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Are the following statements true or false? Justify your conclusions. (a) For each integer \(a\), if 3 does not divide \(a\), then 3 divides \(2 a^{2}+1\). (b) For each integer \(a\), if 3 divides \(2 a^{2}+1,\) then 3 does not divide \(a\). (c) For each integer \(a, 3\) does not divide \(a\) if and only if 3 divides \(2 a^{2}+1\).

Short Answer

Expert verified
All three statements (a), (b), and (c) are true. We showed this by considering the cases of integers a in the form of 3k+1 or 3k+2, analyzing the divisibility of the expression (2*a^2 + 1) by 3, and proving the truth of each statement and their conclusions separately.

Step by step solution

01

Statement (a) - If 3 does not divide a, then 3 divides (2*a^2 + 1)

For an integer a, there are two possibilities if 3 does not divide a: the integer a can be in the form of 3k+1 or 3k+2, where k is an integer. Case 1: a = 3k+1 When a = 3k+1, we need to consider the expression (2*a^2 + 1) and investigate whether it is divisible by 3: \(2(3k+1)^2 + 1 = 2(9k^2 + 6k + 1) + 1 = 18k^2 + 12k + 2 + 1 = 18k^2 + 12k + 3\) Since 18k^2 and 12k are divisible by 3, the entire expression is divisible by 3. Case 2: a = 3k+2 When a = 3k+2, we again consider the expression (2*a^2 + 1) and investigate its divisibility by 3: \(2(3k+2)^2 + 1 = 2(9k^2 + 12k + 4) + 1 = 18k^2 + 24k + 8 + 1 = 18k^2 + 24k + 9\) Since 18k^2 and 24k are divisible by 3, the entire expression is divisible by 3. Since both cases show that if 3 does not divide a, then 3 divides (2*a^2 + 1), statement (a) is true.
02

Statement (b) - If 3 divides (2*a^2 + 1), then 3 does not divide a

This statement is the converse of statement (a). Since we already proved statement (a) to be true, this means that if 3 does not divide a, then 3 will divide (2*a^2 + 1). Therefore, it is impossible that 3 divides both a and (2*a^2 + 1). So statement (b) is true.
03

Statement (c) - For each integer a, 3 does not divide a if and only if 3 divides (2*a^2 + 1)

This statement is actually the combination of statements (a) and (b). We have proved both statements (a) and (b) to be true, so statement (c) is also true. In conclusion, all three statements are true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exploring Divisibility
Understanding the concept of divisibility is crucial for solving problems involving integers and their properties. Divisibility refers to the ability of one number to be divided by another without leaving a remainder. In mathematical terms, we say that a number \( a \) is divisible by \( b \) if there exists an integer \( k \) such that \( a = bk \).

When we look at the exercise, divisibility plays a central role. Particularly, we're exploring scenarios where one number does not divide another and how this relates to different expressions. For example:
  • If a number is not divisible by 3, we say it's in the form \( 3k+1 \) or \( 3k+2 \).
  • If a number \( 3 \) divides the expression \( 2a^2 + 1 \), it means this expression can be written as \( 3m \) for some integer \( m \).
By considering different cases for integers and checking whether particular expressions are divisible by 3, we unravel important truths about their relationships. The logic behind examining divisibility in this manner helps establish foundational conclusions in number theory.
Integer Properties and Residue Classes
Integer properties help us understand the nature of numbers and how they behave under different operations. In the realm of this exercise, we particularly focus on two properties: integer division and residue classes.

When an integer is divided by another, the remainder is crucial. Understanding residue classes—or the remainder when an integer is divided by a number like 3—illustrates why integers can be expressed as \( 3k+1 \) or \( 3k+2 \) when they are not divisible by 3.
  • For each integer \( a \) not divisble by 3, the result can only yield remainders of 1 or 2.
  • These two classes help us create small cases, making it easy to analyze the expression \( 2a^2 + 1 \) and verify if it meets divisibility criteria.
Using these residue classes simplifies the mathematics significantly, allowing us to convert a potentially complex problem into manageable sections. Thus, integer properties aid in structuring our proof strategies.
Implementing Proof Strategies
Developing effective proof strategies is essential when tackling problems about integers and divisibility. One common and powerful strategy used here is proof by cases. This method requires exploring all possible scenarios to validate a statement.

In our problem, we examined scenarios where:
  • \( a = 3k+1 \) and \( a = 3k+2 \), representing numbers not divisible by 3.
  • In both cases, the expression \( 2a^2 + 1 \) was analyzed to confirm its divisibility by 3.
This approach ensures thorough coverage of possible numbers, leaving no stone unturned. Additionally, proof by contraposition is also at play, helping verify statements by proving that if the conclusion does not hold, neither can the premise.

These strategies allow for a systematic exploration of logical conclusions, ensuring each assumption and resulting proof is sound and comprehensive. This technique, especially in number theory, illustrates the elegance and power of structured reasoning in mathematics.

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Most popular questions from this chapter

(a) Verify that the triangle inequality is true for several different real numbers \(x\) and \(y .\) Be sure to have some examples where the real numbers are negative. (b) Explain why the following proposition is true: For each real number \(r\), \(-|r| \leq r \leq|r|\) (c) Now let \(x\) and \(y\) be real numbers. Apply the result in Part (14b) to both \(x\) and \(y\). Then add the corresponding parts of the two inequalities to obtain another inequality. Use this to prove that \(|x+y| \leq|x|+|y|\)

Is the following statement true or false? Justify your conclusion. For each integer \(n\) that is greater than 1 , if \(a\) is the smallest positive factor of \(n\) that is greater than \(1,\) then \(a\) is prime. See Exercise (13) in Section 2.4 (page 78 ) for the definition of a prime number and the definition of a composite number.

One of the most famous unsolved problems in mathematics is a conjecture made by Christian Goldbach in a letter to Leonhard Euler in 1742. The conjecture made in this letter is now known as Goldbach's Conjecture. The conjecture is as follows: Every even integer greater than 2 can be expressed as the sum of two (not necessarily distinct) prime numbers. Currently, it is not known if this conjecture is true or false. (a) Write \(50,142,\) and 150 as a sum of two prime numbers. (b) Prove the following: If Goldbach's Conjecture is true, then every integer greater than 5 can be written as a sum of three prime numbers. (c) Prove the following: If Goldbach's Conjecture is true, then every odd integer greater than 7 can be written as a sum of three odd prime numbers.

Consider the following proposition: For each integer \(a, a \equiv 3(\bmod 7)\) if and only if \(\left(a^{2}+5 a\right) \equiv 3(\bmod 7)\). (a) Write the proposition as the conjunction of two conditional statements. (b) Determine if the two conditional statements in Part (a) are true or false. If a conditional statement is true, write a proof, and if it is false, provide a counterexample. (c) Is the given proposition true or false? Explain.

(a) Use the result in Proposition 3.33 to help prove that the integer \(m=\) 5,344,580,232,468,953,153 is not a perfect square. Recall that an integer \(n\) is a perfect square provided that there exists an integer \(k\) such that \(n=k^{2} .\) Hint: Use a proof by contradiction. (b) Is the integer \(n=782,456,231,189,002,288,438\) a perfect square? Justify your conclusion.

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