e^{-1.5} \times 1.5^1}{1!} = e^{-1.5} \times 1.5 \] Calculate this value to find the probability of having exactly 1 knot.
05

Combine Probabilities for 0 and 1 Knots

Since we want the probability of having "at most 1 knot", we sum the probabilities for 0 knots and 1 knot: \[ P(X \leq 1) = P(X = 0) + P(X = 1) \]
06

Calculate Final Probability

First, compute \( e^{-1.5} \). Then find: \( P(X = 0) = e^{-1.5} \) and \( P(X = 1) = e^{-1.5} \times 1.5 \). Add these values to get the probability that there are at most 1 knot.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Mass Function
Poisson distribution is a key concept in probability and statistics, especially when dealing with counts or occurrences over a fixed interval. An essential part of it is the probability mass function (PMF), which helps us determine probabilities of specific events. For a Poisson distribution, the PMF is defined by the formula:
  • \( P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!} \),

where each symbol has its own meaning.
  • \( X \) is the Poisson random variable signifying the number of events occurring.
  • \( k \) represents the number of occurrences you are interested in finding the probability for.
  • \( \lambda \) is the rate parameter or average number of occurrences.
  • \( e \) is the base of the natural logarithm, approximately equal to 2.71828.

This formula is beautiful and efficient because it gives us a direct way to compute the likelihood of a given number of events happening in a defined space or time period, as seen in the case of discovering the number of knots in wood.
Probability Calculation
Calculating probabilities using the Poisson distribution's PMF involves a few straightforward steps. In the context of our example with knots in wood, let's look at how you would perform these calculations.The primary goal is to find the probability of having at most 1 knot in the wood. So, we need to compute the probabilities for both 0 knots and 1 knot using the PMF formula:
  • For 0 knots (\( k = 0 \)), the probability is given by: \[ P(X = 0) = \frac{e^{-1.5} \times 1.5^0}{0!} = e^{-1.5} \]
  • For 1 knot (\( k = 1 \)), the probability is: \[ P(X = 1) = \frac{e^{-1.5} \times 1.5^1}{1!} = e^{-1.5} \times 1.5 \]

It is also crucial to remember that calculating these requires the value of \( e^{-\lambda} \), which in this case is \( e^{-1.5} \).
Once these probabilities are calculated, the sum of probabilities for 0 and 1 knot gives us the desired result:
  • \[ P(X \leq 1) = P(X = 0) + P(X = 1) \]

This step-by-step approach ensures that you accurately and reliably calculate the probability of specific outcomes.
Rate Parameter
The rate parameter \( \lambda \) in the context of the Poisson distribution is vital for understanding the distribution's behavior. It represents the average rate or number of occurrences of the event within the specified interval. In our problem, \( \lambda = 1.5 \), indicating an average of 1.5 knots in every 10 cubic feet of wood.Why is the rate parameter important?
  • It determines the shape and characteristics of the distribution. A higher value of \( \lambda \) points towards a higher average number of events, which affects the spread and variability of the data.
  • It directly impacts the PMF calculation as it appears in both the exponential and multiplicative terms of the formula.
  • Understanding \( \lambda \) helps in setting realistic expectations for variability in observations and can be used for planning and predictive purposes in different fields.

When working with Poisson-reliant processes, accurately defining \( \lambda \) provides a powerful way to model and assess future occurrences based on past averages. Thus, it is a fundamental aspect of not only solving statistical problems but also interpreting real-world random events effectively.

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