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Is the following proposition true or false? Justify your conclusion. For each natural number \(n,\left(\frac{n^{3}}{3}+\frac{n^{2}}{2}+\frac{7 n}{6}\right)\) is a natural number.

Short Answer

Expert verified
The proposition is false. After simplifying and factoring the expression, we analyzed three cases of n being multiples of 2, 3, or 6. In the first two cases, the expression does not simplify to a natural number. In the third case, it does result in a natural number. Thus, the given proposition is not true for every natural number n.

Step by step solution

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Numbers
Natural numbers are the simplest kinds of numbers that are foundational in mathematics. They include all positive integers starting from 1, such as 1, 2, 3, and so on. These numbers are used for counting and ordering. For instance, you can count apples or rank positions in a line using natural numbers.

In mathematical reasoning, when a variable is described as ranging over natural numbers, it indicates that the variable will take on values that are whole numbers greater than zero. This is an essential concept because it affects how we evaluate expressions and phenomena. When dealing with equations or expressions, if a result should be a natural number, then any fraction or decimal value is considered inappropriate for that evaluation.

This is particularly relevant in the context of the original exercise, where you evaluate whether the expression \( \frac{n^{3}}{3}+\frac{n^{2}}{2}+\frac{7n}{6} \) yields a natural number for all values of \( n \). Understanding the nature of natural numbers will guide you in making correct judgments about whether certain expressions meet the criteria of being solely whole numbers.
Inductive Reasoning
Inductive reasoning in mathematics is a process of reasoning that involves making generalizations from specific instances. It's a logical method for determining the truth of propositions, especially in sequences or patterns related to natural numbers.

This reasoning plays a crucial role in proving statements for all natural numbers. To apply inductive reasoning, you typically start by checking the base case, which is the smallest value of the natural number involved, often \( n = 1 \). If the base case holds true, you then assume it is true for some arbitrary natural number \( n = k \), and show that it must also be true for \( n = k + 1 \).

The rationale behind this technique is that if something works initially and continues to hold true from step to step, it continues to be true for all succeeding steps. Inductive reasoning can be incredibly powerful in mathematical proofs, but it must be applied correctly with each step carefully verified.
Proof Techniques
Proof techniques are methods used to determine the validity of mathematical statements. Each technique has its application and scenarios where it is most effective.

In the context of the exercise challenge, for instance, determining whether \( \frac{n^{3}}{3}+\frac{n^{2}}{2}+\frac{7n}{6} \) is a natural number for each natural number \( n \) might initially consider testing individual values or checking overall properties.
  • Direct Proof: Involves straightforward verification of the proposition by substitution and simplification.
  • Counterexample: In proving a statement is false, finding one instance where the statement doesn't hold is enough. For this particular exercise, identifying \( n = 1 \) as a counterexample quickly invalidates the need to prove the expression is always a natural number since \( \frac{1^{3}}{3}+\frac{1^{2}}{2}+\frac{7 \times 1}{6} \) does not result in a natural number.
  • Mathematical Induction: Generally used when proving statements for any natural number, verifying the base case and the inductive step, but here it serves less purpose due to the presence of a clear counterexample.
Learning to choose and apply appropriate proof techniques is crucial in validating mathematical propositions, helping in distinguishing between true and false statements effectively.

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Most popular questions from this chapter

The Future Value of an Ordinary Annuity. For an ordinary annuity, \(R\) dollars is deposited in an account at the end of each compounding period. It is assumed that the interest rate, \(i,\) per compounding period for the account remains constant. Let \(S_{t}\) represent the amount in the account at the end of the \(t\) th compounding period. \(S_{t}\) is frequently called the future value of the ordinary annuity. So \(S_{1}=R\). To determine the amount after two months, we first note that the amount after one month will gain interest and grow to \((1+i) S_{1} .\) In addition, a new deposit of \(R\) dollars will be made at the end of the second month. So $$ S_{2}=R+(1+i) S_{1} $$ (a) For each \(n \in \mathbb{N},\) use a similar argument to determine a recurrence relation for \(S_{n+1}\) in terms of \(R, i,\) and \(S_{n}\). (b) By recognizing this as a recursion formula for a geometric series, use Proposition 4.16 to determine a formula for \(S_{n}\) in terms of \(R, i,\) and \(n\) that does not use a summation. Then show that this formula can be written as $$ S_{n}=R\left(\frac{(1+i)^{n}-1}{i}\right) $$ (c) What is the future value of an ordinary annuity in 20 years if \(\$ 200\) dollars is deposited in an account at the end of each month where the interest rate for the account is \(6 \%\) per year compounded monthly? What is the amount of interest that has accumulated in this account during the 20 years?

Which of the following sets are inductive sets? Explain. (a) \(\mathbb{Z}\) (c) \(\\{x \in \mathbb{Z} \mid x \leq 10\\}\) (b) \(\\{x \in \mathbb{N} \mid x \geq 4\\}\) (d) \(\\{1,2,3, \ldots, 500\\}\)

For the sequence \(a_{1}, a_{2}, \ldots, a_{n}, \ldots,\) assume that \(a_{1}=1,\) and that for each natural number \(n\), $$ a_{n+1}=a_{n}+n \cdot n ! $$ (a) Compute \(n !\) for the first 10 natural numbers. (b) Compute \(a_{n}\) for the first 10 natural numbers. (c) Make a conjecture about a formula for \(a_{n}\) in terms of \(n\) that does not involve a summation or a recursion.

Prove that for each odd natural number \(n\) with \(n \geq 3\), $$ \left(1+\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1+\frac{1}{4}\right) \cdots\left(1+\frac{(-1)^{n}}{n}\right)=1 . $$

Can each natural number greater than or equal to 6 be written as the sum of at least two natural numbers, each of which is a 2 or a 5 ? Justify your conclusion. For example, \(6=2+2+2,9=2+2+5,\) and \(17=2+5+5+5\).

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