/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Will the lone divider method alw... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Will the lone divider method always result in an envy-free division? If not, will it ever result in an envy-free division?

Short Answer

Expert verified
No, the lone divider method does not always result in envy-free division, but it can result in envy-free outcomes under certain conditions.

Step by step solution

01

Understanding the Lone Divider Method

The lone divider method is a fair division algorithm where one person divides the item (usually a cake) into as many equally valuable pieces as there are people, and the other people choose pieces.
02

Concept of Envy-Free Division

An envy-free division is achieved when each participant believes they have received at least as much value as every other participant, meaning no one envies another person's share.
03

Analyzing the Lone Divider Method for Envy-Free Properties

The lone divider method does not guarantee envy-free results because the divider might create parts they value equally, but others might see differences in these parts. If others choose the divider's most valued parts, the divider might feel envious.
04

Explaining When Envy-Free Occurs

Despite not being guaranteed, an envy-free division can occur in some cases when the divider's value perception aligns closely with others' perceptions, or when the other participants' choices prevent the divider from feeling envious.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Envy-Free Division
In the context of fair division, an envy-free division ensures that each participant feels satisfied with their share compared to what others have received. Essentially, no one should prefer someone else's portion over their own.
This is crucial in dividing goods, like a cake, as it ensures that all parties involved feel content with their distribution. An envy-free division means that each participant firmly believes they have received the best available portion according to their value perception.
To achieve this, each person's subjective evaluation of the portions plays a significant role. For instance, if two people are dividing a cake, an envy-free division occurs when both believe they have received at least as much cake value as the other. This leads to harmony and fairness, removing any potential feelings of jealousy or unfair treatment.
Fair Division Algorithm
A fair division algorithm is a systematic method used to divide goods or resources among several participants in a way deemed fair by each of them.
The lone divider method is a classic example of such an algorithm. It tackles the complex problem of how to divide a resource fairly among participants with distinct value perceptions.
### Lone Divider Method
1. The "divider" splits the resource (e.g., a cake) into equal parts, where the number of parts equals the number of participants.
2. Other participants then select their preferred piece, typically in a predetermined sequence. The divider receives the piece left.
The main aim of a fair division algorithm is to optimize each participant's satisfaction with their allocated share. However, since value perceptions differ, these algorithms must consider human subjectivity to achieve the closest approximation to fairness.
Cake Cutting
Cake cutting serves as a metaphor for the broader concept of dividing resources among individuals.
This symbolism is often used to illustrate the challenges and solutions in fair division problems. The goal in cake cutting is not only to divide the cake but to ensure each participant is happy with their piece.
The lone divider method, used in cake cutting, attempts to balance precision with fairness. By allowing one individual to divide the cake and others to choose from these divisions, it offers a structured approach that can sometimes result in an envy-free division.
Moreover, the complexity arises because the "cake" can be any divisible good, like land, time, or even responsibilities, where each participant's value perception can differ greatly.
Participant Value Perception
Participant value perception is a fundamental aspect of fair division problems. It deals with how each person subjectively evaluates the worth of the divided portions.
Each participant may place different values on portions based on their preferences, needs, and desires. For example, in cake cutting, one person might value frosting over size, while another prefers the opposite.
This variance in personal valuation is the key challenge in achieving an envy-free division. Even if one participant sees their portion as equally valuable, another might disagree.
Achieving satisfaction in a division, therefore, depends heavily on how well the division aligns with each participant’s unique value perception. Recognizing and accounting for these perspectives is critical to enhancing the fairness and success of any division method.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 6 -foot sub valued at \(\$ 30\) is divided among five players \(\left(\mathrm{P}_{1}, \mathrm{P}_{2}, \mathrm{P}_{3}, \mathrm{P}_{4}, \mathrm{P}_{5}\right)\) using the last-diminisher method. The players play in a fixed order, with \(\mathrm{P}_{1}\) first, \(\mathrm{P}_{2}\) second, and so on. In round \(1, \mathrm{P}_{1}\) makes the first cut and makes a claim on a piece. For each of the remaining players, the value of the current claimed piece at the time it is their turn is given in the following table: \begin{tabular}{|l|l|l|l|l|} \hline & \(\mathbf{P}_{2}\) & \(\mathbf{P}_{3}\) & \(\mathbf{P}_{4}\) & \(\mathbf{P}_{5}\) \\ \hline Value of the current claimed piece & \(\$ 6.00\) & \(\$ 8.00\) & \(\$ 7.00\) & \(\$ 6.50\) \\ \hline \end{tabular} a. Which player gets his or her share at the end of round \(1 ?\) b. What is the value of the share to the player receiving it? c. How would your answer change if the values were: \begin{tabular}{|l|l|l|l|l|} \hline & \(\mathbf{P}_{2}\) & \(\mathbf{P}_{3}\) & \(\mathbf{P}_{4}\) & \(\mathbf{P}_{5}\) \\ \hline Value of the current claimed piece & \(\$ 6.00\) & \(\$ 8.00\) & \(\$ 7.00\) & \(\$ 4.50\) \\ \hline \end{tabular}

A huge collection of low-value baseball cards appraised at \(\$ 100\) is being divided by 5 kids \(\left(\mathrm{P}_{1}, \mathrm{P}_{2}, \mathrm{P}_{3}, \mathrm{P}_{4}, \mathrm{P}_{5}\right)\) using the last-diminisher method. The players play in a fixed order, with \(\mathrm{P}_{1}\) first, \(\mathrm{P}_{2}\) second, and so on. In round \(1, \mathrm{P}_{1}\) makes the first selection and makes a claim on a pile of cards. For each of the remaining players, the value of the current pile of cards at the time it is their turn is given in the following table: \begin{tabular}{|l|l|l|l|l|} \hline & \(\mathbf{P}_{2}\) & \(\mathbf{P}_{3}\) & \(\mathbf{P}_{4}\) & \(\mathbf{P}_{5}\) \\ \hline Value of the current pile of cards & \(\$ 15.00\) & \(\$ 22.00\) & \(\$ 18.00\) & \(\$ 19.00\) \\ \hline \end{tabular} a. Which player gets his or her share at the end of round \(1 ?\) b. What is the value of the share to the player receiving it? c. How would your answer change if the values were: \begin{tabular}{|l|l|l|l|l|} \hline & \(\mathbf{P}_{2}\) & \(\mathbf{P}_{3}\) & \(\mathbf{P}_{4}\) & \(\mathbf{P}_{5}\) \\ \hline Value of the current pile of cards & \(\$ 15.00\) & \(\$ 22.00\) & \(\$ 18.00\) & \(\$ 21.00\) \\ \hline \end{tabular}

This question explores how bidding dishonestly can end up hurting the cheater. Four partners are dividing a million-dollar property using the lone-divider method. Using a map, Danny divides the property into four parcels \(\mathrm{s}_{1}, \mathrm{~s}_{2}, \mathrm{~s}_{3},\) and \(\mathrm{s}_{4} .\) The following table shows the value of the four parcels in the eyes of each partner (in thousands of dollars): \begin{tabular}{|c|c|c|c|c|} \hline & s1 & s2 & s3 & s 4 \\ \hline Danny & \(\$ 250\) & \(\$ 250\) & \(\$ 250\) & \(\$ 250\) \\ \hline Brianna & \(\$ 460\) & \(\$ 180\) & \(\$ 200\) & \(\$ 160\) \\ \hline Carlos & \(\$ 260\) & \(\$ 310\) & \(\$ 220\) & \(\$ 210\) \\ \hline Greedy & \(\$ 330\) & \(\$ 300\) & \(\$ 270\) & \(\$ 100\) \\ \hline \end{tabular} a. Assuming all players bid honestly, which piece will Greedy receive? b. Assume Brianna and Carlos bid honestly, but Greedy decides to bid only for s1, figuring that doing so will get him \(\mathrm{s} 1\). In this case there is a standoff between Brianna and Greedy. Since Danny and Carlos are not part of the standoff, they can receive their fair shares. Suppose Danny gets \(s 3\) and Carlos gets \(s 2,\) and the remaining pieces are put back together and Brianna and Greedy will split them using the basic divider-chooser method. If Greedy gets selected to be the divider, what will be the value of the piece he receives? c. Extension: Create a Sealed Bids scenario that shows that sometimes a player can successfully cheat and increase the value they receive by increasing their bid on an item, but if they increase it too much, they could end up receiving less than their fair share.

As part of an inheritance, four children, Abby, Ben, Carla, and Dan, are dividing four vehicles using Sealed Bids. Their bids (in thousands of dollars) for each item is shown below. Find the final allocation. $$ \begin{array}{|c|r|r|r|r|} \hline & \multicolumn{1}{|c|} {\text { Abby }} & \text { Ben } & \multicolumn{1}{|c|} {\text { Carla }} & \multicolumn{1}{|c|} {\text { Dan }} \\\ \hline \text { Motorcycle } & 6 & 7 & 11 & 8 \\ \hline \text { Car } & 8 & 13 & 10 & 11 \\ \hline \text { Tractor } & 3 & 1 & 5 & 4 \\ \hline \text { Boat } & 7 & 6 & 3 & 8 \\ \hline \end{array} $$

Jenna, Tatiana, and Nina are dividing a large bag of candy. They randomly split the bag into three bowls. The values of the entire bag and each of the three bowls in the eyes of each of the players are shown below. For each player, identify which bowls they value as a fair share. $$ \begin{array}{|c|l|l|l|l|} \hline & \text { Whole Bag } & \text { Bowl 1 } & \text { Bowl 2 } & \text { Bowl 3 } \\ \hline \text { Jenna } & \$ 8 & \$ 4.50 & \$ 0.75 & \$ 2.75 \\ \hline \text { Tatiana } & \$ 4 & \$ 1.00 & \$ 1.00 & \$ 2.00 \\ \hline \text { Nina } & \$ 6 & \$ 1.75 & \$ 2.50 & \$ 1.75 \\ \hline \end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.