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A ball is drawn randomly from a jar containing 6 red marbles, 2 white marbles, and 5 yellow marbles. Find the probability of: a. Drawing a white marble. b. Drawing a red marble. c. Drawing a green marble. d. Drawing two yellow marbles if you draw with replacement. e. Drawing first a red marble then a white marble if marbles are drawn without replacement.

Short Answer

Expert verified
a. \(\frac{2}{13}\), b. \(\frac{6}{13}\), c. 0, d. \(\frac{25}{169}\), e. \(\frac{1}{13}\).

Step by step solution

01

Calculate Total Number of Marbles

First, determine the total number of marbles in the jar. Add the number of red, white, and yellow marbles together: \[ 6 + 2 + 5 = 13 \] Hence, the total number of marbles is 13.
02

Probability of Drawing a White Marble

To find the probability of drawing a white marble, divide the number of white marbles by the total number of marbles: \[ P( ext{white}) = \frac{2}{13} \]
03

Probability of Drawing a Red Marble

For the probability of drawing a red marble, use a similar calculation: divide the number of red marbles by the total number of marbles: \[ P( ext{red}) = \frac{6}{13} \]
04

Probability of Drawing a Green Marble

Since there are no green marbles in the jar, the probability of drawing a green marble is zero: \[ P( ext{green}) = 0 \]
05

Probability of Drawing Two Yellow Marbles with Replacement

Since the draws are with replacement, the probability of drawing a yellow marble remains the same for each draw. Thus, the probability is given by: \[ P( ext{two yellow marbles}) = \left(\frac{5}{13}\right) \times \left(\frac{5}{13}\right) = \frac{25}{169} \]
06

Probability of Drawing First a Red Marble, Then a White Marble Without Replacement

For draws without replacement, the probability changes after the first draw. Calculate the probabilities sequentially: First, drawing a red: \[ \frac{6}{13} \] Then, drawing a white: \[ \frac{2}{12} = \frac{1}{6} \] Thus, the total probability is: \[ P( ext{red then white}) = \frac{6}{13} \times \frac{1}{6} = \frac{1}{13} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Drawing Marbles
When we talk about drawing marbles from a jar, we're diving into the world of probability and random selection. Imagine a jar filled with colorful marbles of different hues—each representing a potential outcome in a probability scenario. When you draw a marble, it's an event where you can't predict the color with certainty, but you can calculate the likelihood of each possible outcome. In this exercise, the jar contains red, white, and yellow marbles, so these are the only outcomes possible unless we add other colors. Here are the steps to consider when drawing marbles:
  • Identify all possible outcomes (colors of marbles in the jar).
  • Know the quantity of each colored marble.
  • Consider how drawing one marble can affect future draws, which leads us to concepts like replacement.
Grasping these basics is key to determining the probabilities of different events.
With Replacement
"With replacement" is an important term in probability that affects how we calculate chances. When you're drawing marbles with replacement, you put the marble back into the jar after selecting it. This action ensures the total number of marbles remains constant throughout the drawing process. Why is this significant? Because it keeps the probability of drawing any particular marble the same every time you draw it. Let's break it down:
  • Say you draw a yellow marble, the chance of drawing one yellow marble is determined by the ratio of yellow marbles to the total number of marbles (e.g. \( \frac{5}{13} \)).
  • You return that marble to the jar, and the probability of drawing another yellow marble in the next selection remains \( \frac{5}{13} \).
This consistency is crucial for situations where outcomes should be independent, allowing identical probability calculations for every draw.
Without Replacement
The term "without replacement" refers to a scenario where you do not put the marble back into the jar after drawing it out. This situation drastically changes the probabilities because the number of marbles in the jar decreases, hence altering the odds with each draw. For instance, if you first draw a red marble out of the jar containing 6 red, 2 white, and 5 yellow marbles:
  • The probability of drawing a red marble first would be \( \frac{6}{13} \).
  • After removing a red marble, there are now only 12 marbles in total.
  • If you then wish to draw a white marble, the probability is \( \frac{2}{12} = \frac{1}{6} \).
As you can see, the probabilities are dependent on prior events, making each draw connected and influencing subsequent outcomes.
Probability Calculation
Probability calculation is about finding how likely an event is to happen. It's often shown as a fraction or a decimal. The basic formula for finding probability is:\[P(\text{event}) = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}\]In our exercise, to determine the probability of drawing any specific marble, we must:
  • Count how many marbles of that color are in the jar (the "favorable outcomes").
  • Know the total number of marbles in the jar.
If we want a probability of a chain of events, such as drawing one marble and then another, you multiply the probabilities of each individual event. For example, drawing two yellow marbles with replacement involves multiplying each draw's probability:\[P(\text{two yellow marbles}) = \frac{5}{13} \times \frac{5}{13} = \frac{25}{169}\]Grasping this helps you understand how likely different events are, and is a foundational skill in mathematics.

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Most popular questions from this chapter

A bag contains 2 black marbles, 4 orange marbles, and 20 yellow marbles. Someone offers to play this game: You randomly select one marble from the bag. If it is black, you win \(\$ 3 .\) If it is orange, you win \(\$ 2 .\) If it is yellow, you lose \(\$ 1 .\) a. Make a probability model for this game. b. What is your expected value if you play this game? c. Should you play this game?

At the local fair there is a game in which folks are betting where a chicken will poop on a 4 by 4 -foot grid. (There are 16,1 by 1 squares to choose from) You can buy a 1 by 1 -foot square for \(\$ 15\) and if the chicken poops on your square you win \(\$ 125\). Find the expected value for this game.

The contingency table below shows the number of credit cards owned by a group of individuals below the age of 35 and above the age of 35 . $$ \begin{array}{|c|c|c|c|c|} \hline & \text { Zero } & \text { One } & \text { Two or more } & \text { Total } \\ \hline \begin{array}{c} \text { Between the ages } \\ \text { of } 18-35 \end{array} & 9 & 5 & 19 & 33 \\ \hline \text { Over age 35 } & 18 & 10 & 20 & 48 \\ \hline \text { Total } & 27 & 15 & 39 & 81 \\ \hline \end{array} $$ If one person was chosen at random: a. What is the probability they had no credit cards? b. What is the probability they had one credit card? c. What is the probability they had no credit cards and is over \(35 ?\) d. What is the probability they are between the ages of 18 and \(35,\) or have zero credit cards? e. What is the probability they had no credit cards given that they are between the ages of 18 and \(35 ?\) f. What is the probability they have no credit cards given that they are over age \(35 ?\) g. Does it appear that having no credit cards depends on age? Or are they independent? Use probability to support your claim.

According to a survey by Pew Research in \(2020,68 \%\) of U.S. adults say the federal government is doing too little to protect water quality. \((+/-1.6 \%)^{1}\) If you pick two adults at random, what is the probability that a. Both of them think the government is doing too little to protect water quality. b. Neither of them thinks the government is doing too little to protect water quality.

A company wants to offer a 2-year extended warranty in case their product fails after the original warranty period but within 2 years of the purchase. They estimate that \(1.5 \%\) of their products will fail during that time, and it will cost them \(\$ 450\) to replace a failed product. If they charge \(\$ 55\) for the extended warranty, what is the company's expected profit or loss on each warranty sold?

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