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Es seien \(\mu: \mathfrak{f} \rightarrow \overline{\mathbb{R}}\) ein ±Ê°ùä³¾²¹ÃŸ auf dem Halbring \(\mathfrak{H}\) über \(X\) und \(\eta\) das äußere \(\mathrm{MaB} \mathrm{zu}\) \(\mu\). Zeigen Sie: a) Eine Teilmenge \(A \subset X\) ist genau dann \(\eta\)-meßbar, wenn für alle \(M \in \mathfrak{H}(!)\) mit \(\mu(M)<\infty\) gilt: \(\mu(M)=\eta(M \cap A)+\eta\left(M \cap A^{c}\right)\). (Bemerkung: Im Falle des Lebesgueschen ±Ê°ùä³¾²¹ÃŸes auf \(\mathbb{R}\) ist dieses die ursprüngliche ²Ñ±ðß²ú²¹°ù°ì±ð¾±³Ù²õ»å±ð´Ú¾±²Ô¾±³Ù¾±´Ç²Ô von LEBESGUE [1], S. 209-210.) b) Eine Menge \(M \subset X\) ist genau dann \(\eta\)-meßbar, wenn \(M \cap A \eta\)-meßbar ist für alle \(A \in \mathfrak{H}\) \(\operatorname{mit} \mu(A)<\infty\)

Short Answer

Expert verified
Proofs for measure theoretic statements such as these heavily rely on the definitions of measurability and the properties of the premeasure and outer measure. From these properties, direct proofs or proofs by contradiction can be carried out.

Step by step solution

01

Prove Statement a

This is a statement where a proof by contradiction can be very useful. If it's assumed that there exists a set M in the half-ring, with measure less than infinity, such that \( \mu(M) \ne \eta(M \cap A) + \eta\left(M \cap A^{c}\right) \) then it will lead to a contradiction with the definition of the outer measure, because the outer measure is always the infimum of the measures of the coverings of a set. Comparison of the measure of M to the measures of its intersections with A and its complement will lead to the contradiction, proving the statement.
02

Prove Statement b

This statement can be proven directly by using the definition of measurability in relation with the outer measure. If for every subset A in the half-ring (with measure less than infinity), the intersection of M and A is measurable, then that signifies M must also be measurable. The requirement for the measure of A to be less than infinity is necessary, as otherwise the measure of the intersection could be undefined.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

±Ê°ùä³¾²¹ÃŸ
A ±Ê°ùä³¾²¹ÃŸ is a foundational concept in measure theory, vital to understanding how measures are extended from simpler structures to more complex ones. In essence, a ±Ê°ùä³¾²¹ÃŸ is a function that assigns a non-negative extended real number to subsets within a certain collection (like a Halbring) and satisfies two key properties. First, it must return zero when applied to the empty set. Second, it must be countably additive, meaning if you have a countable collection of disjoint sets, the measure assigned to their union should equal the sum of the measures of each individual set. This concept forms the building blocks for defining a full measure on a space.

For example, in the context of the real numbers, the Lebesguesches ±Ê°ùä³¾²¹ÃŸ assigns lengths to intervals which is the starting point for constructing the Lebesgue measure, a fundamental tool in real analysis.
Halbring
The term Halbring, or semiring in English, refers to a collection of sets that provides a structure from which more complicated sets can be built and measured. A few basic rules define a Halbring: firstly, it must contain the empty set. Secondly, the intersection of any two sets in a Halbring should also be in the Halbring. Lastly, if you take two sets from the Halbring, the difference of these sets needs to be expressible as a finite union of disjoint sets in the Halbring. The concept of a Halbring is significant because it is a starting point from which we can define a ±Ê°ùä³¾²¹ÃŸ, thus laying the groundwork for more complex measures.

Visualizing a Halbring can be as simple as thinking about intervals on the number line, where the intersection and difference of intervals can still create new intervals or points on the line.
äußeres Maß
An äußeres Maß, or outer measure, is an extended concept in measure theory that allows us to measure any subset of a given space, regardless of whether they belong to a particular structure like a Halbring. The approach for constructing an äußeres Maß is to cover the set in question with a collection of measurable sets for which the measure is known, then to take the infimum (or the greatest lower bound) of the sums of the measures of these covering sets. An outer measure needs to satisfy three conditions: it must assign a measure of zero to the empty set, be countably sub-additive, and be monotone. This comprehensive approach is a pivotal step in defining measurable sets, which in turn refines the understanding of an actual measure on a space.

For instance, if we cover a shape on the plane with rectangles whose areas we can calculate, the outer measure gives us an 'outer' estimate of the shape's area by considering the total area of the rectangles.
²Ñ±ðß²ú²¹°ù°ì±ð¾±³Ù²õ»å±ð´Ú¾±²Ô¾±³Ù¾±´Ç²Ô
The ²Ñ±ðß²ú²¹°ù°ì±ð¾±³Ù²õ»å±ð´Ú¾±²Ô¾±³Ù¾±´Ç²Ô, or the definition of measurability, acts as a crucial bridge between a ±Ê°ùä³¾²¹ÃŸ on a Halbring and an outer measure. A set is considered measurable with respect to an outer measure if, for every set with finite outer measure, the measure of the whole set can be approximated as closely as desired by adding the measures of the intersection of the set with the measurable set and the complement of the measurable set. This condition ensures that we can extend our initial pre-measure, which applies only to simple sets like intervals, to more complex sets, ultimately leading to a complete measure theory.

For a real-world analogy, imagine you're wrapping an irregularly shaped present; the measurable condition ensures that you can use a finite number of predetermined-sized wrapping papers (simple sets) to cover the present (complex set) without leaving any parts unwrapped or significantly overlapping.
Lebesguesches ±Ê°ùä³¾²¹ÃŸ
The Lebesguesches ±Ê°ùä³¾²¹ÃŸ is specifically considered within the realm of real numbers and serves as a prototype for a ±Ê°ùä³¾²¹ÃŸ. It is defined on the Halbring of intervals in the real line, with the measure of an interval equal to its length. The Lebesguesches ±Ê°ùä³¾²¹ÃŸ is particularly significant because it was Henri Lebesgue's pioneering work on this concept that laid the foundations of modern measure theory. By introducing the idea that more complex sets' measures should agree with the 'pre-measure' of the intervals they are composed of, it allows for a harmonious transition to the full Lebesgue measure, which is capable of assessing the 'size' of a much broader class of sets in a way that the traditional Riemann integral could not.

Metaphorically, if we think of the Lebesgue measure as a sophisticated scale able to measure every type of object, the Lebesguesches ±Ê°ùä³¾²¹ÃŸ would be the initial calibration using known weights (intervals), which ensures that this scale gives accurate readings for any item (set) placed on it.

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Most popular questions from this chapter

Für jede rektifizierbare Kurve \(\gamma:[a, b] \rightarrow \mathbb{R}^{p}\) ist \(h_{\alpha}([\gamma])=0\) für alle \(\alpha>1\), und es gilt \(\lambda^{p}([\gamma])=0\), falls \(p \geq 2\). (Hinweise: Lemma \(9.7\) und Satz III.2.9.)

Es seien \(X\) ein metrischer (oder topologischer) Raum und \(\mu\) ein endlicher Inhalt auf dem Halbring \(\mathfrak{H}\) über \(X\). Dann heißt \(\mu\) von innen regulär, wenn zu jedem \(\varepsilon>0\) und jedem \(A \in \mathfrak{H}\) ein \(K \in \mathfrak{H}\) existiert, so daß gilt: \(\bar{K}\) ist kompakt, \(\bar{K} \subset A, \mu(A) \leq \mu(K)+\varepsilon .\) Zeigen Sie: Ist \(\mu\) von innen regulär, so ist \(\mu\) ein ±Ê°ùä³¾²¹ÃŸ. (Hinweis: Ist \(\mu\) von innen regulär, so auch die Fortsetzung \(\nu\) von \(\mu\) auf den von \(\mathfrak{H}\) erzeugten Ring. \(\nu\) genügt der Bedingung d) aus Satz 1.10.)

Es sei \(\mu\) ein Inhalt auf dem Ring \(\Re\) über \(X\). Zeigen Sie: a) Durch \(A \sim B: \Longleftrightarrow \mu(A \triangle B)=0 \quad(A, B \in \Re)\) wird eine Äquivalenzrelation auf \(\Re\) definiert. b) Die Äquivalenzklasse \(\mathfrak{N}:=\\{A \in \mathfrak{R}: A \sim \emptyset\\}\) der leeren Menge enthält genau die \(\mu\) Nullmengen, und \(\mathfrak{N}\) ist ein Ideal in \(\mathfrak{R}\) (d.h. \(\mathfrak{N}\) ist ein Unterring von \(\mathfrak{R}\), und für alle \(A \in\) \(\mathfrak{R}, B \in \mathfrak{N}\) gilt \(A \cap B \in \mathfrak{N})\). c) Für alle \(A, B \in \Re\) mit \(A \sim B\) gilt \(\mu(A)=\mu(B)=\mu(A \cap B)=\mu(A \cup B)\). \({ }^{3}\) Diese Arbeit von Herrn Young ist die erste unter denjenigen, die zum endgultigen Verständnis dessen, was das Stieltjessche Integral ist, geführt haben. Man ist [aber erst] Dank der Definition von Herrn Radon ... und der Arbeiten von Herrn de la Vallée Poussin über die Ausdehnung des Maßbegriffes ... wirklich zum Kern dieses Begriffes vorgedrungen. \(\mu\) gleichmäßig stetig bez. \(\delta\). Die Mengenoperationen \(\cap, \cup, \backslash, \triangle\) sind bez. \(\delta\) gleichmäßig stetige Abbildungen von \(\Re \times \Re\) in \(\Re\). e) \(\mu\) sei endlich, \(\hat{\Re}\) bezeichne die Menge der Äquivalenzklassen \(\hat{A}:=\\{B \in \Re: B \sim A\\} \quad(A \in\) \(\mathfrak{R})\), und für \(A, B \in \mathfrak{R}\) sei \(d(\hat{A}, \hat{B}):=\delta(A, B)\). Zeigen Sie: \((\hat{\Re}, d)\) ist ein metrischer Raum. f) Es sei \(\mu\) ein endliches ±Ê°ùä³¾²¹ÃŸ auf dem \(\sigma\)-Ring \(\mathfrak{S} .\) Dann ist der metrische Raum \((\hat{\mathrm{S}}, d)\) vollständig. (Hinweise: Es seien \(A_{n} \in \mathfrak{S}\) und \(\left(\hat{A}_{n}\right)_{n \geq 1}\) eine Cauchy-Folge in \((\hat{\mathfrak{S}}, d)\). Wählen Sie eine Teilfolge \(B_{k}=A_{n_{k}} \quad(k \geq 1)\), so daß \(d\left(\hat{B}_{k}, \hat{B}_{k+1}\right) \leq 2^{-k} \quad(k \geq 1)\). Folgern Sie aus \(B_{p} \triangle\) \(\bigcup_{k=p}^{q} B_{k} \subset \bigcup_{k=p}^{q-1} B_{k} \Delta B_{k+1}(q>p \geq 1)\), daß für alle \(q \geq p\) gilt \(\mu\left(B_{p} \Delta \bigcup_{k=p}^{q} B_{k}\right)<2^{-(p-1)}\) und folgern Sie aus der Stetigkeit des ±Ê°ùä³¾²¹ÃŸes von unten, daß für \(C_{p}:=\bigcup_{k=p}^{\infty} B_{k} \in \mathcal{G}\) gilt \(d\left(\hat{B}_{p}, \hat{C}_{p}\right) \leq 2^{-(p-1)} .\) Für \(B:=\varlimsup_{k \rightarrow \infty} B_{k}\) gilt \(C_{p} \downarrow B\). Schließen Sie nun aus der Stetigkeit des ±Ê°ùä³¾²¹ÃŸes von oben und aus \(d\left(\hat{B}_{p}, \hat{B}\right) \leq d\left(\hat{B}_{p}, \hat{C}_{p}\right)+d\left(\hat{C}_{p}, \hat{B}\right)\), daß \(\left(\hat{B}_{k}\right)_{k \geq 1}\) gegen \(\hat{B}\) konvergiert. Warum folgt hieraus die Konvergenz der Folge \(\left(\hat{A}_{n}\right)_{n \geq 1}\) gegen \(\hat{B}\) ?) d) Es seien zusätzlich \(\mu\) endlich und \(\delta: \Re \times \Re \rightarrow \mathbb{R}, \delta(A, B):=\mu(A \triangle B)\) für \(A, B \in \Re\). Zeigen Sie: \(\delta\) ist eine Halbmetrik auf \(\Re\) (d.h. es gilt für alle \(A, B, C \in \Re: \delta(A, A)=0, \delta(A, B)=\) \(\delta(B, A), \delta(A, C) \leq \delta(A, B)+\delta(B, C)) .\) Es ist \(|\mu(A)-\mu(B)| \leq \delta(A, B) \quad(A, B \in \Re)\) und daher

Es gibt eine magere Menge \(A \subset \mathbb{R}\) und eine Lebesguesche Nullmenge \(N \subset \mathbb{R}\) mit \(\mathbb{R}=A \cup N\). (Bemerkung: Nach einem berühmten Satz von BAIRE hat in jedem vollständigen metrischen Raum \(X\) jede magere Teilmenge \(A \subset X\) ein in \(X\) dichtes Komplement (s. z.B. HewitT und STROMBERG [1], (6.54)). Daher ist \(N\) dicht in \(\mathbb{R}\).)

Es seien \(X\) ein metrischer (oder topologischer) Raum, und \(\mu, \nu: \mathfrak{B}(X) \rightarrow \overline{\mathbb{R}}\) seien zwei Maße. Zeigen Sie: Stimmen \(\mu\) und \(\nu\) auf allen offenen (bzw. abgeschlossenen) Teilmengen überein und gibt es eine Folge \(\left(A_{n}\right)_{n \geq 1}\) offener (bzw. abgeschlossener) Teilmengen von \(X\) mit \(\mu\left(A_{n}\right)<\infty(n \in \mathrm{N}), X=\bigcup_{n=1}^{\infty} A_{n}\), so ist \(\mu=\nu .\) Ist \(X\) ein Hausdorff-Raum, so gilt diese Aussage sinngemäß auch für kompakte Mengen.

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