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Suppose that we wish to expand \((x+y+z)^{17} .\) What is the coefficient of \(x^{2} y^{5} z^{10} ?\)

Short Answer

Expert verified
The coefficient of \(x^2 y^5 z^{10}\) is 27,907.

Step by step solution

01

Identify the Problem

We need to find the coefficient of the term \(x^{2} y^{5} z^{10}\) in the expansion of \((x+y+z)^{17}\).
02

Apply Multinomial Theorem

We use the multinomial theorem, which states that the expansion of \((x_1 + x_2 + \cdots + x_m)^n\) is the sum of terms like \(\frac{n!}{k_1! k_2! \cdots k_m!} x_1^{k_1} x_2^{k_2} \cdots x_m^{k_m}\), where \(k_1 + k_2 + \cdots + k_m = n\).
03

Assign Values

For \((x+y+z)^{17}\), we want the term \(x^{2} y^{5} z^{10}\). So \(k_1 = 2\), \(k_2 = 5\), \(k_3 = 10\).
04

Calculate Factorials

We calculate the factorials required for the formula: \(17!\), \(2!\), \(5!\), and \(10!\).
05

Apply Coefficient Formula

Use the formula to determine the coefficient: \(\frac{17!}{2! 5! 10!}\).
06

Compute Numerical Result

Calculate the factorial values: \(17! = 355687428096000\), \(2! = 2\), \(5! = 120\), and \(10! = 3628800\), then \(\frac{355687428096000}{2 \times 120 \times 3628800} = 27,907 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Expansion
The concept of binomial expansion is fundamental when working with polynomials raised to a power. In our exercise, while the term is multinomial, which applies to three or more terms, understanding the binomial theorem helps to simplify such general expressions. Binomial expansion is based on expanding (a + b)^n, making it a sum of terms in the form:
  • \[ \frac{n!}{k!(n-k)!} a^{n-k} b^k \]
This involves using coefficients and factorial calculations to determine each term in the expression. For a simple binomial like (x+y)^n, it forms a sequence of terms that increment the power of y while decrementing the power of x, resulting in a clear pattern. In our problem (x+y+z)^{17}, the expansion is extended beyond just two elements. The role of the multinomial theorem, which uses similar principles, becomes crucial here.
Understanding this process helps students predict and determine the specific term coefficients without directly expanding the entire expression which can be cumbersome for higher powers.
Coefficient
Coefficients play a critical role in polynomial expansions by determining the weight of each term in the expansion. These numbers give insight into how each variable component contributes to the overall polynomial expression. In the multinomial theorem, the coefficient of a specific term is calculated using:
  • \[ \frac{n!}{k_1!k_2! \cdots k_m!} \]
Here, \(n\) is the total power of the polynomial, and \(k_1, k_2, \ldots, k_m\) are the exponents of each variable ensuring they sum to \(n\). So for (x+y+z)^{17}, to find the coefficient of x^2y^5z^{10}, assign \(k_1=2\), \(k_2=5\), \(k_3=10\). With the factorials calculated, the coefficient tells us how many times the term x^2y^5z^{10} appears in the expanded form of the polynomial.
The computation gives a dominantly numerical result, simplifying the task of polynomial expansion. By understanding coefficients, students can confidently approach similar problems by computationally deciding term values effectively.
Factorials
Factorials are pivotal when calculating the coefficients in a polynomial expansion using the multinomial theorem. The factorial of a non-negative integer \(n\), denoted as \(n!\), is the product of all positive integers less than or equal to \(n\). This is a crucial part of determining the number of ways elements can be arranged, which translates to the coefficients in polynomial expansions.
For instance, in calculating the term coefficient of x^2y^5z^{10} in the expansion of (x+y+z)^{17}, the factorials involved are \(17!\), \(2!\), \(5!\), \(10!\). These factorials are used in \(\frac{17!}{2! 5! 10!}\) to determine how many combinations of arranging 2 x's, 5 y's, and 10 z's exist among the 17 different slots.
Understanding factorials allows students to better grasp the quantitative nature of polynomial coefficients, enhancing their problem-solving skills not just in algebra but also in combinatorics and probability.

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