/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 92 Utility companies, which must pl... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Utility companies, which must plan the operation and expansion of electricity generation, are vitally interested in predicting customer demand over both short and long periods of time. A short-term study was conducted to investigate the effect of each month's mean daily temperature \(x_{1}\) and of cost per kilowatt-hour, \(x_{2}\) on the mean daily consumption (in \(\mathrm{kWh}\) ) per household. The company officials expected the demand for electricity to rise in cold weather (due to heating), fall when the weather was moderate, and rise again when the temperature rose and there was a need for air conditioning. They expected demand to decrease as the cost per kilowatt-hour increased, reflecting greater attention to conservation. Data were available for 2 years, a period during which the cost per kilowatt-hour \(x_{2}\) increased due to the increasing costs of fuel. The company officials fitted the model $$Y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{1}^{2}+\beta_{3} x_{2}+\beta_{4} x_{1} x_{2}+\beta_{5} x_{1}^{2} x_{2}+\varepsilon$$ to the data in the following table and obtained \(\hat{y}=325.606-11.383 x_{1}+.113 x_{1}^{2}-21.699 x_{2}+.873 x_{1} x_{2}-.009 x_{1}^{2} x_{2}\) with \(\mathrm{SSE}=152.177\) When the model \(Y=\beta_{0}-\beta_{1} x_{1}+\beta_{2} x_{1}^{2}+\varepsilon\) was fit, the prediction equation was \(\hat{y}=130.009-3.302 x_{1}+.033 x_{1}^{2}\) with \(\mathrm{SSE}=465.134 .\) Test whether the terms involving \(x_{2}\left(x_{2}, x_{1} x_{2}, x_{1}^{2} x_{2}\right)\) contribute to a significantly better fit of the model to the data. Give bounds for the attained significance level.

Short Answer

Expert verified
Test if terms involving \(x_2\) improve model by using F-test; calculate F-value, determine significance.

Step by step solution

01

State Hypotheses

We want to test whether the terms involving \(x_2\) significantly improve the model. The null hypothesis \(H_0\) is that the coefficients of \(x_2, x_1 x_2, x_1^2 x_2\) are zero. The alternative hypothesis \(H_a\) is that at least one of these coefficients is not zero.
02

Determine Test Statistic

We use the F-test to compare the two models. The test statistic is given by \[ F = \frac{(SSER - SSEF) / (df_R - df_F)}{SSEF / df_F} \] where \(SSER\) is the sum of squared errors for the reduced model, \(SSEF\) is the sum for the full model, \(df_R\) is the degrees of freedom for the reduced model, and \(df_F\) for the full model.
03

Calculate SSE and Degrees of Freedom

From the problem, \(SSER = 465.134\) and \(SSEF = 152.177\). The full model has 6 parameters (including the intercept), and the reduced model has 3 parameters. Assuming the use of the same number of observations \(n\), the degrees of freedom are \(df_R = n - 3\) and \(df_F = n - 6\).
04

Compute F-statistic

Substitute the given values into the F-statistic formula:\[ F = \frac{(465.134 - 152.177) / (3)}{152.177 / (n - 6)} \]This can be simplified further once \(n\) (the number of observations) is known.
05

Determine Significance

With the calculated \(F\)-value, consult the \(F\)-distribution table to find the \(p\)-value using the degrees of freedom \((3, n-6)\). This tells us the significance level.
06

Make a Conclusion

If the \(p\)-value is less than the significance level (often 0.05), we reject the null hypothesis. If it is greater, we fail to reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Multiple Regression Analysis
Multiple regression analysis is a statistical method used to understand relationships among multiple variables. In this exercise, the utility company wants to predict electricity consumption based on various factors. Here, the dependent variable (the outcome we want to predict) is the mean daily consumption of electricity per household. On the other hand, the independent variables are the mean daily temperature, both linear and quadratic terms
  • Linear term: Temperature (\[x_1\])
  • Quadratic term: Temperature squared (\[x_1^2\])
  • Cost per kilowatt-hour (\[x_2\])
  • Interaction terms (\[x_1 \times x_2\], and \[x_1^2 \times x_2\])
These components construct a model that tries to predict how the electricity demand changes under different temperatures and costs. This model is essential for companies to plan their operations efficiently and make informed decisions about future electricity generation needs.
F-Test
The F-test is a statistical test used in this context to compare two competing models to see if the more complex model (with more variables) provides a significantly better prediction of the dependent variable.
The null hypothesis (\[H_0\]) in this scenario assumes that the additional variables \[x_2, x_1 x_2, x_1^2 x_2\] do not improve the model fit. The alternative hypothesis (\[H_a\]) suggests that at least one of these terms does improve the model.
The test statistic in the F-test is calculated using the formula: \[ F = \frac{(SSER - SSEF) / (df_R - df_F)}{SSEF / df_F} \]where
  • \[SSER\] is the sum of squared errors for the reduced model
  • \[SSEF\] is the sum for the full model
  • \[df_R\] represents the degrees of freedom for the reduced model
  • \[df_F\] for the full model
This statistical test is crucial in evaluating whether incorporating extra terms in the model significantly improves its predictive capability.
Model Comparison
Model comparison is vital to determine which statistical model fits the data better. In this exercise, the objective is to evaluate if including terms related to the cost per kilowatt-hour \[x_2\] and its interactions with temperature leads to a more accurate prediction of electricity consumption.
The first model only considers temperature (\[x_1\] and \[x_1^2\]), while the second, more comprehensive model, incorporates \[x_2\] and the interaction terms (\[x_1 \times x_2\], and \[x_1^2 \times x_2\]).
The balance between model complexity and accuracy is essential. A model with too many parameters may fit the current data very well but perform poorly on new data—a phenomenon known as overfitting. Conversely, a simpler model may not capture all underlying patterns.
Using the F-test, students compare these models by calculating the F-statistic and checking its significance against established criteria (like the p-value threshold of 0.05). This process helps determine if the additional variables genuinely contribute valuable information to the model's predictions.

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Most popular questions from this chapter

The following model was proposed for testing whether there was evidence of salary discrimination against women in a state university system: $$Y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\beta_{3} x_{1} x_{2}+\beta_{4} x_{2}^{2}+\varepsilon$$,where \(Y=\) annual salary (in thousands of dollars), \(x_{1}=\left\\{\begin{array}{ll}1, & \text { if female } \\ 0, & \text { if male }\end{array}\right.\) \(x_{2}=\) amount of experience (in years).When this model was fit to data obtained from the records of 200 faculty members, \(\mathrm{SSE}=783.90\). The reduced model \(Y=\beta_{0}+\beta_{1} x_{2}+\beta_{2} x_{2}^{2}+\varepsilon\) was also fit and produced a value of \(\mathrm{SSE}=795.23 .\) Do the data provide sufficient evidence to support the claim that the mean salary depends on the gender of the faculty members? Use \(\alpha=.05\)

Information about eight four-cylinder automobiles judged to be among the most fuel efficient in 2006 is given in the following table. Engine sizes are in total cylinder volume, measured in liters (L). $$\begin{array}{lcc}\text { Car } & \text { Cylinder Volume }(x) & \text { Horsepower }(y) \\\\\hline \text { Honda Civic } & 1.8 & 51 \\ \text { Toyota Prius } & 1.5 & 51 \\\\\text { WW Golf } & 2.0 & 115 \\\\\text { WW Beetle } & 2.5 & 150 \\\\\text { Toyota Corolla } & 1.8 & 126 \\ \text { WW Jetta } & 2.5 & 150 \\\\\text { Mini Cooper } & 1.6 & 118 \\\\\text { Toyota Yaris } & 1.5 & 106\end{array}$$ a. Plot the data points on graph paper. b. Find the least-squares line for the data. c. Graph the least-squares line to see how well it fits the data. d. Use the least-squares line to estimate the mean horsepower rating for a fuel-efficient automobile with cylinder volume \(1.9 \mathrm{L}\).

Television advertising would ideally be aimed at exactly the audience that observes the ads. A study was conducted to determine the amount of time that individuals spend watching TV during evening prime-time hours. Twenty individuals were observed for a 1 -week period, and the average time spent watching TV per evening, \(Y\), was recorded for each. Four other bits of information were also recorded for each individual: \(x_{1}=\) age, \(x_{2}=\) education level, \(x_{3}=\) disposable income, and \(x_{4}=\) IQ. Consider the three models given below: Model I: $$Y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\beta_{3} x_{3}+\beta_{4} x_{4}+\varepsilon$$ Model II: $$Y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\varepsilon$$ Model III: $$Y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\beta_{3} x_{1} x_{2}+\varepsilon$$ Are the following statements true or false? a. If Model I is fit, the estimate for \(\sigma^{2}\) is based on 16 df. b. If Model II is fit, we can perform a \(t\) test to determine whether \(x_{2}\) contributes to a better fit of the model to the data. c. If Models I and II are both fit, then \(\mathrm{SSE}_{\mathrm{I}} \leq \mathrm{SSE}_{\mathrm{II}}\) d. If Models I and II are fit, then \(\hat{\sigma}_{1}^{2} \leq \widehat{\sigma}_{\Pi}^{2}\). e. Model II is a reduction of model I. f. Models I and III can be compared using the complete/reduced model technique presented in Section 11.14.

A study was conducted to determine the effects of sleep deprivation on subjects' ability to solve simple problems. The amount of sleep deprivation varied over \(8,12,16,20,\) and 24 hours without sleep. A total of ten subjects participated in the study, two at each sleep-deprivation level. After his or her specified sleep-deprivation period, each subject was administered a set of simple addition problems, and the number of errors was recorded. The results shown in the following table were obtained. $$\begin{array}{l|ccccc}\text { Number of Errors }(y) & 8,6 & 6,10 & 8,14 & 14,12 & 16,12 \\\\\hline \text { Number of Hours without Sleep }(x) & 8 & 12 & 16 & 20 & 24\end{array}$$ a. Find the least-squares line appropriate to these data. b. Plot the points and graph the least-squares line as a check on your calculations. c. Calculate \(S^{2}\).

The results that follow were obtained from an analysis of data obtained in a study to assess the relationship between percent increase in yield ( \(Y\) ) and base saturation \(\left(x_{1},\) pounds/acre). \right. phosphate saturation \(\left(x_{2}, \mathrm{BEC} \%\right),\) and soil \(\mathrm{pH}\left(x_{3}\right) .\) Fifteen responses were analyzed in the study. The least-squares equation and other useful information follow. $$\hat{y}=38.83-0.0092 x_{1}-0.92 x_{2}+11.56 x_{3}, \quad S_{y y}=10965.46, \quad \mathrm{SSE}=1107.01$$ $$10^{4}\left(\mathbf{X}^{\prime} \mathbf{X}\right)^{-1}=\left[\begin{array}{cccc} 151401.8 & 2.6 & 100.5 & -28082.9 \\ 2.6 & 1.0 & 0.0 & 0.4 \\ 100.5 & 0.0 & 8.1 & 5.2 \\ -28082.9 & 0.4 & 5.2 & 6038.2 \end{array}\right]$$ a. Is there sufficient evidence that, with all independent variables in the model, \(\beta_{2}<0\) ? Test at the \(\alpha=.05\) level of significance. b. Give a \(95 \%\) confidence interval for the mean percent increase in yield if \(x_{1}=914, x_{2}=65\) and \(x_{3}=6\)

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