Suppose that the universe satisfies the axiom of choice.
Let \(\mu\) be an infinite cardinal. By induction on the integers, we define a
sequence of cardinal \(\left(\lambda_{n}\right)_{n \in \omega}\) by setting
\- \(\lambda_{0}=\mu\);
\- for every \(n \in \omega, \lambda_{n+1}=2^{\lambda_{n}} .\)
Set \(\lambda=\sum_{n \in \omega} \lambda_{n} .\)
(a) Show that \(\lambda^{\mu}=\mu^{2}=\lambda^{\lambda}=2^{\lambda}\).
(b) Show that, for every cardinal \(\gamma\),
$$
\begin{aligned}
&\text { if } \aleph_{0} \leq \gamma \leq \lambda, \quad \text { then }
\lambda^{\gamma_{0}}=\lambda^{\gamma}=\lambda^{\lambda} \\
&\text { if } \gamma \geq \lambda, \quad \text { then }
\lambda^{\gamma}=2^{\gamma}
\end{aligned}
$$
(c) Show that there exist cardinals \(\alpha, \beta, \gamma\), and \(\delta\) such
that
$$
\alpha<\beta, \quad \gamma<\delta, \quad \text { and } \quad
\alpha^{\gamma}=\beta^{\delta} .
$$