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A fair six-sided die is rolled twice. What is the probability of getting: a. a 6 on both rolls? b. a 5 on the first roll and an even number on the second roll?

Short Answer

Expert verified
a. \( \frac{1}{36} \); b. \( \frac{1}{12} \).

Step by step solution

01

Understanding the Problem

We are asked to calculate probabilities for two different events involving two rolls of a fair six-sided die. A fair six-sided die has faces numbered from 1 to 6, meaning each face has an equal probability of landing face-up.
02

Probability of Rolling a 6 on One Roll

The probability of rolling a 6 on a single roll of a fair die is 1 out of 6 possible outcomes. This can be represented mathematically as: \( P(6) = \frac{1}{6} \).
03

Probability of Rolling a 6 on Both Rolls

To find the probability of rolling a 6 on both rolls, we multiply the probability of rolling a 6 on the first roll by the probability of rolling a 6 on the second roll. Since the rolls are independent, we have: \( P(6 \text{ on both rolls}) = P(6) \times P(6) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \).
04

Probability of Rolling a 5 on the First Roll

The probability of rolling a 5 on a single roll is also \( \frac{1}{6} \), just like rolling any other specific number on a fair die.
05

Probability of Rolling an Even Number on the Second Roll

There are three even numbers on a six-sided die: 2, 4, and 6. The probability of rolling an even number is \( \frac{3}{6} = \frac{1}{2} \).
06

Probability of a 5 on First Roll and Even Number on Second Roll

To find the combined probability of both events happening, we multiply the probabilities of each independent event. Thus, \( P(5 \text{ first and even second}) = P(5 \text{ on first roll}) \times P(\text{even on second roll}) = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
When we talk about independent events in probability, we're looking at situations where the outcome of one event does not affect the outcome of another. This is essential in many probability problems, including those involving dice.

For example, when you roll a die, each roll is an independent event. What you roll first has no impact on what you will roll second. So, if we want to find the probability of rolling a 6 on two separate dice rolls, we consider each roll individually.

The formula to determine the probability of two independent events occurring together is simply the product of their individual probabilities. Hence, if both rolls are independent, and each roll results in a 6 with a probability of \( \frac{1}{6} \), then the combined probability of rolling 6 on both rolls is \( \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \). This multiplication rule is widely applicable to any independent events in probability calculations.
Fair Die
A fair die is crucial in probability exercises as it ensures a balanced outcome across its faces.

When a die is described as 'fair,' it means there is no bias in the rolling process. Each number from 1 to 6 has an equal chance of appearing. This fairness is what guarantees that the probabilities for each face are equal, precisely \( \frac{1}{6} \).

In our exercises, using a fair die means each face has the same likelihood every time we roll. If the die were biased, some numbers would have higher probabilities, complicating the probability calculations. Therefore, assuming a fair die simplifies our understanding and calculations, ensuring each scenario is analyzed on an even playing field.
Dice Rolling
Rolling dice is a classic way to explore probabilities. It鈥檚 a random process with discrete outcomes, perfect for learning how chance works.

Dice rolling problems typically involve calculating the probability of specific outcomes when the dice are thrown. To simplify, think of each roll as a small experiment where we're observing which face lands up.

Here are some key dice concepts:
  • Each die has six faces, each representing an equal probability of \( \frac{1}{6} \).
  • The result of one roll does not influence the next, making them independent events.
  • You can multiply probabilities of separate events to find the likelihood of a combination of outcomes.
These principles of dice rolling extend to more complex probability problems you're likely to encounter in more advanced mathematics.
Mathematics Education
Understanding probability is an essential part of mathematics education, offering students insights into randomness and chance. Probability teaches us how to predict and interpret outcomes in uncertain situations, a skill that is valuable in everyday life and many professions.

Learning about independent events and fair dice through practical exercises, like dice rolling, allows students to ground abstract concepts in real-world scenarios.
  • It promotes critical thinking and problem-solving skills.
  • It enhances students鈥 analytical abilities.鈥
  • Develops a foundation for advanced statistical methods.
By using everyday examples, such as rolling dice, students can channel their natural curiosity into exploring mathematical principles, making learning both engaging and effective. This practical approach helps demystify what can seem like an abstract topic, fostering a deeper appreciation and understanding of mathematics.

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Most popular questions from this chapter

According to a survey by Pew Research in \(2020,68 \%\) of U.S. adults say the federal government is doing too little to protect water quality. \((+/-1.6 \%)^{1}\) If you pick two adults at random, what is the probability that a. Both of them think the government is doing too little to protect water quality. b. Neither of them thinks the government is doing too little to protect water quality.

A bag contains 3 green marbles, 4 red marbles, and 5 blue marbles (and no others). If you randomly pull out a marble and put the marble back 3 times, what is the probability that you pull out a blue marble all 3 times? Write the probability in all three forms.

According to a national AP-NORC Survey, \(95 \%\) of U.S. adults think changes are needed in the criminal justice system \((+/-3.7 \%) .^{2}\) If you pick 3 people at random, what is the probability that a. All of them support criminal justice reform. b. None of them support criminal justice reform

Suppose that \(21 \%\) of people own dogs. If you pick two people at random, what is the probability that neither own a dog?

The following contingency table provides data from a sample of 6,224 individuals who were exposed to smallpox in Boston. $$ \begin{array}{|c|c|c|c|} \hline & \text { Inoculated } & \text { Not Inoculated } & \text { Total } \\ \hline \text { Lived } & 238 & 5136 & 5374 \\ \hline \text { Died } & 6 & 844 & 850 \\ \hline \text { Total } & 244 & 5980 & 6224 \\ \hline \end{array} $$ a. What is the probability that a person was inoculated? b. What is the probability that a person lived? c. What is the probability that a person died or was inoculated? d. What is the probability that a person died given they were inoculated? e. What is the probability that a person died given they were not inoculated? f. Does it appear that survival depended on if a person were inoculated? Or are they independent? Use probability to support your claim.

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