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In each case, determine if the statement is true or false. (a) For all \([a],[b] \in \mathbb{Z}_{6},\) if \([a] \neq[0]\) and \([b] \neq[0],\) then \([a] \odot[b] \neq[0]\). (b) For all \([a],[b] \in \mathbb{Z}_{5},\) if \([a] \neq[0]\) and \([b] \neq[0],\) then \([a] \odot[b] \neq[0]\).

Short Answer

Expert verified
(a) False. (b) True.

Step by step solution

01

Understand the given ring

Since we are given the ring \(\mathbb{Z}_{6}\), it has six elements (from \(0\) to \(5\)). The multiplication operation \(\odot\) is defined as the multiplication modulo \(6\).
02

Check the conditions for the non-zero elements

Let's analyze the given statement: if \([a] \neq [0]\) and \([b] \neq [0]\), then \([a] \odot [b] \neq [0]\). We will test the non-zero elements of \(\mathbb{Z}_{6}\) for this condition: 1. \([1] \odot [1]=[1]\) (satisfies the condition) 2. \([1] \odot [2]=[2]\) (satisfies the condition) 3. \([1] \odot [3]=[3]\) (satisfies the condition) 4. \([1] \odot [4]=[4]\) (satisfies the condition) 5. \([1] \odot [5]=[5]\) (satisfies the condition) 6. \([2] \odot [2]=[4]\) (satisfies the condition) 7. \([2] \odot [3]=[0]\) (does NOT satisfy the condition)
03

Determine if the statement is true or false

Since one case (\([2] \odot [3]=[0]\)) does not satisfy the conditions stated in the problem, the given statement is false. (b) \( \mathbb{Z}_{5} \)
04

Understand the given ring

Since we are given the ring \(\mathbb{Z}_{5}\), it has five elements (from \(0\) to \(4\)). The multiplication operation \(\odot\) is defined as the multiplication modulo \(5\).
05

Check the conditions for the non-zero elements

Let's analyze the given statement: if \([a] \neq [0]\) and \([b] \neq [0]\), then \([a] \odot [b] \neq [0]\). We will test the non-zero elements of \(\mathbb{Z}_{5}\) for this condition: 1. \([1] \odot [1]=[1]\) (satisfies the condition) 2. \([1] \odot [2]=[2]\) (satisfies the condition) 3. \([1] \odot [3]=[3]\) (satisfies the condition) 4. \([1] \odot [4]=[4]\) (satisfies the condition) 5. \([2] \odot [2]=[4]\) (satisfies the condition) 6. \([2] \odot [3]=[1]\) (satisfies the condition) 7. \([2] \odot [4]=[3]\) (satisfies the condition) 8. \([3] \odot [3]=[4]\) (satisfies the condition) 9. \([3] \odot [4]=[2]\) (satisfies the condition) 10. \([4] \odot [4]=[1]\) (satisfies the condition)
06

Determine if the statement is true or false

Since all possible cases satisfy the conditions stated in the problem, the given statement is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ring Theory
Ring theory is a branch of abstract algebra that deals with structures known as rings. A ring is a set equipped with two binary operations, typically called addition and multiplication, that generalize the arithmetic of integers. In a ring, addition must be commutative (change in the order does not change the result), associative (grouping of elements does not affect the result), and the set must have an additive identity (usually denoted as 0), as well as an additive inverse for each element.

Moreover, multiplication in a ring is associative and must distribute over addition. However, multiplication doesn't necessarily have to be commutative. Rings can be with or without a multiplicative identity (often denoted as 1).

Understanding ring theory is essential when working with different systems of numbers and when exploring concepts such as modular arithmetic, which is often studied within the context of rings. For example, in our exercise, the ring \( \mathbb{Z}_{6} \) and \( \mathbb{Z}_{5} \) represent the sets of integers modulo 6 and modulo 5, respectively, each with their own unique properties and elements.
Modular Arithmetic
Modular arithmetic is sometimes referred to as 'clock arithmetic' because of its cyclic nature, like the hours on a clock. It is a system of arithmetic for integers, where numbers wrap around upon reaching a certain value called the modulus. The classic example of modular arithmetic is a 12-hour clock. After 12 hours, the next hour is 1 again, not 13, because a clock resets modulo 12.

In our example involving the rings \( \mathbb{Z}_{6} \) and \( \mathbb{Z}_{5} \), the modulus is 6 and 5, respectively. The operation \( \odot \) mentioned in the exercise refers to multiplication in modular arithmetic. It's essential to note that properties of modular arithmetic vary with different moduli; for instance, \( \mathbb{Z}_{6} \) does not form a field because 6 is not a prime number and does not contain a multiplicative inverse for each non-zero element, as seen in the exercise where \( [2] \odot [3]=[0] \) in \( \mathbb{Z}_{6} \) breaks the expected rule for non-zero elements.
Proof Writing
Proof writing is a formal method of demonstrating the truth of mathematical statements. A proof can take several forms, but its main goal is always to show that given certain premises, a conclusion necessarily follows. A proof must be logical, clear, concise, and rigorous. When writing a proof, one must use established mathematical results and logical deductions to arrive at the conclusion.

In the textbook exercise, we see a simple form of proof called 'proof by counterexample' for part (a). To disprove the statement given for \( \mathbb{Z}_{6} \), we find a specific case where the condition does not hold: \( [2] \odot [3]=[0] \), hence showing the statement is false. Conversely, for \( \mathbb{Z}_{5} \), the proof would be of the type 'proof by exhaustion' because we test all possible scenarios to show that the condition holds true in all cases, strengthening our claim that the statement in part (b) is indeed true.

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Most popular questions from this chapter

A Partition Defines an Equivalence Relation. Let \(A=\\{a, b, c, d, e\\}\) and let \(\mathcal{C}=\\{\\{a, b, c\\},\\{d, e\\}\\}\) (a) Explain why \(\mathcal{C}\) is a partition of \(A\). Define a relation \(\sim\) on \(A\) as follows: For \(x, y \in A, x \sim y\) if and only if there exists a set \(U\) in \(\mathcal{C}\) such that \(x \in U\) and \(y \in U\) (b) Prove that \(\sim\) is an equivalence relation on the set \(A\), and then determine all the equivalence classes for \(\sim\). How does the collection of all equivalence classes compare to \(\mathcal{C} ?\) What we did for the specific partition in Part (12b) can be done for any partition of a set. So to generalize Part (12b), we let \(A\) be a nonempty set and let \(\mathcal{C}\) be a partition of \(A\). We then define a relation \(\sim\) on \(A\) as follows: For \(x, y \in A, x \sim y\) if and only if there exists a set \(U\) in \(\mathcal{C}\) such that \(x \in U\) and \(y \in U\) (c) Prove that \(\sim\) is an equivalence relation on the set \(A\). (d) Let \(a \in A\) and let \(U \in \mathcal{C}\) such that \(a \in U\). Prove that \([a]=U\).

Let \(R_{<}=\\{(x, y) \in \mathbb{R} \times \mathbb{R} \mid x

Let \(U\) be a finite, nonempty set and let \(\mathcal{P}(U)\) be the power set of \(U\). That is, \(\mathcal{P}(U)\) is the set of all subsets of \(U\). Define the relation \(\sim\) on \(\mathcal{P}(U)\) as follows: For \(A, B \in \mathcal{P}(U), A \sim B\) if and only if \(A \cap B=\emptyset .\) That is, the ordered pair \((A, B)\) is in the relation \(\sim\) if and only if \(A\) and \(B\) are disjoint. Is the relation \(\sim\) an equivalence relation on \(\mathcal{P}(U) ?\) If not, is it reflexive, symmetric, or transitive? Justify all conclusions.

Define the relation \(\sim\) on \(\mathbb{Q}\) as follows: For \(a, b \in \mathbb{Q}, a \sim b\) if and only if \(a-b \in \mathbb{Z} .\) In Progress Check \(7.9,\) we showed that the relation \(\sim\) is an equivalence relation on \(\mathbb{Q}\). (a) List four different elements of the set \(C=\left\\{x \in \mathbb{Q} \mid x \sim \frac{5}{7}\right\\}\). (b) Use set builder notation (without using the symbol \(\sim\) ) to specify the set \(C .\) (c) Use the roster method to specify the set \(C\).

Prove the following proposition: For each \(a \in \mathbb{Z},\) if there exist integers \(b\) and \(c\) such that \(a=b^{4}+c^{4}\), then the units digit of \(a\) must be \(0,1,2,5,6,\) or 7 .

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