/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 a) Show that the integral $$ ... [FREE SOLUTION] | 91Ó°ÊÓ

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a) Show that the integral $$ \int x^{m}\left(a+b x^{n}\right)^{p} \mathrm{~d} x $$ whose differential is a binomial, where \(m, n\), and \(p\) are rational numbers, can be reduced to the integral $$ \int(a+b t)^{p} t^{q} \mathrm{~d} t $$ where \(p\) and \(q\) are rational numbers. b) The integral (5.194) can be expressed in terms of elementary functions if one of the three numbers \(p, q\), and \(p+q\) is an integer. (Chebyshev showed that there were no other cases in which the integral (5.194) could be expressed in elementary functions.)

Short Answer

Expert verified
###Answer### The given integral can be reduced to the integral $$\int (a+bt)^p t^q ~dt,$$ where \(p\) and \(q\) are rational numbers. The simplified integral can be expressed in terms of elementary functions if one of the three numbers \(p\), \(q\), and \(p + q\) is an integer. This is due to Chebyshev's theorem, which states that there are no other cases in which the integral can be expressed in elementary functions.

Step by step solution

01

Substitution

Let \(\displaystyle u=a+bx^{n}\). Then, differentiate \(u\) with respect to \(x\) to find \(\displaystyle \frac{du}{dx}\): $$ \frac{du}{dx} = nbx^{n-1}. $$ Next, solve for \(dx\): $$ dx = \frac{du}{nbx^{n-1}}. $$
02

Rewrite the integral in terms of \(u\)

Replace the expression in the integral with our substitution and the new expression for \(dx\): $$ \begin{aligned} \int x^m(a+b x^n)^p ~d x &= \int x^m u^p \frac{du}{nbx^{n-1}} \\ &= \frac{1}{nb} \int x^{m-n+1} u^p ~du. \end{aligned} $$
03

Introduce variable \(t\)

Let \(t = x^{m-n+1}\). Then, by the chain rule, differentiate \(t\) with respect to \(x\) to find \(\frac{dt}{dx}\): $$ \frac{dt}{dx} = (m-n+1)x^{m-n}. $$ Now, solve for \(dx\): $$ dx = \frac{dt}{(m-n+1)x^{m-n}}. $$
04

Rewrite the integral in terms of \(t\)

Replace the expression \(\displaystyle x^{m-n+1}\) in the integral with our new variable \(t\) and the new expression for \(dx\): $$ \int x^{m-n +1} u^p ~du = \int t u^p \frac{dt}{(m-n+1)x^{m-n}}. $$ Since \(t = x^{m-n+1}\), we can rewrite \(x^{m-n}\) in terms of \(t\): $$ x^{m-n} = t^{1/(m-n+1)}. $$ Now, substitute this expression for \(\displaystyle x^{m-n}\) back into the integral: $$ \int t u^p \frac{dt}{(m-n+1)t^{1/(m-n+1)}} = \int u^p t^q ~dt, $$ with \(q = 1 -\frac{1}{m-n+1}\). We have shown that the integral $$ \int x^m(a+b x^n)^p~ dx $$ can be reduced to the integral $$ \int (a+bt)^p t^q ~dt, $$ where \(p\) and \(q\) are rational numbers.
05

Part b: Expressing the integral in terms of elementary functions

The integral can be expressed in terms of elementary functions if one of the three numbers \(p\), \(q\), and \(p + q\) is an integer. This is due to Chebyshev's theorem, which states that there are no other cases in which the integral can be expressed in elementary functions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elementary Functions
Elementary functions are the basic building blocks of calculus and have rich properties. They include functions like polynomials, exponentials, logarithms, trigonometric functions, and their inverses. When we discuss expressing integrals in terms of elementary functions, it means writing the result using these basic functions, without needing more complex ones.

Certain conditions, such as having integer coefficients, allow the integral to be expressed as an elementary function. For example:
  • The integral of a polynomial like \( \int x^2 \, dx \) results in another polynomial, \( \frac{x^3}{3} \).
  • For other elementary functions, like \( \sin x \) or \( e^x \), their integrals also remain within the realm of elementary functions.
Recognizing when an integral can be expressed this way is crucial for simplifying complex calculus problems.
Chebyshev's Theorem
Chebyshev's Theorem provides insightful limitations on expressing integrals in terms of elementary functions. Named after the Russian mathematician Pafnuty Chebyshev, the theorem specifies conditions under which integrals cannot be simplified to elementary forms.

In the problem, Chebyshev's Theorem explains that the integral can only be expressed as an elementary function if one of the numbers \(p, q,\) or \(p+q\) is an integer. This restriction is profound because it tells us that, except in these specific cases, we cannot simplify the integral further using elementary operations.

This limitation guides mathematicians to better understand which problems can be resolved completely with elementary functions and which require more advanced techniques or numerical methods.
Rational Exponents
Rational exponents appear in many areas of calculus, including integrals like the one discussed in the original exercise. When working with rational exponents, the base of the power is raised to a fraction, such as \( x^{3/2} \).

Handling rational exponents:
  • We can convert rational exponents to radical expressions. For example, \( x^{3/2} \) is the same as \( \sqrt{x^3} \).
  • Operations with rational exponents follow the same rules as other exponents, such as addition, subtraction, multiplication, owning to their commutative properties.
This makes them pivotal when simplifying expressions within integral calculations, allowing transitions between different forms, hoped to be more approachable as sought by substitution methods.
Integral Reduction
Integral Reduction is a technique used to simplify complicated integrals into simpler, more manageable forms, often making them easier to solve. One method of reduction involves substitution, which was demonstrated in the problem you examined.

Key steps in integral reduction by substitution:
  • Identify a portion of the integral that can be set as a new variable, which simplifies integration.
  • Change not only the integrand but also the differential \( dx \) to \( du \), accommodating the new substitution variable.
  • Return to the original variable once integration is complete or simplify and solve directly.
The process changes the structure of the integral, making it simpler, often converting it into a standard integrable form. This is useful especially when integrating functions involving polynomials and other non-standard forms.

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Most popular questions from this chapter

Show that if \(f \in C(] a, b[)\) and the inequality $$ f\left(\frac{x_{1}+x_{2}}{2}\right) \leq \frac{f\left(x_{1}\right)+f\left(x_{2}\right)}{2} $$ holds for any points \(\left.x_{1}, x_{2} \in\right] a, b[\), then the function \(f\) is convex on \(] a, b[\).

A differential equation of the form $$ \frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{f(x)}{g(y)} $$ is called an equation with variables separable, since it can be rewritten in the form $$ g(y) \mathrm{d} y=f(x) \mathrm{d} x $$ in which the variables \(x\) and \(y\) are separated. Once this is done, the equation can be solved as $$ \int g(y) \mathrm{d} y=\int f(x) \mathrm{d} x+c $$ by computing the corresponding integrals. Solve the following equations: a) \(2 x^{3} y y^{\prime}+y^{2}=2\) b) \(x y y^{\prime}=\sqrt{1+x^{2}}\) c) \(y^{\prime}=\cos (y+x)\), setting \(u(x)=y(x)+x\); d) \(x^{2} y^{\prime}-\cos 2 y=1\), and exhibit the solution satisfying the condition \(y(x) \rightarrow 0\) as \(x \rightarrow+\infty\). e) \(\frac{1}{x} y^{\prime}(x)=\operatorname{Si}(x)\); f) \(\frac{V^{\prime}(x)}{\cos x}=C(x)\).

$$ \text { Verify that } \cos x<\left(\frac{\sin x}{r}\right)^{3} \text { for } 0<|x|<\frac{\pi}{2} \text {. } $$

a) Investigate whether the Cauchy function $$ f(z)= \begin{cases}e^{-1 / z^{2}}, & z \neq 0 \\ 0, & z=0\end{cases} $$ is continuous at \(z=0\). b) Is the restriction \(\left.f\right|_{\mathbb{R}}\) of the function \(f\) in a) to the real line continuous? c) Does the Taylor series of the function \(f\) in a) exist at the point \(z_{0}=0 ?\) d) Are there functions analytic at a point \(z_{0} \in \mathbb{C}\) whose Taylor series converge only at the point \(z_{0} ?\) e) Invent a power series \(\sum_{n=0}^{\infty} c_{n}\left(z-z_{0}\right)^{n}\) that converges only at the one point \(z_{0} .\)

The barometric formula. a) Using the data from Sect. 5.6.2, obtain a formula for a correction term to take account of the dependence of pressure on the temperature of the air column, if the temperature is subject to variation (for example, seasonal) within the range \(\pm 40^{\circ} \mathrm{C}\). b) Use formula (5.144) to determine the dependence of pressure on elevation at temperatures of \(-40^{\circ} \mathrm{C}, 0^{\circ} \mathrm{C}\), and \(40^{\circ} \mathrm{C}\), and compare these results with the results given by your approximate formula from part a). c) The change in temperature of the atmosphere at an altitude of \(10-11 \mathrm{~km}\) is well described by the following empirical formula: \(T(h)=T_{0}-\alpha h\), where \(T_{0}\) is the temperature at sea level (at \(h=0 \mathrm{~m}\) ), the coefficient \(\alpha=6.5 \times 10^{-3} \mathrm{~K} / \mathrm{m}\), and \(h\) is the height in meters. Deduce under these conditions the formula for the dependence of the pressure on the height. \(\left(T_{0}\right.\) it is often given the value \(288 \mathrm{~K}\), corresponding to \(15^{\circ} \mathrm{C} .\) d) Find the pressure in a mine shaft at depths of \(1 \mathrm{~km}, 3 \mathrm{~km}\) and \(9 \mathrm{~km}\) using formula ( \(5.144)\) and the formula that you obtained in c). e) Independently of altitude, air consists of approximately \(1 / 5\) oxygen. The partial pressure of oxygen is also approximately \(1 / 5\) of the air pressure. A certain species of fish can live under a partial pressure of oxygen not less than \(0.15\) atmospheres. Should one expect to find this species in a river at sea level? Could it be found in a river emptying into Lake Titicaca at an elevation of \(3.81 \mathrm{~km} ?\)

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