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Suppose that the null hypothesis is true, that the distribution of the test statistic, \(T\) say, is continuous with cdf \(F\) and that the test rejects for large values of \(T\). Let \(V\) denote the \(p\) -value of the test. a. Show that \(V=1-F(T).\) b. Conclude that the null distribution of \(V\) is uniform. (Hint: See Proposition \(\mathrm{C}\) of Section \(2.3 .)\) c. If the null hypothesis is true, what is the probability that the \(p\) -value is greater than .1? d. Show that the test that rejects if \(V<\alpha\) has significance level \(\alpha .\)

Short Answer

Expert verified
a. \( V = 1 - F(T) \). b. \( V \) is uniformly distributed under the null. c. Probability is 0.9. d. Significance level is \( \alpha \).

Step by step solution

01

Understanding the Hypothesis

We need to understand that under the null hypothesis, we have a continuous cumulative distribution function (cdf) given by \( F \), and we reject the hypothesis for large values of the test statistic \( T \). The \( p \)-value \( V \) is the probability of observing a value as extreme as or more extreme than \( T \).
02

Derive the Expression for V

Since the test rejects for large values of \( T \) and under the null hypothesis \( F \) is the cdf of \( T \), then the \( p \)-value \( V \) can be defined as the probability that the test statistic is observed at least as extreme as \( T \), given by \( V = 1 - F(T) \).
03

Show the Distribution of V

Under the null hypothesis, the distribution of the \( p \)-value \( V = 1 - F(T) \) is uniformly distributed over \([0, 1]\). This results because for any given value \( v \) in this interval, the chance \( P(V \leq v) \) equals \( v \), satisfying the characteristics of a uniform distribution.
04

Probability that V is Greater than 0.1

To find the probability that \( V > 0.1 \), we calculate \( P(V > 0.1) = 1 - P(V \leq 0.1) \). Because \( V \) is uniformly distributed, \( P(V \leq 0.1) = 0.1 \). Thus, \( P(V > 0.1) = 1 - 0.1 = 0.9 \).
05

Significance Level of the Test

If the null hypothesis is true, a test that rejects when \( V < \alpha \) can be shown to have a significance level of \( \alpha \). This is because \( P(V < \alpha) = \alpha \) as a property of the uniform distribution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis is a fundamental concept in hypothesis testing. It represents a statement or position that there is no effect or no difference in a population relative to a certain condition. Typically, it's assumed to be true unless evidence suggests otherwise. When conducting a hypothesis test, we collect data and analyze it to determine whether there is enough evidence to reject the null hypothesis. Rejecting it suggests that there might be a significant effect or difference. However, failing to reject the null hypothesis doesn't prove it's true; it simply indicates lack of evidence against it. In statistical terms, it usually takes the form of equalities, such as the mean of a population being equal to a specified value.
P-value
The p-value is an integral part of hypothesis testing. It represents the probability of observing a test statistic as extreme as, or more extreme than, what was actually observed, assuming that the null hypothesis is true. The smaller the p-value, the stronger the evidence against the null hypothesis.
The p-value helps us decide whether to reject the null hypothesis. A commonly used threshold is 0.05. If the p-value is less than or equal to this threshold, we reject the null hypothesis. Otherwise, we do not reject it. A very small p-value indicates unlikely outcomes under the null hypothesis, thus suggesting alternative explanations might be more appropriate.
Cumulative Distribution Function
A cumulative distribution function (CDF) describes the probability that a random variable takes a value less than or equal to a certain number. For a continuous random variable, the CDF ranges from 0 to 1. If you know the CDF of a test statistic under the null hypothesis, you can compute probabilities for ranges of values.
In hypothesis testing, the CDF helps in determining the p-value for a test. For instance, if the CDF at a test statistic value is 0.6, it means there is a 60% probability that the value will be less than or equal to that statistic, under the null hypothesis's assumptions. So, the p-value would be the remaining 40% or 0.4, calculating the likelihood of observing such extremity in data.
Uniform Distribution
Uniform distribution is a type of probability distribution where every outcome is equally likely. In the context of hypothesis testing, the null distribution of p-values is uniform if the null hypothesis is true. This means that any p-value within the interval [0, 1] is equally probable.
  • It simplifies hypothesis testing because calculating probabilities becomes straightforward. For a given threshold \( \alpha \), the probability of a p-value being less than \( \alpha \) when the null hypothesis is true, equals \( \alpha \), just as it does with any point along the interval.
  • This equality helps us set significance levels – thresholds at which we decide to reject the null hypothesis based purely on our willingness to accept a type I error, which is incorrectly rejecting a true null.
Understanding uniform distribution in this context enhances clarity in decision-making around hypothesis tests, particularly in calculating error probabilities.

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Most popular questions from this chapter

Let \(X_{1}, \ldots, X_{25}\) be a sample from a normal distribution having a variance of 100. Find the rejection region for a test at level \(\alpha=.10\) of \(H_{0}: \mu=0\) versus \(H_{A}: \mu=1.5 .\) What is the power of the test? Repeat for \(\alpha=.01.\)

Suppose that a single observation \(X\) is taken from a uniform density on \([0, \theta]\) and consider testing \(H_{0}: \theta=1\) versus \(H_{1}: \theta=2.\) a. Find a test that has significance level \(\alpha=0 .\) What is its power? b. For \(0<\alpha<1,\) consider the test that rejects when \(X \in[0, \alpha] .\) What is its significance level and power? c. What is the significance level and power of the test that rejects when \(X \in\) \([1-\alpha, 1] ?\) d. Find another test that has the same significance level and power as the previous one. e. Does the likelihood ratio test determine a unique rejection region? f. What happens if the null and alternative hypotheses are interchanged \(-H_{0}:\) \(\theta=2\) versus \(H_{1}: \theta=1 ?\)

True or false, and state why: a. The significance level of a statistical test is equal to the probability that the null hypothesis is true. b. If the significance level of a test is decreased, the power would be expected to increase. c. If a test is rejected at the significance level \(\alpha,\) the probability that the null hypothesis is true equals \(\alpha .\) d. The probability that the null hypothesis is falsely rejected is equal to the power of the test. f. A type II error is more serious than a type I error. g. The power of a test is determined by the null distribution of the test statistic. h. The likelihood ratio is a random variable. e. A type I error occurs when the test statistic falls in the rejection region of the test.

True or false: a. The generalized likelihood ratio statistic \(\Lambda\) is always less than or equal to \(1 .\) b. If the \(p\) -value is \(.03,\) the corresponding test will reject at the significance level .02. c. If a test rejects at significance level.06, then the \(p\) -value is less than or equal to .06. d. The \(p\) -value of a test is the probability that the null hypothesis is correct. e. In testing a simple versus simple hypothesis via the likelihood ratio, the \(p\) -value equals the likelihood ratio. f. If a chi-square test statistic with 4 degrees of freedom has a value of \(8.5,\) the \(p\) -value is less than .05.

Let \(X\) be a binomial random variable with \(n\) trials and probability \(p\) of success. a. What is the generalized likelihood ratio for testing \(H_{0}: p=.5\) versus \(H_{A}: p \neq .5 ?\) b. Show that the test rejects for large values of \(|X-n / 2| .\) c. Using the null distribution of \(X,\) show how the significance level corresponding to a rejection region \(|X-n / 2|>k\) can be determined. d. If \(n=10\) and \(k=2,\) what is the significance level of the test? e. Use the normal approximation to the binomial distribution to find the significance level if \(n=100\) and \(k=10.\) This analysis is the basis of the sign test, a typical application of which would be something like this: An experimental drug is to be evaluated on laboratory rats. In \(n\) pairs of litter mates, one animal is given the drug and the other is given a placebo. A physiological measure of benefit is made after some time has passed. Let \(X\) be the number of pairs for which the animal receiving the drug benefited more than its litter mate. A simple model for the distribution of \(X\) if there is no drug effect is binomial with \(p=.5 .\) This is then the null hypothesis that must be made untenable by the data before one could conclude that the drug had an effect.

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