/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Let \(X_{1}, \ldots, X_{n}\) be ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(X_{1}, \ldots, X_{n}\) be random variables with \(\operatorname{Var}\left(X_{i}\right)=\sigma^{2}\) and \(\operatorname{Cov}\left(X_{i}, X_{j}\right)=\) \(\rho \sigma^{2},\) for \(i \neq j .\) Use matrix methods to find \(\operatorname{Var}(\bar{X})\)

Short Answer

Expert verified
\(\operatorname{Var}(\bar{X}) = \frac{\sigma^2}{n}(1 - \rho + \rho n)\).

Step by step solution

01

Express the Sample Mean

The sample mean \( \bar{X} \) of the random variables \( X_1, X_2, \ldots, X_n \) is given by \( \bar{X} = \frac{1}{n} (X_1 + X_2 + \ldots + X_n) \). In matrix form, this can be expressed as \( \bar{X} = \frac{1}{n} \mathbf{1}^T \mathbf{X} \), where \( \mathbf{1} \) is a vector of ones of length \( n \) and \( \mathbf{X} \) is the vector of random variables.
02

Define the Covariance Matrix

The covariance matrix \( \Sigma \) for the random variables \( X_1, X_2, \ldots, X_n \) is an \( n \times n \) matrix where \( \Sigma_{ii} = \operatorname{Var}(X_i) = \sigma^2 \) for all \( i \), and \( \Sigma_{ij} = \operatorname{Cov}(X_i, X_j) = \rho \sigma^2 \) for all \( i eq j \). This covariance matrix can be expressed as \( \Sigma = \sigma^2 ( (1-\rho) I_n + \rho J_n) \), where \( I_n \) is the identity matrix and \( J_n \) is a matrix of ones.
03

Calculate the Variance of the Sample Mean

The variance of the sample mean \( \operatorname{Var}(\bar{X}) \) is given by \( \operatorname{Var}(\bar{X}) = \frac{1}{n^2} \mathbf{1}^T \Sigma \mathbf{1} \). Substituting the covariance matrix \( \Sigma \), we have \( \operatorname{Var}(\bar{X}) = \frac{\sigma^2}{n^2} \mathbf{1}^T ( (1-\rho) I_n + \rho J_n) \mathbf{1} \).
04

Simplify the Variance Calculation

Evaluate the expression \( \mathbf{1}^T I_n \mathbf{1} = n \) and \( \mathbf{1}^T J_n \mathbf{1} = n^2 \). Therefore, \( \operatorname{Var}(\bar{X}) = \frac{\sigma^2}{n^2} ( (1-\rho)n + \rho n^2) = \frac{\sigma^2}{n^2} ( n - \rho n + \rho n^2) = \frac{\sigma^2}{n} ( 1 - \rho + \rho n) \).
05

Present the Final Result

The final expression for the variance of the sample mean is \( \operatorname{Var}(\bar{X}) = \frac{\sigma^2}{n} (1 - \rho + \rho n) \). This accounts for both the individual variances and the covariance between the variables, reflecting their correlated structure.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variance of the Sample Mean
Understanding the variance of the sample mean is essential in statistics, as it aids in evaluating the variability in sample estimations of population means.
The sample mean, typically denoted as \( \bar{X} \), is essentially an average of the set of random variables \( X_1, X_2, \ldots, X_n \).
Since averages can be from random variables, the sample mean itself is a random variable with its own variance.

The variance of a sample mean is a measure of how much to expect the sample mean to vary from the true population mean, due to randomness.
A smaller variance implies that the sample mean is typically close to the true population mean, whereas a larger variance indicates more uncertainty.

Using matrix methods, the variance of the sample mean can be calculated as:\[ \operatorname{Var}(\bar{X}) = \frac{\sigma^2}{n} (1 - \rho + \rho n) \]
where:
  • \( \sigma^2 \) is the variance of individual random variables.
  • \( \rho \) represents the correlation between pairs of different random variables.
  • \( n \) is the number of random variables in the sample.
This formula reflects not only the variance of individual terms, but also adjusts for the correlation, providing a complete picture of variability.
Matrix Methods
Matrix methods in statistics provide powerful ways to simplify and manage complex calculations, especially when working with multiple variables.
In the context of this exercise, matrix methods were employed to compute the variance of the sample mean by using the covariance matrix \( \Sigma \).

The covariance matrix \( \Sigma \) for a set of random variables is structured such that each diagonal element contains the variance of a single variable, and each off-diagonal element contains the covariance between pairs of variables.
For our case, the covariance matrix is given by:\[ \Sigma = \sigma^2 ((1-\rho) I_n + \rho J_n) \]
where:
  • \( I_n \) is the identity matrix, indicating variances on its diagonal.
  • \( J_n \) is a matrix of ones, capturing the covariances off-diagonal.
This expression allows the structured aggregation of both variance terms and covariance terms, facilitating the unified application of mathematical operations.

With matrix expressions, complex statistical tasks like deriving the variance of a sample mean are not only streamlined but also optimized for numerical computation.
Random Variables
Random variables are fundamental components in probability and statistics, serving as the building blocks for modeling random phenomena.
Each random variable \( X_i \) in this exercise represents an uncertain numerical outcome, with specific mean and variance parameters.

In this exercise, we considered \( X_1, X_2, \ldots, X_n \) with:
  • \( \operatorname{Var}(X_i) = \sigma^2 \)
  • \( \operatorname{Cov}(X_i, X_j) = \rho \sigma^2 \) for \( i eq j \)
This setup implies that each random variable exhibits the same amount of spread (variance), and is similarly correlated with other variables through the parameter \( \rho \).

Understanding these relationships is crucial, as the variance of the sample mean is inherently connected to the properties of the individual random variables.
Therefore, defining these characteristics in mathematical terms enables structured analysis and computational efficiency, forming the foundation for more advanced statistical insights and decisions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The file bi smuth contains the transition pressure (bar) of the bismuth II-I transition as a function of temperature \(\left(^{\circ} \mathrm{C}\right)\) (see Example \(\mathrm{E}\) in Section 14.2 .2 ). Fit a linear relationship between pressure and temperature, examine the residuals, and comment.

Suppose that the independent variables in a least squares problem are replaced by rescaled variables \(u_{i j}=k_{j} x_{i j}\) (for example, centimeters are converted to meters.) Show that \(Y\) does not change. Does \(\hat{\beta}\) change? (Hint: Express the new design matrix in terms of the old one.)

This problem extends some of the material in Section \(14.2 .3 .\) Let \(X\) and \(Y\) be random variables with $$ \begin{array}{c} E(X)=\mu_{x} \quad E(Y)=\mu_{y} \\ \operatorname{Var}(X)=\sigma_{x}^{2} \quad \operatorname{Var}(Y)=\sigma_{y}^{2} \\ \operatorname{Cov}(X, Y)=\sigma_{x y} \end{array} $$ Consider predicting \(Y\) from \(X\) as \(\hat{Y}=\alpha+\beta X,\) where \(\alpha\) and \(\beta\) are chosen to minimize \(E(Y-\tilde{Y})^{2},\) the expected squared prediction error.

The following table shows the monthly returns of stock in Disney. MacDonalds, Schlumberger, and Haliburton for January through May \(1998 .\) Fit a multiple regression to predict Disney returns from those of the other stocks. What is the standard deviation of the residuals? What is \(R^{2} ?\) $$\begin{array}{cccc} \hline \text { Disney } & \text { MacDonalds } & \text { Schlumberger } & \text { Haliburton } \\ \hline 0.08088 & -0.01309 & -0.08463 & -0.13373 \\ 0.04737 & 0.15958 & 0.02884 & 0.03616 \\ -0.04634 & 0.09966 & 0.00165 & 0.07919 \\ 0.16834 & 0.03125 & 0.09571 & 0.09227 \\ -0.09082 & 0.06206 & -0.05723 & -0.13242 \\ \hline \end{array}$$ Next, using the regression equation you have just found, carry out the predictions for January through May of 1999 and compare to the actual data listed below. What is the standard deviation of the prediction error? How can the comparison with the results from 1998 be explained? Is a reasonable explanation that the fundamental nature of the relationships changed in the one year period? $$\begin{array}{cccc} \hline \text { Disney } & \text { MacDonalds } & \text { Schlumberger } & \text { Haliburton } \\ \hline 0.1 & 0.02604 & 0.02695 & 0.00211 \\ 0.06629 & 0.07851 & 0.02362 & -0.04 \\ -0.11545 & 0.06732 & 0.23938 & 0.35526 \\ 0.02008 & -0.06483 & 0.06127 & 0.10714 \\ -0.08268 & -0.09029 & -0.05773 & -0.02933 \\ \hline \end{array}$$

Let \(X\) be a random \(n\) -vector and let \(Y\) be a random vector with \(Y_{1}=X_{1}\) \(Y_{i}=X_{i}-X_{i-1}, i=1,2, \ldots, n\) a. If the \(X_{i}\) are independent random variables with variances \(\sigma^{2},\) find the covariance matrix of Y. b. If the \(Y_{i}\) are independent random variables with variances \(\sigma^{2},\) find the covariance matrix of X.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.