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Graph \(f(x)=x^2-4 x-5\)

Short Answer

Expert verified
Vertex: (2, -9); Axis of Symmetry: x=2; Y-Intercept: (0,-5); X-Intercepts: (5,0) and (-1,0).

Step by step solution

01

Identify the Form of the Quadratic Function

The given function is in the form of a standard quadratic equation: \[f(x) = ax^2 + bx + c\]. Here, \[a=1, b=-4, \text{and} c=-5\].
02

Find the Vertex

To find the vertex of the parabola, use the formula for the x-coordinate of the vertex: \[x = -\frac{b}{2a}\].Substitute \[a = 1\] and \[b = -4\]: \[x = -\frac{-4}{2 \times 1} = 2\].Now, find the y-coordinate by substituting \[x = 2\] back into the function: \[y = (2)^2 - 4(2) - 5 = 4 - 8 - 5 = -9\].Thus, the vertex is \((2, -9)\).
03

Determine the Axis of Symmetry

The axis of symmetry is a vertical line that passes through the vertex. It has the equation: \[x = 2\].
04

Calculate the Y-Intercept

The y-intercept is the point where the graph crosses the y-axis. To find it, set \[x=0\] and solve for \[y\]: \[f(0) = 0^2 - 4(0) - 5 = -5\].Thus, the y-intercept is \( (0, -5) \).
05

Find the X-Intercepts

To find the x-intercepts, set \[f(x) = 0\] and solve for \[x\]: \[x^2 - 4x - 5 = 0\].Factor the quadratic equation: \[(x - 5)(x + 1) = 0\].So, the x-intercepts are \[x = 5\] and \[x = -1\]. These points are \((5, 0)\) and \((-1, 0)\).
06

Sketch the Graph

Using the vertex \((2, -9)\), the axis of symmetry \(x = 2\), the y-intercept \((0, -5)\), and the x-intercepts \((5, 0)\) and \((-1, 0)\), plot these points on the coordinate plane. Sketch a smooth curve that passes through these points, forming a parabola that opens upwards.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertex of a Parabola
The vertex of a parabola represents its highest or lowest point, depending on whether the parabola opens upwards or downwards. For the quadratic function given as \(f(x) = ax^2 + bx + c\), the x-coordinate of the vertex is found using the formula \(x = -\frac{b}{2a}\). This formula helps us pinpoint the exact horizontal location of the vertex. For our specific function \(f(x) = x^2 - 4x - 5\), we substitute \(a = 1\) and \(b = -4\) to get: \[ x = -\frac{-4}{2 \times 1} = 2 \]
To find the y-coordinate, we substitute \(x = 2\) back into the function and solve for \(y\): \[ y = (2)^2 - 4(2) - 5 = 4 - 8 - 5 = -9 \] This means the vertex is located at the point \( (2, -9) \).
The vertex is a critical point that helps in sketching the parabola correctly.
Axis of Symmetry
The axis of symmetry of a parabola is a vertical line that passes through its vertex, dividing the parabola into two mirror-image halves. This axis of symmetry has a simple equation derived directly from the x-coordinate of the vertex. Using the vertex we found earlier \( (2, -9)\), the axis of symmetry for our given quadratic function is: \[ x = 2 \]
This vertical line helps in ensuring the parabola is symmetric about this axis when graphing. Knowing the axis of symmetry can provide a clear guideline on how to plot additional points on the parabola.
X and Y Intercepts
Intercepts are points where the graph crosses the axes. Identifying these helps in accurately sketching the parabola.

**Finding the Y-Intercept:**
The y-intercept is found by setting \( x = 0 \) and solving for \( y \). For \(f(x) = x^2 - 4x - 5\), substituting \(x = 0\) gives us: \[ f(0) = 0^2 - 4(0) - 5 = -5 \] Therefore, the y-intercept is the point \( (0, -5) \).

**Finding the X-Intercepts:**
X-intercepts are found by setting the function equal to zero and solving for \( x \). This involves solving the equation: \[ x^2 - 4x - 5 = 0 \] Factoring the quadratic equation, we get: \[ (x - 5)(x + 1) = 0 \] Solving for \( x \), we find: \[ x = 5 \] and \[ x = -1 \] So, the x-intercepts are \( (5, 0) \) and \( (-1, 0) \).
Understanding intercepts is vital in sketching the precise shape of the parabola.
Factoring Quadratic Equations
Factoring is a method used to solve quadratic equations and find the x-intercepts of a parabola. The standard form of a quadratic equation is \(ax^2 + bx + c = 0\). To factor the quadratic, you need to express it as a product of two binomials.

For our given quadratic equation \(x^2 - 4x - 5 = 0\), we look for two numbers that multiply to \(-5\) and add up to \(-4\). These numbers are \(-5\) and \(+1\): \[ x^2 - 4x - 5 = (x - 5)(x + 1) \]
Once factored, we set each binomial to zero to find the solutions for \ x \):
\( x - 5 = 0 \text{ or } \( x + 1 = 0 \).
Solving these gives us: \[ x = 5 \] and \[ x = -1 \]
Thus, the x-intercepts are \(5 \) and \(-1 \). Factoring is a powerful tool that simplifies solving quadratic equations and understanding the points where the parabola crosses the x-axis.

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