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Let \(g: \mathbb{N} \times \mathbb{N} \rightarrow \mathbb{N}\) by \(g(m, n)=2^{m} 3^{n},\) let \(A=\\{1,2,3\\},\) and let \(C=\) \(\\{1,4,6,9,12,16,18\\}\) . Find (a) \(g(A \times A)\) (b) \(g^{-1}(C)\) (c) \(g^{-1}(g(A \times A))\) (d) \(g\left(g^{-1}(C)\right)\)

Short Answer

Expert verified
(a) \(g(A \times A) = \{6, 18, 54, 12, 36, 108, 24, 72, 216\}\) (b) \(g^{-1}(C) = \{(0,0), (2,0), (1,1), (0,2), (2,1), (4,0), (1,2)\}\) (c) \(g^{-1}(g(A \times A)) = \{(1,1), (1,2), (1,3), (2,1), (2,2), (2,3), (3,1), (3,2), (3,3)\}\) (d) \(g(g^{-1}(C)) = \{1, 4, 6, 9, 12, 16, 18\}\)

Step by step solution

01

(a) Calculating g(A × A)#

First, let's find the cartesian product A × A. A cartesian product of two sets is created by forming ordered pairs with elements from each set. In this case, A = {1,2,3}, so we have: A × A = {(1,1), (1,2), (1,3), (2,1), (2,2), (2,3), (3,1), (3,2), (3,3)} Now, we'll apply the function g(m,n) = 2^m 3^n to each pair: g(A × A) = {\(g(1,1), g(1,2), g(1,3), g(2,1), g(2,2), g(2,3), g(3,1), g(3,2), g(3,3)\)} Calculating the values, we get: g(A × A) = {6, 18, 54, 12, 36, 108, 24, 72, 216}
02

(b) Calculating g^{-1}(C)#

To find the pre-image of C under the function g, we need to find the ordered pairs (m,n) such that g(m,n) is in C. C = {1, 4, 6, 9, 12, 16, 18} We are looking for pairs (m,n) such that g(m,n) = 2^m 3^n is in the set C. By trial and error, we can find the following pre-images: - g(0,0) = 1 - g(2,0) = 4 - g(1,1) = 6 - g(0,2) = 9 - g(2,1) = 12 - g(4,0) = 16 - g(1,2) = 18 So, g^{-1}(C) = {(0,0), (2,0), (1,1), (0,2), (2,1), (4,0), (1,2)}
03

(c) Calculating g^{-1}(g(A × A))#

We already calculated g(A × A) = {6, 18, 54, 12, 36, 108, 24, 72, 216}. Now we need to find the pre-image of this set under the function g. We already know the pre-images from the previous steps: - g(1,1) = 6 - g(1,2) = 18 - g(1,3) = 54 - g(2,1) = 12 - g(2,2) = 36 - g(2,3) = 108 - g(3,1) = 24 - g(3,2) = 72 - g(3,3) = 216 So, g^{-1}(g(A × A)) = {(1,1), (1,2), (1,3), (2,1), (2,2), (2,3), (3,1), (3,2), (3,3)}
04

(d) Calculating g(g^{-1}(C))#

We previously found g^{-1}(C) = {(0,0), (2,0), (1,1), (0,2), (2,1), (4,0), (1,2)}. Now we need to apply the function g(m,n) to these ordered pairs: g(g^{-1}(C)) = {g(0,0), g(2,0), g(1,1), g(0,2), g(2,1), g(4,0), g(1,2)} Calculating the values, we get: g(g^{-1}(C)) = {1, 4, 6, 9, 12, 16, 18} Since this set is equal to the original set C, we can see that the pre-image and image relationship holds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pre-image in Functions
The pre-image of a function refers to the set of all input values that are mapped to a given set of output values under a specific function. When you have a function like \( g: \mathbb{N} \times \mathbb{N} \rightarrow \mathbb{N} \) given by \( g(m, n)=2^{m} 3^{n} \), finding the pre-image of a set means identifying all ordered pairs \((m, n)\) such that the function value \( g(m, n) \) is included in the set.

In our exercise, when determining \( g^{-1}(C) \), we're hunting for pairs \( (m, n) \) that satisfy \( g(m, n) \in C = \{1, 4, 6, 9, 12, 16, 18\} \). Here, each ordered pair corresponds to a specific value in \( C \) after applying the function, showcasing their pre-image.
To find the pre-image, consider each element in the set \( C \) and perform trial and error by substituting values of \( m \) and \( n \) into \( g(m, n) \). This allows us to systematically determine the combinations that work.
Inverse Function
An inverse function essentially reverses the effect of a function. If you have a function \( f \) that takes \( x \) to \( y \), then the inverse function, denoted as \( f^{-1} \), maps \( y \) back to \( x \). However, not all functions possess an inverse.

In this exercise, the focus is not strictly on one-to-one inverses, but rather on operations that resemble inverse functionality, specifically in terms of pre-images and images like \( g^{-1}(C) \).
Calculating \( g(g^{-1}(C)) \) answers a common inverse-related question. It involves applying the function \( g \) to its pre-image found in the previous step. After calculation, you should retrieve the original set \( C \), demonstrating how a function and its inverse-like operation interact.
Ordered Pairs
Ordered pairs, denoted as \((a, b)\), are foundational in mathematics, especially when dealing with functions. In a Cartesian product, ordered pairs are combinations selected from two sets, where the order matters.

In this example, \( A \times A \) forms ordered pairs such as \((1,2)\), \((2,3)\), and so forth from the set \( A = \{1, 2, 3\} \). Each ordered pair is a potential input for the function \( g(m, n) = 2^m 3^n \).
Ordered pairs are crucial in defining the function \( g \), where the first element contributes to the power of 2, and the second element to the power of 3. Exploring each pair, like in \( g^{-1}(C) \), allows students to appreciate the construction and application of functions across cartesian pairs.
Discrete Mathematics
Discrete mathematics is a branch of mathematics dealing with countable, distinct elements. It plays an integral role when examining sets, functions, and ordered pairs.

This exercise involves applying concepts from discrete mathematics, such as Cartesian products, functions, and their inverses, to solve problems like determining \(g(A \times A)\) or finding \(g^{-1}(C)\).
  • **Functions**: Used to map elements from one set to another. In this case, mapping ordered pairs to integers.
  • **Sets**: We deal with finite sets and their manipulations.
  • **Cartesian Products**: Create specific input combinations for functions.
Working with scenarios from discrete mathematics, such as unique mapping and set operations in this problem, builds foundational skills essential for computer science and related fields.

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Most popular questions from this chapter

Let \(f: A \rightarrow B\) and \(g: B \rightarrow A\). Let \(I_{A}\) and \(I_{B}\) be the identity functions on the sets \(A\) and \(B\), respectively. Prove each of the following: (a) If \(g \circ f=I_{A},\) then \(f\) is an injection. (b) If \(f \circ g=I_{B},\) then \(f\) is a surjection. (c) If \(g \circ f=I_{A}\) and \(f \circ g=I_{B},\) then \(f\) and \(g\) are bijections and \(g=f^{-1}\)

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In Exercise (6), we introduced the number of divisors function \(d\). For this function, \(d: \mathbb{N} \rightarrow \mathbb{N},\) where \(d(n)\) is the number of natural number divisors of \(n\) A function that is related to this function is the so-called set of divisors function. This can be defined as a function \(S\) that associates with each natural number the set of its distinct natural number factors. For example. \(S(6)=\\{1,2,3,6\\}\) and \(S(10)=\\{1,2,5,10\\}\) (a) Discuss the function \(S\) by carefully stating its domain, codomain, and its rule for determining outputs. (b) Determine \(S(n)\) for at least five different values of \(n\). - (c) Determine \(S(n)\) for at least three different prime number values of \(n\). (d) Does there exist a natural number \(n\) such that card \((S(n))=1 ? \mathrm{Ex}-\) plain. [Recall that card \((S(n))\) is the number of elements in the set \(S(n) .]\) (e) Does there exist a natural number \(n\) such that card \((S(n))=2 ? \mathrm{Ex}=\) plain. (f) Write the output for the function \(d\) in terms of the output for the function \(S\). That is, write \(d(n)\) in terms of \(S(n)\). (g) Is the following statement true or false? Justify your conclusion. For all natural numbers \(m\) and \(n,\) if \(m \neq n,\) then \(S(m) \neq S(n)\). (h) Is the following statement true or false? Justify your conclusion. For all sets \(T\) that are subsets of \(\mathbb{N}\), there exists a natural number \(n\) such that \(S(n)=T\)

Let \(f: S \rightarrow T\) and let \(A\) and \(B\) be subsets of \(S\). Prove or disprove each of the following: (a) If \(A \subseteq B,\) then \(f(A) \subseteq f(B)\). (b) If \(f(A) \subseteq f(B),\) then \(A \subseteq B\)

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