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Let \(a\) be a real number and let \(f\) be a real-valued function defined on an interval containing \(x=a\). Consider the following conditional statement: If \(f\) is differentiable at \(x=a,\) then \(f\) is continuous at \(x=a\). Which of the following statements have the same meaning as this conditional statement and which ones are negations of this conditional statement? (a) If \(f\) is continuous at \(x=a,\) then \(f\) is differentiable at \(x=a\). (b) If \(f\) is not differentiable at \(x=a,\) then \(f\) is not continuous at \(x=a\). (c) If \(f\) is not continuous at \(x=a,\) then \(f\) is not differentiable at \(x=a\). (d) \(f\) is not differentiable at \(x=a\) or \(f\) is continuous at \(x=a\). (e) \(f\) is not continuous at \(x=a\) or \(f\) is differentiable at \(x=a\). (f) \(f\) is differentiable at \(x=a\) and \(f\) is not continuous at \(x=a\).

Short Answer

Expert verified
Option (c) has the same meaning as the original statement, and options (b) and (f) are negations of the original statement.

Step by step solution

01

Option (a)

If \(f\) is continuous at \(x=a,\) then \(f\) is differentiable at \(x=a\). This statement can be represented as: Continuous \(\Rightarrow\) Differentiable This does not have the same meaning nor is it a negation of the original statement, so (a) is neither.
02

Option (b)

If \(f\) is not differentiable at \(x=a,\) then \(f\) is not continuous at \(x=a\). This statement can be represented as: Not Differentiable \(\Rightarrow\) Not Continuous This statement is a negation of the original statement, so (b) is a negation option.
03

Option (c)

If \(f\) is not continuous at \(x=a,\) then \(f\) is not differentiable at \(x=a\). This statement can be represented as: Not Continuous \(\Rightarrow\) Not Differentiable This statement has the same meaning as the original statement, so (c) is a same meaning option.
04

Option (d)

\(f\) is not differentiable at \(x=a\) or \(f\) is continuous at \(x=a\). This statement can be represented as: Not Differentiable \(\lor\) Continuous This does not have the same meaning nor is it a negation of the original statement, so (d) is neither.
05

Option (e)

\(f\) is not continuous at \(x=a\) or \(f\) is differentiable at \(x=a\). This statement can be represented as: Not Continuous \(\lor\) Differentiable This does not have the same meaning nor is it a negation of the original statement, so (e) is neither.
06

Option (f)

\(f\) is differentiable at \(x=a\) and \(f\) is not continuous at \(x=a\). This statement can be represented as: Differentiable \(\land\) Not Continuous This statement contradicts the original statement, because if a function is differentiable at \(x=a\), then it must also be continuous at \(x=a\). Thus, (f) is a negation option. In conclusion, options (c) and (f) have the same meaning as the original statement, and options (b) and (d) are negations of the original statement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Statements in Mathematics
Conditional statements, also known as 'if-then' statements, play a critical role in mathematics. They form the basis of logical reasoning by positing that if one statement (the hypothesis) is true, then another statement (the conclusion) will also be true.

For instance, consider the statement: 'If a number is even, then it is divisible by 2.' This represents a straightforward conditional where the truth of the number being even (hypothesis) necessitates the truth of it being divisible by 2 (conclusion).

In the context of functions, as seen in our exercise, the conditional given is 'If a function is differentiable at a point, then it is continuous at that point.' To understand and test such statements, one must grasp the concepts of both differentiability and continuity. It's also essential to comprehend the contrapositive and negation of these conditionals. The contrapositive of the original conditional 'If not continuous, then not differentiable' has the same truth value, whereas the negation would be 'It is differentiable and not continuous,' contradicting the original assertion.

Understanding such logical connections is vital, as it assists in examining the interplay between different mathematical concepts.
Real-Valued Functions
Real-valued functions are functions that take a real number as input and produce a real number as output. This vast category of functions is a cornerstone of calculus and advanced mathematics.

The function described in the original exercise, where we discuss continuity and differentiability, is precisely this kind. A real-valued function might showcase a wide range of behaviors, and understanding these is key to mastering calculus in particular.

Continuity and differentiability are two fundamental properties of real-valued functions. A function is continuous at a point if there are no breaks, jumps, or holes at that point. Mathematically, a function is continuous at a point if the limit as you approach the point equals the function's value at the point.

Differentiability, on the other hand, refers to the existence of a function's derivative at a point, meaning the function's graph has a well-defined tangent at that point. A remarkable aspect of real-valued functions is that if a function is differentiable at any point, it is guaranteed to be continuous there, but the converse need not always hold true.
Mathematical Reasoning
Mathematical reasoning allows us to make logical connections between statements and to understand the implications of given conditions. It involves the use of logic in mathematics to move from one set of facts to another.

In our exercise, the reasoning process involves examining the implications of differentiability and continuity for a real-valued function. By scrutinizing these properties and how they interrelate through the lens of conditional statements, we can derive meaningful conclusions about the function's behavior.

This capability is essential for developing proofs, for hypothesizing the behavior of functions under given conditions, and for solving problems effectively. Strong mathematical reasoning skills enable us to move beyond rote memorization of formulas and to engage deeply with the 'why' and 'how' of mathematics, which—as we see in this exercise—can lead one to uncover the nuances and intricacies of conditional statements and the properties of functions.

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Most popular questions from this chapter

For statements \(P\) and \(Q,\) use truth tables to determine if each of the following statements is a tautology, a contradiction, or neither. (a) \(\neg Q \vee(P \rightarrow Q)\) (c) \((Q \wedge P) \wedge(P \rightarrow \neg Q)\) (b) \(Q \wedge(P \wedge \neg Q)\) (d) \(\neg Q \rightarrow(P \wedge \neg P)\)

Suppose that Daisy says, "If it does not rain, then I will play golf." Later in the day you come to know that it did rain but Daisy still played golf. Was Daisy's statement true or false? Support your conclusion.

Least Upper Bound for a Subset of \(\mathbb{R}\). In Exercise \(14,\) we introduced the definition of an upper bound for a subset of the real numbers. Assume that we know this definition and that we know what it means to say that a number is not an upper bound for a subset of the real numbers. Let \(A\) be a subset of \(\mathbb{R}\). A real number \(\alpha\) is the least upper bound for \(A\) provided that \(\alpha\) is an upper bound for \(A,\) and if \(\beta\) is an upper bound for \(A\), then \(\alpha \leq \beta\) Note: The symbol \(\alpha\) is the lowercase Greek letter alpha, and the symbol \(\beta\) is the lowercase Greek letter beta. If we define \(P(x)\) to be \(^{*} x\) is an upper bound for \(A\)," then we can write the definition for least upper bound as follows: A real number \(\alpha\) is the least upper bound for \(A\) provided that \(P(\alpha) \wedge[(\forall \beta \in \mathbb{R})(P(\beta) \rightarrow(\alpha \leq \beta))]\) (a) Why is a universal quantifier used for the real number \(\beta ?\) (b) Complete the following sentence in symbolic form: "A real number \(\alpha\) is not the least upper bound for \(A\) provided that ...."

For each of the following statements \- Write the statement as an English sentence that does not use the symbols for quantifiers. \- Write the negation of the statement in symbolic form in which the negation symbol is not used. \- Write a useful negation of the statement in an English sentence that does not use the symbols for quantifiers. (a) \((\exists x \in \mathbb{Q})(x>\sqrt{2})\) (b) \((\forall x \in \mathbb{Q})\left(x^{2}-2 \neq 0\right)\). * (c) \((\forall x \in \mathbb{Z})(x\) is even or \(x\) is odd). (d) \(\left(\exists x \in\right.\) Q) \((\sqrt{2}

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