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Prove the following two identities both algebraically and by interpreting their meaning combinatorially. a. \(\left(\begin{array}{l}n \\ r\end{array}\right)=\left(\begin{array}{c}n \\\ n-r\end{array}\right)\) b. \(\left(\begin{array}{l}n \\ r\end{array}\right)=\left(\begin{array}{c}n-1 \\\ r-1\end{array}\right)+\left(\begin{array}{c}n-1 \\ r\end{array}\right)\)

Short Answer

Expert verified
The identities hold: (a) choosing and not choosing items yield the same result, and (b) choices split by including or excluding a specific item.

Step by step solution

01

Understanding the Identity a

The identity \( \binom{n}{r} = \binom{n}{n-r} \) states that the number of ways to choose \( r \) items from \( n \) items is the same as the number of ways to choose \( n-r \) items from \( n \) items. This is because choosing \( r \) items from a total of \( n \) effectively leaves behind \( n-r \) items not chosen, which is another way of counting the combinations.
02

Algebraic Proof of Identity a

To prove \( \binom{n}{r} = \binom{n}{n-r} \) algebraically, use the definition of a binomial coefficient: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] and \( \binom{n}{n-r} = \frac{n!}{(n-r)!r!} \). These expressions are identical, thus confirming the identity.
03

Combinatorial Interpretation of Identity a

For identity \( a \), consider a group of \( n \) people. Choosing \( r \) people to be on a committee leaves \( n-r \) people not on the committee. The number of ways to choose the committee remains the same whether you're selecting \( r \) members to participate or \( n-r \) members not to participate.
04

Understanding the Identity b

The identity \( \binom{n}{r} = \binom{n-1}{r-1} + \binom{n-1}{r} \) suggests that the number of ways to choose \( r \) items from \( n \) items can be split into two groups: including a specific item, or excluding it.
05

Algebraic Proof of Identity b

Consider \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \). Applying the definition of combinations:- \( \binom{n-1}{r-1} = \frac{(n-1)!}{(r-1)!(n-r)!} \)- \( \binom{n-1}{r} = \frac{(n-1)!}{r!(n-r-1)!} \)The addition: \( \frac{(n-1)!}{(r-1)!(n-r)!} + \frac{(n-1)!}{r!(n-r-1)!} = \frac{r(n-r) + r(n-r)}{r!(n-r)!} = \frac{n!}{r!(n-r)!} \), confirming the identity.
06

Combinatorial Interpretation of Identity b

In identity \( b \), visualize choosing \( r \) people from \( n \) people. Pick one person as a guaranteed choice; you now need to choose \( r-1 \) from the remaining \( n-1 \). Alternatively, exclude this person and choose all \( r \) individuals from the remaining \( n-1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient
The concept of a binomial coefficient is fundamental in combinatorics. It represents the number of ways to choose a subset of items from a larger set without considering the order of selection. Formally, the binomial coefficient is written as \( \binom{n}{r} \), which means choosing \( r \) items from a set of \( n \) items.

The formula for calculating a binomial coefficient is:
  • \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \)
Here, \( n! \) (read as \( n \) factorial) represents the product of all positive integers up to \( n \), while \( r! \) and \( (n-r)! \) represent the factorials of \( r \) and \( n-r \), respectively.

This concept is widely applied in various mathematical fields, including algebra, probability, and statistics, particularly in scenarios dealing with combinations and permutations.
Combinatorial Proof
A combinatorial proof uses counting to demonstrate a mathematical identity. This type of proof often involves logically reasoning through a problem without the need for an algebraic equation. It's like solving a puzzle by considering all possible solutions visually or conceptually.

For example, consider the identity \( \binom{n}{r} = \binom{n}{n-r} \). A combinatorial proof for this might involve imagining a group of \( n \) people. Choosing \( r \) people to serve on a committee from these \( n \) people leaves \( n-r \) people not chosen. Therefore, choosing \( n-r \) people not to be on the committee is identical to choosing \( r \) people to be on it.

Another instance is \( \binom{n}{r} = \binom{n-1}{r-1} + \binom{n-1}{r} \). Consider including a specific item in the chosen group or not.

The proof splits into two scenarios: either include this item and choose \( r-1 \) from the remaining, or exclude it completely and choose \( r \) from the remainder. This double-counting verifies the identity.
Algebraic Proof
An algebraic proof for binomial identities involves manipulating algebraic expressions to confirm their truth. Let's consider two important identities.

For \( \binom{n}{r} = \binom{n}{n-r} \):
  • Using \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \) and \( \binom{n}{n-r} = \frac{n!}{(n-r)!r!} \).
Both expressions are clearly the same, confirming the identity through simple algebraic expression manipulation.

For \( \binom{n}{r} = \binom{n-1}{r-1} + \binom{n-1}{r} \):
  • Begin with \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \).
  • Breaking it down, \( \binom{n-1}{r-1} = \frac{(n-1)!}{(r-1)!(n-r)!} \) and \( \binom{n-1}{r} = \frac{(n-1)!}{r!(n-r-1)!} \).
Adding these two expressions proves the identity as the algebraic manipulation shows equality to the initial expression.

Algebraic proofs are concrete, relying only on mathematical transformations and arithmetic steps, making them robust and irrefutable.
Mathematical Identity
Mathematical identities present equations that hold true for all values involved, forming an essential part of mathematics, particularly in algebra and combinatorics. These identities represent fundamental truths that offer insights into complex mathematical problems and help simplify calculations.

In the context of combinatorics, two famous binomial identities are
  • \( \binom{n}{r} = \binom{n}{n-r} \)
  • \( \binom{n}{r} = \binom{n-1}{r-1} + \binom{n-1}{r} \)
Identities make it easier to understand relationships within sets and among numbers, often providing multiple routes to solving complex problems.

Understanding these identities not only aids in mathematical problem-solving but also provides a deeper appreciation of the inherent order and symmetry in mathematics. By recognizing and leveraging these identities, complex combinatorial challenges become more approachable.

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