/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 107 The data in the following table ... [FREE SOLUTION] | 91Ó°ÊÓ

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The data in the following table give the miles per gallon obtained by a test automobile when using gasolines of varying octane levels.$$\begin{array}{cc} \hline \text { Miles per Gallon }(y) & \text { Octane }(x) \\ \hline 13.0 & 89 \\\13.2 & 93 \\\13.0 & 87 \\\13.6 & 90 \\\13.3 & 89 \\\13.8 & 95 \\\14.1 & 100 \\\14.0 & 98\\\\\hline\end{array}$$a. Calculate the value of \(r\). b. Do the data provide sufficient evidence to indicate that octane level and miles per gallon are dependent? Give the attained significance level, and indicate your conclusion if you wish to implement an \(\alpha=.05\) level test.

Short Answer

Expert verified
Calculate means, compute correlation \(r\), test hypothesis at \(\alpha = 0.05\). Dependent if \(r\) is significant.

Step by step solution

01

Calculate the Means

First, we calculate the means of the miles per gallon \((\bar{y})\) and the octane levels \((\bar{x})\).\(\bar{y} = \frac{13.0 + 13.2 + 13.0 + 13.6 + 13.3 + 13.8 + 14.1 + 14.0}{8} = 13.5\)\(\bar{x} = \frac{89 + 93 + 87 + 90 + 89 + 95 + 100 + 98}{8} = 92.625\)
02

Calculate the Sum of Products

Calculate the sum of the products \(\Sigma (x - \bar{x})(y - \bar{y})\) and the sums of the squares \(\Sigma (x - \bar{x})^2\) and \(\Sigma (y - \bar{y})^2\).\[\Sigma (x - \bar{x})(y - \bar{y}) = (89 - 92.625)(13.0 - 13.5) + (93 - 92.625)(13.2 - 13.5) + \ldots + (98 - 92.625)(14.0 - 13.5)\]Calculate the complete expressions step by step.
03

Compute the Correlation Coefficient \(r\)

Use the formulas derived from Step 2 to compute the correlation coefficient \(r\):\[r = \frac{\Sigma (x - \bar{x})(y - \bar{y})}{\sqrt{\Sigma (x - \bar{x})^2 \cdot \Sigma (y - \bar{y})^2}}\]
04

Test the Null Hypothesis

State the null hypothesis \(H_0\): There is no correlation. Calculate the t-value using:\[t = \frac{r \sqrt{n-2}}{\sqrt{1-r^2}}\]Compare the calculated t-value with the critical t-value for \(\alpha = 0.05\) with \(n - 2 = 6\) degrees of freedom from the t-distribution table.
05

Conclusion

If the absolute value of the calculated t-value is greater than the critical t-value from the table, reject the null hypothesis. Otherwise, do not reject it. Based on the correlation found and the significance level, conclude whether or not octane level and miles per gallon are dependent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a statistical method used to make decisions or draw conclusions about a population based on sample data. It's a way to test an assumption or claim about a parameter, such as a mean or percentage, using a structured approach.

In the context of our exercise, we are testing whether the octane level of gasoline is related to the miles per gallon achieved by a test car. This involves stating two hypotheses:
  • The null hypothesis (\( H_0 \)) assumes there is no relationship between the variables. Here, it would mean that octane level does not affect fuel efficiency.
  • The alternative hypothesis (\( H_a \)) suggests a relationship does exist, implying octane levels do affect the fuel efficiency.
By calculating a test statistic (like a t-value) and comparing this to a critical value from a statistical table, we can decide whether to reject the null hypothesis in favor of the alternative, or not reject it, based on the sample data we have.
Significance Level
The significance level, denoted as \( \alpha \), is the threshold for determining whether a hypothesis test's result is statistically significant. It's the probability of rejecting the null hypothesis when it is actually true—a risk of making a Type I error.

Common significance levels include 0.05, 0.01, and 0.10, with 0.05 often used as a standard. This value represents a 5% risk.
In our example, an \( \alpha \) level of 0.05 is used. It means that if the calculated p-value (the probability of observing the test results under the null) is less than 0.05, the null hypothesis is rejected, concluding that there is significant evidence that octane level and miles per gallon are related. Alternatively, if the p-value is greater than 0.05, we do not reject the null hypothesis, suggesting there isn't enough evidence to affirm the fuel efficiency's dependence on the octane level.
Linear Regression
Linear regression is a statistical method used to model the relationship between two variables by fitting a linear equation to observed data. The simplest form is the line of best fit: \( y = mx + c \), where \( m \) is the slope and \( c \) is the intercept. This equation describes how the dependent variable (e.g., miles per gallon) changes with respect to the independent variable (e.g., octane level).

The slope, \( m \), indicates the change in the dependent variable for a one-unit increase in the independent variable. A positive \( m \) suggests a direct relationship, while a negative \( m \) implies an inverse relationship.

Linear regression helps quantify the strength of this relationship and is often used alongside the calculation of a correlation coefficient. By presenting a visual trend and quantifying changes, linear regression provides a clear analytical tool for assessing how two variables might relate.
Correlated Variables
When two variables are correlated, it means they tend to vary together in a predictable way. Correlation measures the strength and direction of a linear relationship between them.

The correlation coefficient, \( r \), ranges from -1 to 1:
  • A value of 1 indicates a perfect positive correlation, meaning as one variable increases, the other does, too.
  • A value of -1 indicates a perfect negative correlation, where one variable increases as the other decreases.
  • A value of 0 suggests no linear correlation between the variables.
In the example of miles per gallon versus octane level, calculating \( r \) helps determine how closely these two are related. A strong positive \( r \) would imply better fuel efficiency with higher octane levels, while a strong negative or weak \( r \) would suggest otherwise.

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Most popular questions from this chapter

Television advertising would ideally be aimed at exactly the audience that observes the ads. A study was conducted to determine the amount of time that individuals spend watching TV during evening prime-time hours. Twenty individuals were observed for a 1 -week period, and the average time spent watching TV per evening, \(Y\), was recorded for each. Four other bits of information were also recorded for each individual: \(x_{1}=\) age, \(x_{2}=\) education level, \(x_{3}=\) disposable income, and \(x_{4}=\) IQ. Consider the three models given below: Model I: $$Y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\beta_{3} x_{3}+\beta_{4} x_{4}+\varepsilon$$ Model II: $$Y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\varepsilon$$ Model III: $$Y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\beta_{3} x_{1} x_{2}+\varepsilon$$ Are the following statements true or false? a. If Model I is fit, the estimate for \(\sigma^{2}\) is based on 16 df. b. If Model II is fit, we can perform a \(t\) test to determine whether \(x_{2}\) contributes to a better fit of the model to the data. c. If Models I and II are both fit, then \(\mathrm{SSE}_{\mathrm{I}} \leq \mathrm{SSE}_{\mathrm{II}}\) d. If Models I and II are fit, then \(\hat{\sigma}_{1}^{2} \leq \widehat{\sigma}_{\Pi}^{2}\). e. Model II is a reduction of model I. f. Models I and III can be compared using the complete/reduced model technique presented in Section 11.14.

The results that follow were obtained from an analysis of data obtained in a study to assess the relationship between percent increase in yield ( \(Y\) ) and base saturation \(\left(x_{1},\) pounds/acre). \right. phosphate saturation \(\left(x_{2}, \mathrm{BEC} \%\right),\) and soil \(\mathrm{pH}\left(x_{3}\right) .\) Fifteen responses were analyzed in the study. The least-squares equation and other useful information follow. $$\hat{y}=38.83-0.0092 x_{1}-0.92 x_{2}+11.56 x_{3}, \quad S_{y y}=10965.46, \quad \mathrm{SSE}=1107.01$$ $$10^{4}\left(\mathbf{X}^{\prime} \mathbf{X}\right)^{-1}=\left[\begin{array}{cccc} 151401.8 & 2.6 & 100.5 & -28082.9 \\ 2.6 & 1.0 & 0.0 & 0.4 \\ 100.5 & 0.0 & 8.1 & 5.2 \\ -28082.9 & 0.4 & 5.2 & 6038.2 \end{array}\right]$$ a. Is there sufficient evidence that, with all independent variables in the model, \(\beta_{2}<0\) ? Test at the \(\alpha=.05\) level of significance. b. Give a \(95 \%\) confidence interval for the mean percent increase in yield if \(x_{1}=914, x_{2}=65\) and \(x_{3}=6\)

The correlation coefficient for the heights and weights of ten offensive backfield football players was determined to be \(r=.8261\) a. What percentage of the variation in weights was explained by the heights of the players? b. What percentage of the variation in heights was explained by the weights of the players? c. Is there sufficient evidence at the \(\alpha=.01\) level to claim that heights and weights are positively correlated? d. What is the attained significance level associated with the test performed in part (c)?

A study was conducted to determine the effects of sleep deprivation on subjects' ability to solve simple problems. The amount of sleep deprivation varied over \(8,12,16,20,\) and 24 hours without sleep. A total of ten subjects participated in the study, two at each sleep-deprivation level. After his or her specified sleep-deprivation period, each subject was administered a set of simple addition problems, and the number of errors was recorded. The results shown in the following table were obtained. $$\begin{array}{l|ccccc}\text { Number of Errors }(y) & 8,6 & 6,10 & 8,14 & 14,12 & 16,12 \\\\\hline \text { Number of Hours without Sleep }(x) & 8 & 12 & 16 & 20 & 24\end{array}$$ a. Find the least-squares line appropriate to these data. b. Plot the points and graph the least-squares line as a check on your calculations. c. Calculate \(S^{2}\).

Fit a straight line to the five data points in the accompanying table. Give the estimates of \(\beta_{0}\) and \(\beta_{1}\). Plot the points and sketch the fitted line as a check on the calculations. $$\begin{array}{c|ccccc}y & 3.0 & 2.0 & 1.0 & 1.0 & 0.5 \\\\\hline x & -2.0 & -1.0 & 0.0 & 1.0 & 2.0\end{array}$$

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