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If the diameters of trees in a forest follow a nearly Normal distribution has a mean of 35 inches and a standard deviation of 15 inches. What is the median width?

Short Answer

Expert verified
The median diameter is 35 inches.

Step by step solution

01

Understanding the Normal Distribution

When a set of data, like tree diameters in this forest, follows a Normal distribution, it means that the data is symmetrically distributed around the mean. The shape of the distribution is a bell curve. In a symmetric distribution like this, the mean, median, and mode are all located at the center of the distribution.
02

Identifying Key Statistical Measures

For a Normal distribution, the mean, median, and mode are equal due to the symmetry of the distribution curve. Given that the mean diameter is 35 inches, it initially suggests that the median will also be around this value.
03

Conclusion Based on Properties of Normal Distribution

Since the median of a Normal distribution is equal to the mean due to its symmetry, and we know that the mean diameter is 35 inches, we can directly conclude the median diameter is the same.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Median
The **mean** is a measure of central tendency that represents the average of all data points. It is calculated by summing all the values and then dividing by the number of values. In many data sets, especially those following a Normal distribution, the mean is a useful indicator of the data's center.
On the other hand, the **median** is the middle value when the data set is ordered from least to greatest. For a Normal distribution, which is symmetric, the median is particularly interesting because it coincides with the mean.
This alignment of the mean and median occurs because the data is evenly spread around the central peak, providing a balanced representation of the dataset's central location.
Standard Deviation
The **standard deviation** quantifies the amount of variation or dispersion in a set of data values. In simpler terms, it tells us how much the individual data points deviate from the mean on average.
When dealing with a Normal distribution, standard deviation is crucial for understanding the spread and range of the data. Here’s why standard deviation is important:
  • It helps determine the width of the bell curve in a Normal distribution. A larger standard deviation indicates a wider distribution.
  • Approximately 68% of the data falls within one standard deviation of the mean.
  • Roughly 95% of the data is within two standard deviations, providing insight into how common or rare certain data points may be.
By knowing the standard deviation, we can accurately predict the variability within the dataset, even before looking at the data graphically.
Symmetric Distribution
A **symmetric distribution** means that the left and right sides of the distribution mirror each other perfectly. In a Normal distribution, this symmetric nature is apparent in the bell curve's shape, where the peak or highest point signifies the mean, median, and mode.
This symmetry is not just about aesthetics; it has practical implications:
  • The symmetric property makes it easier to make probability predictions using the data.
  • Calculations concerning probabilities, like the percentage of values lying within a certain range, rely on symmetry.
  • The balance between values on either side of the mean ensures that measures of central tendency (like the mean and median) overlap.
Understanding symmetry in a Normal distribution helps in grasping why statistical measures align as they do and aids in predicting outcomes based on these even distributions.

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Most popular questions from this chapter

Use the Empirical Rule to answer these questions. About what percentage of the values from a Normal distribution fall between the first and second standard deviations from the mean (both sides)?

An experiment compared the ability of three groups of participants to remember briefly-presented chess positions. The data are shown below. The numbers represent the average number of pieces correctly remembered from three chess positions. a. Find the standard deviation of each group. b. Calculate the 5 -number summary for each group. c. Calculate the range and IQR for each group. d. Create side-by-side boxplots and compare and contrast the two groups. $$ \begin{array}{|c|c|c|} \hline \text { Non-players } & \text { Beginners } & \text { Tournament Players } \\ \hline 22.1 & 32.5 & 40.1 \\ \hline 22.3 & 37.1 & 45.6 \\ \hline 26.2 & 39.1 & 51.2 \\ \hline 29.6 & 40.5 & 56.4 \\ \hline 31.7 & 45.5 & 58.1 \\ \hline 33.5 & 51.3 & 71.1 \\ \hline 38.9 & 52.6 & 74.9 \\ \hline 39.7 & 55.7 & 75.9 \\ \hline 39.7 & 55.7 & 75.9 \\ \hline 43.2 & 55.9 & 80.3 \\ \hline 43.2 & 57.7 & 85.3 \\ \hline \end{array} $$

True or False: The bars of a bar graph should always touch.

This data is a sample of the average number of minutes per week that a driver is delayed by road congestion in 13 cities: \(66,55,53,50,36,45,34,43,52,40,76,45,63\) a. Find the mean and the standard deviation, including units. b. What is the z-score for the city with an average delay time of 42 hours per week? c. Is an average delay time of 42 hours per week unusual? Explain using the calculated z-score.

Use the Empirical Rule to answer these questions. About what percentage of the values from a Normal distribution fall outside of three standard deviations (left and right) of the mean?

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