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If \(P(A)>0, P(B)>0,\) and \(P(A)

Short Answer

Expert verified
Given the conditions, it follows from the definition of conditional probabilities that \( P(B) < P(B | A) \).

Step by step solution

01

Understand the Given Information

We are given three conditions: 1. The probability of event A is greater than zero: \( P(A) > 0 \).2. The probability of event B is also greater than zero: \( P(B) > 0 \).3. The probability of event A is less than the probability of event A given B: \( P(A) < P(A | B) \). Our task is to show that the probability of event B is less than the probability of event B given A: \( P(B) < P(B | A) \).
02

Recall the Definition of Conditional Probability

The conditional probability of A given B is defined as:\[ P(A | B) = \frac{P(A \cap B)}{P(B)} \]Similarly, the conditional probability of B given A is:\[ P(B | A) = \frac{P(B \cap A)}{P(A)} \]Remember that \( P(A \cap B) = P(B \cap A) \) since intersection is commutative.
03

Translate Conditions into Formulae

From \( P(A) < P(A | B) \), we can rewrite using the definition of conditional probability:\[ P(A) < \frac{P(A \cap B)}{P(B)} \].
04

Simplify the Condition \( P(A) < \frac{P(A \cap B)}{P(B)} \)

Multiply both sides by \( P(B) \) (since \( P(B) > 0 \)):\[ P(A) \cdot P(B) < P(A \cap B) \].
05

Rewrite \( P(B | A) \) Using Known Quantities

Using the definition of conditional probability:\[ P(B | A) = \frac{P(A \cap B)}{P(A)} \].
06

Show \( P(B) < P(B | A) \)

From Step 4, we have \( P(A) \cdot P(B) < P(A \cap B) \). Divide both sides by \( P(A) \):\[ P(B) < \frac{P(A \cap B)}{P(A)} = P(B | A) \].This shows \( P(B) < P(B | A) \), as required.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intersection of Events
The intersection of events is a fundamental concept in probability theory.
It refers to the event where two or more events occur simultaneously.
In mathematical terms, the intersection of events \( A \) and \( B \) is denoted by \( A \cap B \).
This represents the set of outcomes that are common to both events.
  • If you roll two dice and want both to show a three, the intersection includes just this outcome.
  • Understanding intersection is key to calculating probabilities where events are not mutually exclusive.
Knowing this allows us to express conditional probabilities, such as \( P(A | B) = \frac{P(A \cap B)}{P(B)} \), where the probability of \( A \), given \( B \), depends on the intersection \( A \cap B \).
Remember, since intersection is commutative, \( P(A \cap B) \) is the same as \( P(B \cap A) \).
The principle behind intersection is crucial in defining relationships between events in probability, especially when exploring dependencies.
Probability Inequalities
Probability inequalities provide insights into how probabilities of events compare with one another.
One important principle is that conditional probabilities can reveal inequalities when comparing through information about dependence between events.
  • For example, if \( P(A) < P(A | B) \), it implies an inequality that would generally suggest \( B \) impacts the likelihood of \( A \).
  • This inequality suggests that the event \( A \) is more likely to occur given \( B \) has occurred than by itself.
  • The conclusion from such inequalities helps us conclude similar inequalities for other event comparisons.
When progressing through exercises, inequalities are pivotal for solving practical problems.
In the original problem, the inequality \( P(B) < P(B | A) \) revealed how informative dependencies between events can be.
This was derived using the previously established inequality for \( A \) and serves as a great tool for logical deduction in probability.
Probability Theory
Probability theory is the branch of mathematics that deals with analyzing random phenomena.
It provides a framework for quantifying the likelihood of different events, whether they are random or unpredictable.
  • Core concepts include the probability of events, sample spaces, and probability distributions.
  • Conditional probability is where one event's occurrence influences the probability of another event.
  • This is a critical teaching in our exercise where we compare simple and conditional probabilities to derive meaningful inequalities.
Understanding probability theory helps us quantify uncertainty in real life.
When it comes to situations where we are interested in both simple probabilities \( P(A) \) or \( P(B) \), and conditional probabilities \( P(A|B) \) or \( P(B|A) \), probability theory provides the tools to manipulate and understand such complex situations.
By arranging these calculations into inequalities or logical deductions, like in our exercise, we can derive powerful insights into event relationships.

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Most popular questions from this chapter

If \(A\) and \(B\) are mutually exclusive events and \(P(B)>0\), show that $$P(A | A \cup B)=\frac{P(A)}{P(A)+P(B)}$$.

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