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Use technology to answer these questions. Suppose a Normal distribution has a mean of 26.1 grams and a standard deviation of 6.5 grams. a. Draw and label the Normal distribution graph. b. What percentage of the data values fall above 32.6 grams? c. What percentage of data is below 15 grams or greater than 36.7 grams? d. What percentage of the data is less than or equal to 20.8 grams?

Short Answer

Expert verified
a) Draw a bell curve centered at 26.1. b) 15.87% fall above 32.6 grams. c) 9.52% is below 15 or above 36.7 grams. d) 20.71% is less than or equal to 20.8 grams.

Step by step solution

01

Understand the Normal Distribution Parameters

The Normal distribution has a mean \( \mu = 26.1 \) grams and a standard deviation \( \sigma = 6.5 \) grams. This information helps us understand the spread and center of our data for any calculations or plots we need to make.
02

Drawing and Labeling the Normal Distribution Graph

A Normal distribution graph is symmetric around its mean. Draw a bell-shaped curve centered at 26.1 on the x-axis. Mark the mean at \( \mu = 26.1 \), and indicate points at \( \mu + \sigma = 32.6 \), \( \mu + 2\sigma = 39.1 \), and similarly for values below the mean. Label the points \( \mu - \sigma = 19.6 \), \( \mu - 2\sigma = 13.1 \), etc.
03

Calculate Percentage Above 32.6 Grams

To find the percentage of data above 32.6 grams, convert 32.6 grams to a z-score using the formula \( z = \frac{x - \mu}{\sigma} \). Substituting the values: \( z = \frac{32.6 - 26.1}{6.5} \approx 1 \). Using z-tables or technology, find the probability of a z-score greater than 1, which corresponds to 0.1587 or 15.87%.
04

Calculate Percentage Below 15 Grams or Above 36.7 Grams

Calculate z-scores for 15 and 36.7 grams: \( z_{15} = \frac{15 - 26.1}{6.5} = -1.71 \) and \( z_{36.7} = \frac{36.7 - 26.1}{6.5} = 1.63 \). Find probabilities for \( P(Z < -1.71) \approx 0.0436 \) and \( P(Z > 1.63) \approx 0.0516 \). Add these probabilities to get the combined probability: \( 0.0436 + 0.0516 = 0.0952 \) or 9.52%.
05

Calculate Percentage Less Than or Equal to 20.8 Grams

Find the z-score for 20.8 grams: \( z = \frac{20.8 - 26.1}{6.5} \approx -0.815 \). Using the z-table or technology, determine the cumulative probability for this z-score, which approximates to 0.2071 or 20.71%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Standard Deviation
Understanding the mean and standard deviation is essential when working with a Normal distribution. The mean, represented by the Greek letter \( \mu \), is the average of all the data points. It's the central point of the distribution, around which all the data is symmetrically spread.

The standard deviation, denoted by \( \sigma \), measures how much the data varies from the mean. A smaller standard deviation indicates that the data points are close to the mean, leading to a narrow and taller bell curve. Conversely, a larger standard deviation shows more spread out data points, which results in a wider and flatter bell curve. In this exercise, we used a mean of 26.1 grams and a standard deviation of 6.5 grams.

These two parameters completely describe a Normal distribution, helping us predict where most data points lie. For instance, about 68% of data points in a Normal distribution are within one standard deviation of the mean. Given our values, this translates to roughly between 19.6 and 32.6 grams for our example dataset.
Z-score Calculation
A Z-score tells us how many standard deviations a data point is away from the mean. It's a very useful tool for comparing data points from different Normal distributions, and for finding probabilities.

To calculate a Z-score, use the formula:
  • \( z = \frac{x - \mu}{\sigma} \)
Here, \( x \) is the data point, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. A positive Z-score indicates the data point is above the mean, while a negative Z-score shows it's below the mean.

For example, when calculating the Z-score for 32.6 grams in our exercise, the result was approximately 1. This tells us that 32.6 grams is one standard deviation above the mean. By using this Z-score, we can easily determine probabilities using Z-tables or technology, allowing us to quantify how likely it is to find data points above or below a certain threshold.
Probability and Percentages
When dealing with Normal distributions, calculating probabilities helps us understand the likelihood of certain outcomes. This involves determining the percentage of the total data that falls above or below certain values.

In our exercise, we calculated the probability of data values falling above 32.6 grams and below 15 grams or above 36.7 grams. By converting these data points into Z-scores, we were able to use Z-tables or technology to find the cumulative probabilities.
  • For values above 32.6 grams, the probability was found to be approximately 15.87%.
  • For values below 15 grams and above 36.7 grams combined, the probability was about 9.52%.
These probabilities are valuable, especially in fields like quality control and risk management, where predicting extremes is crucial. Understanding the percentages helps in making informed decisions based on data behavior in a Normal distribution.

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