Chapter 2: Problem 39
If the graphs of \(3 x^{2}+4 y^{2}-6 x+8 y-5=0\) and \((x-2)^{2}\) \(=4(y+2)\) are drawn on the same coordinate system, at how many points do they intersect? (A) 0 (B) 1 (C) 2 (D) 3 (E) 4
Short Answer
Expert verified
The two graphs intersect at 4 points, therefore the answer is (E) 4.
Step by step solution
01
Rewrite Both Equations
Write the ellipse equation in the standard form by completing the square for both x and y: \( (x - 1)^{2} + 2(y + 1)^{2} = 4 \). For the parabola, rearrange the equation to give \( y = 0.25(x - 2)^{2} - 2\). This step helps to identify the shapes of the curves and their respective translations.
02
Set the Two Equations Equal to Each Other
Set the y-values from the rearranged equations equal to each other in order to find the intersection points on the x-axis. The equation becomes: \( 2(y + 1)^{2} = 0.25(x - 2)^{2} - 2\)
03
Solve For x
Expand and solve this equation for x by using quadratic formula, or graphically by drawing the curves using a suitable software. The roots derived represent the x-coordinates of the points of intersection.
04
Back-substitute to Get y
Substitute the x-coordinates obtained into either of the original equations to solve for the corresponding y-coordinates, which complete the intersection points.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
A quadratic equation is an equation of the second degree, usually in the form of \(ax^2 + bx + c = 0\). Its graph is a parabola, a smooth curve that can open up, down, left, or right. In this exercise, the focus is on finding the intersection of two curves: an ellipse and a parabola. To solve for intersections, once both curves are expressed in the standard form, a key step is to equal the equations. This involves setting the y-values—of the ellipse and the parabola—equal to each other, if possible. The result will be a quadratic equation in terms of x, or even a simpler equation if arranged correctly. This equation can be solved using various methods such as factoring, using the quadratic formula, or sometimes recognizing special equations or patterns.
- Factoring is looking for two numbers that multiply to give you the constant term (\(c\)) and add to give you the middle term (\(b\)).
- Quadratic Formula is applied as \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), which calculates x's values directly.
- Graphing is another approach, providing a visual representation of roots or intersections.
Coordinate Geometry
Coordinate geometry is the study of geometric figures through a coordinate system, usually the Cartesian coordinate system. This involves plotting points, lines, and shapes in a plane using ordered pairs (x, y).In the context of our problem, we deal with an ellipse and a parabola. These shapes are plotted on the Cartesian plane, and their points of intersection are found by examining where the two equations meet, or have the same (x, y) coordinates.
- An ellipse has a standard form of \(\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\), centered at (h, k). Here, symmetry makes it easier to predict possible intersection points visually or algebraically.
- A parabola can open in any direction, with a standard form of \((x - h)^2 = 4p(y - k)\). The vertex of the parabola provides a focal point for examining intersections.
Completing the Square
Completing the square is a method to rearrange a quadratic equation into a form that makes it easier to solve. It involves adjusting the equation so that the expression becomes a perfect square trinomial.This is particularly useful for standardizing the equations of an ellipse and a parabola so that it becomes easier to find their intersection. Consider the equation of an ellipse from our problem: \(3x^2 + 4y^2 - 6x + 8y - 5 = 0\).
- First, group x and y terms, e.g., \(3(x^2 - 2x) + 4(y^2 + 2y) = 5\).
- Next, factor out the coefficients of x and y, to obtain terms that can be manipulated into square form.
- Finally, you add and subtract the appropriate constants to make each quadratic an expression of a squared binomial: \(3((x-1)^2 -1) + 4((y+1)^2 -1) = 5\).
- Adjust the constants accordingly to correct the original equation so it remains equivalent.