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Zeigen Sie: Die Eigenwerte einer \(n \times n\)-Matrix \(M\) sind genau die Elemente \(k \in K\), für die es einen von Null verschiedenen Spaltenvektor \(x\) gibt mit \(M x=k x\)

Short Answer

Expert verified
Eigenvalues of matrix \( M \) are values \( k \), making \( \det(M - kI) = 0 \), allowing a non-zero vector \( x \) such that \( Mx = kx \).

Step by step solution

01

Understand Eigenvalues and Eigenvectors

Eigenvalues are scalars associated with a linear system of equations. For an \( n \times n \) matrix \( M \), an eigenvalue \( k \) corresponds to a non-zero vector (eigenvector) \( x \) such that applying the matrix \( M \) to \( x \) results in the vector \( x \) being stretched by the factor \( k \), mathematically represented as \( Mx = kx \).
02

Setup the Eigenvalue Equation

To find the eigenvalues, rewrite the equation \( Mx = kx \) into the form \((M - kI)x = 0 \), where \( I \) is the identity matrix. This transformation implies that \( x \) is a non-zero vector in the null space of the matrix \( M - kI \).
03

Determine when Non-zero Solutions Exist

For a non-zero solution to exist for the equation \( (M - kI)x = 0 \), the determinant of the matrix \( M - kI \) must be zero. This condition \( \det(M - kI) = 0 \) is known as the characteristic equation, and its solutions are the eigenvalues of the matrix \( M \).
04

Solve the Characteristic Equation

Find the values of \( k \) for which \( \det(M - kI) = 0 \). These values are precisely the eigenvalues of \( M \). Each eigenvalue \( k \) corresponds to at least one non-zero vector \( x \) satisfying \( Mx = kx \).
05

Conclusion Using the Definition

Since by definition, an eigenvalue of an \( n \times n \) matrix is a \( k \) that has a non-zero eigenvector \( x \) such that \( Mx = kx \), and this is exactly what is determined by solving \( \det(M - kI) = 0 \), we confirm that the eigenvalues of \( M \) are exactly those \( k \) for which the equation has non-trivial solutions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eigenvectors
In the world of linear algebra, an eigenvector is a non-zero vector that, when a matrix is multiplied by it, the direction of the vector remains unchanged. This concept is defined formally for a matrix \( M \), where any vector \( x \) satisfying the equation \( Mx = kx \) is an eigenvector corresponding to the eigenvalue \( k \).
  • **Property**: The eigenvector does not change its direction when transformed by its matrix, only its magnitude might get scaled by a factor, which is the eigenvalue.
  • **Example**: Imagine a vector pointing north. After applying the matrix transformation, it points north again but maybe longer or shorter. It's still pointing north, hence an eigenvector.

Importantly, eigenvectors are never the zero vector. They always have a non-zero magnitude, which is crucial for defining them.
Finding them involves solving the equation \((M - kI)x = 0\), where \(I\) is the identity matrix.
Characteristic Equation
The characteristic equation is fundamental in finding the eigenvalues of a matrix. It is derived from the condition that for a non-trivial solution the determinant of \( M - kI \) must be zero, written as \( \det(M - kI) = 0 \).
  • **Purpose**: Solving this equation gives us the eigenvalues — the scalars \( k \) that make \( Mx = kx \) true for some eigenvector \( x \).
  • **Process**: Write \( Mx = kx \) as \((M - kI)x = 0\) indicating that \( x \) is now in the null space of \( M - kI \).

The roots of the characteristic equation correspond to the eigenvalues of the matrix. Once you find these roots (i.e., solutions \( k \)), you know all possible scaling factors for which an eigenvector exists.
This process is critical in applications like stability analysis in engineering and quantum mechanics.
Determinant of a Matrix
The determinant is a special number that can be calculated from a square matrix. It provides insight into the matrix properties, particularly in the context of linear equations and transformations. For a matrix \( M \), the determinant, denoted \( \det(M) \), is crucial for understanding eigenvalues.
  • **Role in Eigenvalues**: The determinant of \( M - kI \) is central to finding eigenvalues because \( \det(M - kI) = 0 \) is the condition for non-trivial solutions\((x eq 0)\).
  • **Geometric Interpretation**: The determinant can be seen as a scaling factor — it tells us how much the matrix multiplies the area or volume of regions in the space it's applied to.

If the determinant is zero, it means the matrix transformation squishes the space into a lower dimension, indicating that eigenvalues exist.
Linear Algebra
Linear Algebra is a field of mathematics concerning vector spaces and operators acting upon them. It's the underlying language for many areas like physics, computer science, and statistics. Key concepts include matrices, vectors, and operations like addition, multiplication, and finding matrices' determinants and eigenvalues.
  • **Vectors**: Fundamental objects often seen as points or arrows in space. Operations with vectors are central to linear algebra.
  • **Matrices**: Rectangular arrays of numbers that represent linear transformations. They are like functions that transform points in space.

An important application is solving systems of linear equations, where matrices represent coefficients of linear equations. Eigenvalues and eigenvectors provide insight into the properties of these systems.
In broader terms, linear algebra can address problems related to geometry, computation, and even abstract areas like quantum physics, showcasing its vast applicability.

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Most popular questions from this chapter

Sei \(M\) die folgendermaßen definierte \(4 \times 4\)-Matrix: $$ M=\left(\begin{array}{llll} a & b & c & d \\ d & a & b & c \\ c & d & a & b \\ b & c & d & a \end{array}\right) \quad(a, b, c, d \in \mathbf{R}), $$ die wir als Matrix aus \(\mathbf{C}^{4 \times 4}\) auffassen. Zeigen Sie, dass \(M\) die Eigenwerte \(a+b+c+d, a-b+c-d, a+b \mathrm{i}-c-d \mathrm{i}, a-b \mathrm{i}-c+d \mathrm{i}\) hat (wobei i die imaginäre Einheit ist). Geben Sie jeweils einen Eigenvektor an.

Zeigen Sie, dass jede reelle \(2 \times 2\)-Matrix \(M\) der Form \(M=\left(\begin{array}{cc}a & b \\ b & a\end{array}\right)\) diagonalisierbar ist. Gilt dies auch über beliebigen Körpern \(K\) ?

Geben Sie eine Matrix mit ganzzahligen Einträgen an, die als Matrix über \(\mathbf{R}\) diagonalisierbar ist, nicht aber als Matrix über \(\mathbf{Q}\).

Zeigen Sie: (a) Wenn die Matrix \(M\) den Eigenwert \(k\) hat, so hat \(M^{2}\) den Eigenwert \(k^{2}\). (b) Verallgemeinern Sie diesen Sachverhalt. (c) Machen Sie sich durch eine \(2 \times 2\)-Matrix klar, dass die Umkehrung von (a) nicht gilt.

Bestimmen Sie die Eigenwerte und je einen zugehörigen Eigenvektor der folgendermaßen definierten linearen Abbildung \(f\) eines 3-dimensionalen reellen Vektorraums mit Basis \(\left\\{v_{1}, v_{2}, v_{3}\right\\}:\) $$ \begin{aligned} &f\left(v_{1}\right):=5 / 2 v_{1}+2 v_{2}+1 / 2 v_{3} \\ &f\left(v_{2}\right):=5 v_{1}+4 v_{2}-2 v_{3} \\ &f\left(v_{3}\right):=-7 / 2 v_{1}-2 v_{2}-3 / 2 v_{3}. \end{aligned} $$

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